{"id":32974,"date":"2025-06-23T04:50:46","date_gmt":"2025-06-23T04:50:46","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=32974"},"modified":"2025-06-23T04:50:47","modified_gmt":"2025-06-23T04:50:47","slug":"4al-3o2-2al2o3-how-many-grams-of-aluminum-are-burned-if-200-0-grams-of-aluminum-oxide-are-formed","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/4al-3o2-2al2o3-how-many-grams-of-aluminum-are-burned-if-200-0-grams-of-aluminum-oxide-are-formed\/","title":{"rendered":"4Al + 3O2 -> 2Al2O3 how many grams of aluminum are burned if 200.0 grams of aluminum oxide are formed"},"content":{"rendered":"\n<p>4Al + 3O2 -> 2Al2O3 how many grams of aluminum are burned if 200.0 grams of aluminum oxide are formed?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h6 class=\"wp-block-heading\">ChatGPT said:<\/h6>\n\n\n\n<p><strong>Correct Answer:<\/strong><br><strong>Aluminum burned = 105.88 grams<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Step-by-Step Explanation:<\/strong><\/p>\n\n\n\n<p>We are asked how many grams of aluminum are burned if 200.0 grams of aluminum oxide (Al\u2082O\u2083) are formed based on the reaction:<\/p>\n\n\n\n<p><strong>4Al + 3O\u2082 \u2192 2Al\u2082O\u2083<\/strong><\/p>\n\n\n\n<p><strong>Step 1: Calculate Molar Masses<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Aluminum (Al) = 27.0 g\/mol<\/li>\n\n\n\n<li>Oxygen (O) = 16.0 g\/mol<\/li>\n\n\n\n<li>Aluminum oxide (Al\u2082O\u2083) = (2 \u00d7 27.0) + (3 \u00d7 16.0) = 54.0 + 48.0 = <strong>102.0 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<p><strong>Step 2: Determine Moles of Aluminum Oxide Formed<\/strong><br>Given mass of Al\u2082O\u2083 = 200.0 grams<br>Molar mass of Al\u2082O\u2083 = 102.0 g\/mol<\/p>\n\n\n\n<p>Moles of Al\u2082O\u2083 = Mass \/ Molar Mass = 200.0 g \/ 102.0 g\/mol \u2248 <strong>1.9608 moles<\/strong><\/p>\n\n\n\n<p><strong>Step 3: Find the Moles of Aluminum Reacted Using the Balanced Equation<\/strong><br>The balanced equation shows:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>4 moles of Al produce 2 moles of Al\u2082O\u2083<\/li>\n<\/ul>\n\n\n\n<p>Thus, moles of Al required = (4 moles Al \/ 2 moles Al\u2082O\u2083) \u00d7 1.9608 moles Al\u2082O\u2083<br>Moles of Al = 3.9216 moles<\/p>\n\n\n\n<p><strong>Step 4: Convert Moles of Aluminum to Grams<\/strong><br>Molar mass of Aluminum = 27.0 g\/mol<\/p>\n\n\n\n<p>Mass of Aluminum = Moles \u00d7 Molar Mass = 3.9216 moles \u00d7 27.0 g\/mol \u2248 <strong>105.88 grams<\/strong><\/p>\n\n\n\n<p><strong>Final Answer:<\/strong> Approximately <strong>105.88 grams<\/strong> of aluminum are burned.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>Additional Notes:<\/strong><br>This calculation follows the stoichiometric relationships in the balanced chemical equation. The mass-to-mole and mole-to-mass conversions are essential to link the amount of product formed to the amount of reactant used. This type of problem is common in chemistry to ensure reactants are used efficiently and to predict reactant requirements for industrial or laboratory reactions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-466.jpeg\" alt=\"\" class=\"wp-image-32975\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-466.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-466-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-466-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>4Al + 3O2 -> 2Al2O3 how many grams of aluminum are burned if 200.0 grams of aluminum oxide are formed? The Correct Answer and Explanation is: ChatGPT said: Correct Answer:Aluminum burned = 105.88 grams Step-by-Step Explanation: We are asked how many grams of aluminum are burned if 200.0 grams of aluminum oxide (Al\u2082O\u2083) are formed [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32974","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32974","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32974"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32974\/revisions"}],"predecessor-version":[{"id":32976,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32974\/revisions\/32976"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32974"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32974"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32974"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}