{"id":33036,"date":"2025-06-23T05:33:58","date_gmt":"2025-06-23T05:33:58","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=33036"},"modified":"2025-06-23T05:34:00","modified_gmt":"2025-06-23T05:34:00","slug":"balance-this-chemical-equation-below-nahco3-h2o-co2-na2co3","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/balance-this-chemical-equation-below-nahco3-h2o-co2-na2co3\/","title":{"rendered":"Balance this chemical equation below: NaHCO3 = H2O + CO2 + Na2CO3"},"content":{"rendered":"\n<p>Balance this chemical equation below: NaHCO3 = H2O + CO2 + Na2CO3<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Balanced Chemical Equation:<\/h3>\n\n\n\n<p><strong>2NaHCO\u2083 \u2192 H\u2082O + CO\u2082 + Na\u2082CO\u2083<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Balancing a chemical equation involves ensuring the same number of each type of atom appears on both sides of the equation. The given reaction is the thermal decomposition of sodium bicarbonate (baking soda), which breaks down when heated to form water, carbon dioxide, and sodium carbonate.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step-by-step Process:<\/h4>\n\n\n\n<p>The unbalanced equation is:<br><strong>NaHCO\u2083 \u2192 H\u2082O + CO\u2082 + Na\u2082CO\u2083<\/strong><\/p>\n\n\n\n<p>First, list the elements involved: Sodium (Na), Hydrogen (H), Carbon (C), and Oxygen (O).<\/p>\n\n\n\n<p><strong>Left Side:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Na = 1<\/li>\n\n\n\n<li>H = 1<\/li>\n\n\n\n<li>C = 1<\/li>\n\n\n\n<li>O = 3<\/li>\n<\/ul>\n\n\n\n<p><strong>Right Side (before balancing):<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H\u2082O: H = 2, O = 1<\/li>\n\n\n\n<li>CO\u2082: C = 1, O = 2<\/li>\n\n\n\n<li>Na\u2082CO\u2083: Na = 2, C = 1, O = 3<\/li>\n<\/ul>\n\n\n\n<p>To balance sodium (Na), place a coefficient of 2 before NaHCO\u2083:<\/p>\n\n\n\n<p><strong>2NaHCO\u2083 \u2192 H\u2082O + CO\u2082 + Na\u2082CO\u2083<\/strong><\/p>\n\n\n\n<p>Now, recount the atoms:<\/p>\n\n\n\n<p><strong>Left Side:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Na = 2<\/li>\n\n\n\n<li>H = 2<\/li>\n\n\n\n<li>C = 2<\/li>\n\n\n\n<li>O = 6<\/li>\n<\/ul>\n\n\n\n<p><strong>Right Side:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H\u2082O: H = 2, O = 1<\/li>\n\n\n\n<li>CO\u2082: C = 1, O = 2<\/li>\n\n\n\n<li>Na\u2082CO\u2083: Na = 2, C = 1, O = 3<\/li>\n<\/ul>\n\n\n\n<p>Total on Right Side:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Na = 2<\/li>\n\n\n\n<li>H = 2<\/li>\n\n\n\n<li>C = 2<\/li>\n\n\n\n<li>O = 1 + 2 + 3 = 6<\/li>\n<\/ul>\n\n\n\n<p>All atoms now match on both sides, so the equation is balanced.<\/p>\n\n\n\n<p>This reaction is an example of a decomposition reaction, commonly seen in baking processes. Heating sodium bicarbonate produces carbon dioxide gas, which helps dough or batter rise. The leftover solid sodium carbonate and water vapor are byproducts of the decomposition. Balancing ensures the reaction follows the law of conservation of mass, meaning matter cannot be created or destroyed, only rearranged.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-480.jpeg\" alt=\"\" class=\"wp-image-33037\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-480.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-480-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-480-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Balance this chemical equation below: NaHCO3 = H2O + CO2 + Na2CO3 The Correct Answer and Explanation is: Balanced Chemical Equation: 2NaHCO\u2083 \u2192 H\u2082O + CO\u2082 + Na\u2082CO\u2083 Explanation: Balancing a chemical equation involves ensuring the same number of each type of atom appears on both sides of the equation. The given reaction is the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-33036","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33036","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=33036"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33036\/revisions"}],"predecessor-version":[{"id":33038,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33036\/revisions\/33038"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=33036"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=33036"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=33036"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}