{"id":35025,"date":"2025-06-24T06:22:30","date_gmt":"2025-06-24T06:22:30","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=35025"},"modified":"2025-06-24T06:22:31","modified_gmt":"2025-06-24T06:22:31","slug":"which-electronic-configuration-for-p-orbitals-obeys-all-the-rules-pauli-exclusion-principle-hunds-rule-and-aufbau-principle","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-electronic-configuration-for-p-orbitals-obeys-all-the-rules-pauli-exclusion-principle-hunds-rule-and-aufbau-principle\/","title":{"rendered":"Which electronic configuration for p-orbitals obeys all the rules Pauli Exclusion Principle; Hund&#8217;s Rule and Aufbau Principle"},"content":{"rendered":"\n<p>Which electronic configuration for p-orbitals obeys all the rules Pauli Exclusion Principle; Hund&#8217;s Rule and Aufbau Principle)? (a) 0 1 1 (b) 4 _ &#8211; (c) L 1 1 (d) 1 4 1 Select one: Only d b. All of them Only Your answer is incorrect Only Only<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is: <strong>(a) 0 1 1<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine which p-orbital electron configuration obeys all three fundamental rules \u2014 the <strong>Aufbau Principle<\/strong>, <strong>Pauli Exclusion Principle<\/strong>, and <strong>Hund&#8217;s Rule<\/strong> \u2014 we need to evaluate each choice carefully.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Understanding the p-Orbitals<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A p-subshell has <strong>three orbitals<\/strong>: pxp_xpx\u200b, pyp_ypy\u200b, and pzp_zpz\u200b<\/li>\n\n\n\n<li>Each orbital can hold <strong>a maximum of two electrons<\/strong> with <strong>opposite spins<\/strong><\/li>\n\n\n\n<li>So the p-subshell can hold up to <strong>six electrons<\/strong> total<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>The Three Principles<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Aufbau Principle<\/strong>: Electrons fill orbitals in order of increasing energy. Lower energy orbitals fill before higher ones.<\/li>\n\n\n\n<li><strong>Pauli Exclusion Principle<\/strong>: No two electrons in the same atom can have the same set of four quantum numbers. Therefore, each orbital can have at most two electrons, and they must have opposite spins.<\/li>\n\n\n\n<li><strong>Hund&#8217;s Rule<\/strong>: When electrons occupy orbitals of equal energy (degenerate orbitals), one electron enters each orbital until all are half-filled before pairing begins. Electrons in singly occupied orbitals will have parallel spins.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Evaluate the Options<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>(a) 0 1 1<\/strong><br>This means one electron in each of two orbitals and none in the third. This follows:\n<ul class=\"wp-block-list\">\n<li>Hund\u2019s Rule: Yes, electrons occupy separate orbitals before pairing.<\/li>\n\n\n\n<li>Pauli Exclusion Principle: Yes, since no orbital has more than one electron.<\/li>\n\n\n\n<li>Aufbau Principle: Yes, electrons are filling the lowest energy p-orbitals.<br><strong>\u2713 This is correct.<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>(b) 4 _ &#8211;<\/strong><br>Invalid. No orbital can have 4 electrons. This violates both Pauli Exclusion Principle and Aufbau Principle.<br><strong>\u2717 Incorrect.<\/strong><\/li>\n\n\n\n<li><strong>(c) L 1 1<\/strong><br>This is not a valid numeric configuration. &#8216;L&#8217; is not a number, so it&#8217;s ambiguous or invalid.<br><strong>\u2717 Incorrect.<\/strong><\/li>\n\n\n\n<li><strong>(d) 1 4 1<\/strong><br>The second orbital has 4 electrons, which is impossible.<br><strong>\u2717 Incorrect.<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>Only option <strong>(a) 0 1 1<\/strong> satisfies <strong>all three<\/strong> rules of electronic configuration.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-617.jpeg\" alt=\"\" class=\"wp-image-35034\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-617.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-617-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-617-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which electronic configuration for p-orbitals obeys all the rules Pauli Exclusion Principle; Hund&#8217;s Rule and Aufbau Principle)? (a) 0 1 1 (b) 4 _ &#8211; (c) L 1 1 (d) 1 4 1 Select one: Only d b. All of them Only Your answer is incorrect Only Only The Correct Answer and Explanation is: The [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-35025","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35025","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=35025"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35025\/revisions"}],"predecessor-version":[{"id":35035,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/35025\/revisions\/35035"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=35025"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=35025"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=35025"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}