{"id":34109,"date":"2025-06-23T13:44:56","date_gmt":"2025-06-23T13:44:56","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=34109"},"modified":"2025-06-23T13:44:57","modified_gmt":"2025-06-23T13:44:57","slug":"the-graph-represents-velocity-over-time","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-graph-represents-velocity-over-time\/","title":{"rendered":"The graph represents velocity over time"},"content":{"rendered":"\n<p>The graph represents velocity over time. What is the acceleration? -0.4 m\/s\u00b2 -0.2 m\/s\u00b2 0.2 m\/s\u00b2 0.4 m\/s\u00b2<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"995\" height=\"506\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-253.png\" alt=\"\" class=\"wp-image-34110\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-253.png 995w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-253-300x153.png 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-253-768x391.png 768w\" sizes=\"auto, (max-width: 995px) 100vw, 995px\" \/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>0.2 m\/s\u00b2<\/strong>.<\/p>\n\n\n\n<p>To find acceleration from a velocity versus time graph, you analyze the slope of the graph. Acceleration is defined as the rate of change of velocity with respect to time. Mathematically, it is given by the formula:<\/p>\n\n\n\n<p>a=\u0394v\u0394ta = \\frac{\\Delta v}{\\Delta t}<\/p>\n\n\n\n<p>where \u0394v\\Delta v is the change in velocity, and \u0394t\\Delta t is the change in time.<\/p>\n\n\n\n<p>According to the graph, the velocity starts at 0 m\/s and reaches 20 m\/s at 100 seconds. That gives:<\/p>\n\n\n\n<p>\u0394v=20\u2009m\/s\u22120\u2009m\/s=20\u2009m\/s\\Delta v = 20 \\, \\text{m\/s} &#8211; 0 \\, \\text{m\/s} = 20 \\, \\text{m\/s}<\/p>\n\n\n\n<p>\u0394t=100\u2009s\u22120\u2009s=100\u2009s\\Delta t = 100 \\, \\text{s} &#8211; 0 \\, \\text{s} = 100 \\, \\text{s}<\/p>\n\n\n\n<p>Substituting into the formula:<\/p>\n\n\n\n<p>a=20\u2009m\/s100\u2009s=0.2\u2009m\/s2a = \\frac{20 \\, \\text{m\/s}}{100 \\, \\text{s}} = 0.2 \\, \\text{m\/s}^2<\/p>\n\n\n\n<p>This value is positive, which indicates the object is accelerating. Since the velocity-time graph is a straight line, the acceleration is constant throughout the entire time interval. A sloped line on a velocity-time graph always represents uniform acceleration, and the steeper the slope, the greater the acceleration. In this case, the moderate, steady rise from 0 to 20 m\/s over 100 seconds results in a gentle, consistent acceleration.<\/p>\n\n\n\n<p>Among the given choices, 0.2 m\/s\u00b2 matches the calculated value. The negative values can be ruled out because the graph shows velocity increasing rather than decreasing. Likewise, 0.4 m\/s\u00b2 overstates the rate of change.<\/p>\n\n\n\n<p>This analysis highlights how closely interpreting a graph connects to understanding motion. Graphs like these are visual tools that encapsulate physical laws in a simple, elegant form.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-564.jpeg\" alt=\"\" class=\"wp-image-34114\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-564.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-564-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-564-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The graph represents velocity over time. What is the acceleration? -0.4 m\/s\u00b2 -0.2 m\/s\u00b2 0.2 m\/s\u00b2 0.4 m\/s\u00b2 The Correct Answer and Explanation is: The correct answer is 0.2 m\/s\u00b2. To find acceleration from a velocity versus time graph, you analyze the slope of the graph. Acceleration is defined as the rate of change of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-34109","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/34109","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=34109"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/34109\/revisions"}],"predecessor-version":[{"id":34115,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/34109\/revisions\/34115"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=34109"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=34109"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=34109"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}