{"id":33414,"date":"2025-06-23T08:33:47","date_gmt":"2025-06-23T08:33:47","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=33414"},"modified":"2025-06-23T08:33:48","modified_gmt":"2025-06-23T08:33:48","slug":"lithium-oxide-can-be-produced-by-the-reaction-shown-below","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/lithium-oxide-can-be-produced-by-the-reaction-shown-below\/","title":{"rendered":"Lithium oxide can be produced by the reaction shown below."},"content":{"rendered":"\n
Lithium oxide can be produced by the reaction shown below. If a manufacturing company wants to make 25.0 g of Li2O, what mass of Li is necessary? [Molar masses: Li, 6.94 g\/mol; O, 16.00 g\/mol] 4Li(s) + O2(g) \u00e2\u2020\u2019 2Li2O(s) A) 0.0861 g Li B) 2.903 g Li C) 11.6 g Li D) 12.5 g Li E) 23.2 g Li<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
Correct Answer: C) 11.6 g Li<\/strong><\/h3>\n\n\n\n
Step by Step Explanation:<\/h3>\n\n\n\n
Step 1: Write the balanced equation<\/strong>4Li(s)+O2(g)\u21922Li2O(s)4Li (s) + O_2 (g) \\rightarrow 2Li_2O (s)4Li(s)+O2\u200b(g)\u21922Li2\u200bO(s)<\/p>\n\n\n\n
Step 2: Find the molar masses<\/strong><\/p>\n\n\n\n
Step 3: Calculate the moles of Li\u2082O required<\/strong> We are asked to produce 25.0 g of Li\u2082O<\/strong>. Using molar mass:Moles of Li2O=25.0\u2009g29.88\u2009g\/mol=0.8365\u2009mol\\text{Moles of } Li_2O = \\frac{25.0 \\, g}{29.88 \\, g\/mol} = 0.8365 \\, molMoles of Li2\u200bO=29.88g\/mol25.0g\u200b=0.8365mol<\/p>\n\n\n\n
Step 4: Use the mole ratio from the equation<\/strong> From the balanced reaction:<\/p>\n\n\n\n
\n
4 moles of Li produce 2 moles of Li\u2082O<\/li>\n\n\n\n
Therefore, to produce 0.8365 moles of Li\u2082O:<\/li>\n<\/ul>\n\n\n\n
Moles of Li needed=0.8365\u2009mol\u00d74\u2009mol\u2009Li2\u2009mol\u2009Li2O=1.673\u2009mol\u2009Li\\text{Moles of Li needed} = 0.8365 \\, mol \\times \\frac{4 \\, mol \\, Li}{2 \\, mol \\, Li_2O} = 1.673 \\, mol \\, LiMoles of Li needed=0.8365mol\u00d72molLi2\u200bO4molLi\u200b=1.673molLi<\/p>\n\n\n\n
Step 5: Calculate mass of Lithium required<\/strong>Mass of Li=1.673\u2009mol\u00d76.94\u2009g\/mol=11.61\u2009g\\text{Mass of Li} = 1.673 \\, mol \\times 6.94 \\, g\/mol = 11.61 \\, gMass of Li=1.673mol\u00d76.94g\/mol=11.61g<\/p>\n\n\n\n
Final Mass Rounded to Three Significant Figures<\/strong>11.6\u2009g11.6 \\, g11.6g<\/p>\n\n\n\n
Conclusion:<\/h3>\n\n\n\n
The company needs 11.6 grams of Lithium<\/strong> to produce 25.0 grams of Lithium Oxide.<\/p>\n\n\n\n
Thus, the correct choice is C) 11.6 g Li<\/strong>.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
Lithium oxide can be produced by the reaction shown below. If a manufacturing company wants to make 25.0 g of Li2O, what mass of Li is necessary? [Molar masses: Li, 6.94 g\/mol; O, 16.00 g\/mol] 4Li(s) + O2(g) \u00e2\u2020\u2019 2Li2O(s) A) 0.0861 g Li B) 2.903 g Li C) 11.6 g Li D) 12.5 g […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-33414","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33414","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=33414"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33414\/revisions"}],"predecessor-version":[{"id":33416,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33414\/revisions\/33416"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=33414"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=33414"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=33414"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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