Calculate the pH of Sr(OH)2 0.25M.<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n Correct Answer: pH = 13.70<\/strong><\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n Strontium hydroxide, written chemically as Sr(OH)\u2082, is a strong base. This means it completely dissociates in water. When Sr(OH)\u2082 dissolves in water, it separates into its constituent ions:<\/p>\n\n\n\n Sr(OH)\u2082 \u2192 Sr\u00b2\u207a + 2OH\u207b<\/strong><\/p>\n\n\n\n From the equation, each mole of Sr(OH)\u2082 yields 2 moles of OH\u207b ions<\/strong>. Given that the concentration of the Sr(OH)\u2082 solution is 0.25 M<\/strong>, this means the concentration of OH\u207b ions is:<\/p>\n\n\n\n [OH\u207b] = 0.25 M \u00d7 2 = 0.50 M<\/strong><\/p>\n\n\n\n To find the pH, first calculate the pOH<\/strong> using the formula:<\/p>\n\n\n\n pOH = -log[OH\u207b]<\/strong><\/p>\n\n\n\n Substitute the concentration:<\/p>\n\n\n\n pOH = -log(0.50) \u2248 0.30<\/strong><\/p>\n\n\n\n Now, to find the pH, use the relationship between pH and pOH:<\/p>\n\n\n\n pH + pOH = 14<\/strong><\/p>\n\n\n\n So:<\/p>\n\n\n\n pH = 14 – pOH = 14 – 0.30 = 13.70<\/strong><\/p>\n\n\n\n This result shows the solution is highly basic, which aligns with expectations for a strong base like Sr(OH)\u2082 at this concentration. High pH values indicate low hydrogen ion concentration and high hydroxide ion concentration. Since Sr(OH)\u2082 contributes two hydroxide ions per formula unit, its effect on pH is greater than that of a base producing only one OH\u207b per molecule. Strong bases like this are fully dissociated, which simplifies pH calculation because the OH\u207b concentration directly comes from the stoichiometry of the dissociation reaction. In conclusion, for a 0.25 M Sr(OH)\u2082 solution, the pH is 13.70<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Calculate the pH of Sr(OH)2 0.25M. The correct answer and explanation is: Correct Answer: pH = 13.70 Explanation: Strontium hydroxide, written chemically as Sr(OH)\u2082, is a strong base. This means it completely dissociates in water. When Sr(OH)\u2082 dissolves in water, it separates into its constituent ions: Sr(OH)\u2082 \u2192 Sr\u00b2\u207a + 2OH\u207b From the equation, each […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-35101","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35101","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=35101"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35101\/revisions"}],"predecessor-version":[{"id":35103,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35101\/revisions\/35103"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=35101"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=35101"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=35101"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}