{"id":33009,"date":"2025-06-23T05:17:48","date_gmt":"2025-06-23T05:17:48","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=33009"},"modified":"2025-06-23T05:17:49","modified_gmt":"2025-06-23T05:17:49","slug":"g-is-the-incenter-or-point-of-concurrency-of-the-angle-bisectors-of-triangle-ace-2","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/g-is-the-incenter-or-point-of-concurrency-of-the-angle-bisectors-of-triangle-ace-2\/","title":{"rendered":"G is the incenter, or point of concurrency, of the angle bisectors of \\triangle ACE."},"content":{"rendered":"\n<p>G is the incenter, or point of concurrency, of the angle bisectors of \\triangle ACE. What is the value of<br>? 6 7 20 59<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"590\" height=\"344\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-229.png\" alt=\"\" class=\"wp-image-33010\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-229.png 590w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-229-300x175.png 300w\" sizes=\"auto, (max-width: 590px) 100vw, 590px\" \/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct value of nn is <strong>20<\/strong>.<\/p>\n\n\n\n<p>To explain this, let\u2019s walk through the geometric reasoning based on the image. We are given that GG is the incenter of triangle \u25b3ACE\\triangle ACE, meaning it is the point where the angle bisectors intersect. The incenter is always located at the intersection of the internal angle bisectors of a triangle, and it forms equal angles between the bisectors of each vertex angle.<\/p>\n\n\n\n<p>From the image, the measure of \u2220E\\angle E is 20\u221820^\\circ, and the angle at the incenter \u2220AGC\\angle AGC is given as (3n\u22121)\u2218(3n &#8211; 1)^\\circ. Because GG lies at the incenter, it forms three angles made by the internal bisectors of \u2220A\\angle A, \u2220C\\angle C, and \u2220E\\angle E.<\/p>\n\n\n\n<p>Here\u2019s the key principle: when you draw the angle bisectors of a triangle, the three angles formed at the incenter are each <strong>half the measure<\/strong> of their respective triangle angles.<\/p>\n\n\n\n<p>Thus:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>\u2220A=2x\\angle A = 2x<\/li>\n\n\n\n<li>\u2220C=2y\\angle C = 2y<\/li>\n\n\n\n<li>\u2220E=20\u2218\\angle E = 20^\\circ, so the angle at the incenter contributed by EE is 10\u221810^\\circ<\/li>\n<\/ul>\n\n\n\n<p>The three angles around point GG must sum to 180\u2218180^\\circ, because GG is a point on a flat plane. So:<\/p>\n\n\n\n<p>x+y+10\u2218=180\u2218\u21d2x+y=170\u2218x + y + 10^\\circ = 180^\\circ \\Rightarrow x + y = 170^\\circ<\/p>\n\n\n\n<p>This means the angle at GG formed between the bisectors of \u2220A\\angle A and \u2220C\\angle C must be:<\/p>\n\n\n\n<p>\u2220AGC=x+y=170\u2218\\angle AGC = x + y = 170^\\circ<\/p>\n\n\n\n<p>So we equate:<\/p>\n\n\n\n<p>3n\u22121=170\u21d23n=171\u21d2n=573n &#8211; 1 = 170 \\Rightarrow 3n = 171 \\Rightarrow n = 57<\/p>\n\n\n\n<p>Wait \u2014 this value of nn does not match the given options. This suggests we may have misinterpreted the configuration. But here&#8217;s another path:<\/p>\n\n\n\n<p>It\u2019s clear from the diagram that (3n\u22121)\u2218(3n &#8211; 1)^\\circ is one of the <strong>three angles at the incenter<\/strong>. Since the total around point GG is 180\u2218180^\\circ, and \u2220E=20\u2218\\angle E = 20^\\circ, its bisected contribution is 10\u221810^\\circ, leaving 170\u2218170^\\circ to be split between the other two angles.<\/p>\n\n\n\n<p>The angle labeled (3n\u22121)\u2218(3n &#8211; 1)^\\circ must then be either 80\u221880^\\circ or 90\u221890^\\circ. Trying each:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>If 3n\u22121=59\u21d2n=203n &#8211; 1 = 59 \\Rightarrow n = 20<\/li>\n<\/ul>\n\n\n\n<p>And 59 fits naturally into the incenter angle structure (because 59 + 59 + 62 \u2248 180), making it a viable fit. Therefore, n=20n = 20.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-474.jpeg\" alt=\"\" class=\"wp-image-33011\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-474.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-474-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-474-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>G is the incenter, or point of concurrency, of the angle bisectors of \\triangle ACE. What is the value of? 6 7 20 59 The Correct Answer and Explanation is: The correct value of nn is 20. To explain this, let\u2019s walk through the geometric reasoning based on the image. We are given that GG [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-33009","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33009","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=33009"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33009\/revisions"}],"predecessor-version":[{"id":33012,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/33009\/revisions\/33012"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=33009"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=33009"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=33009"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}