In the Zn2+ ion (in its ground state), how many electrons are l = 0 and s = -1\/2? The atomic number of Zn is 30.<\/p>\n\n\n\n
The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n Correct Answer: 5 electrons<\/strong><\/p>\n\n\n\n To solve this question, we need to understand the electronic configuration of the Zn\u00b2\u207a ion and identify the electrons that have azimuthal quantum number (l) = 0<\/strong> and spin quantum number (s) = -1\/2<\/strong>.<\/p>\n\n\n\n Zinc has an atomic number of 30, which means a neutral zinc atom has 30 electrons. The electron configuration of neutral Zn is:<\/p>\n\n\n\n Zn: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b9\u2070 4s\u00b2<\/strong><\/p>\n\n\n\n The Zn\u00b2\u207a ion has lost two electrons. Electrons are always removed from the outermost shell first, which means from the 4s orbital<\/strong>.<\/p>\n\n\n\n So, Zn\u00b2\u207a configuration becomes:<\/p>\n\n\n\n Zn\u00b2\u207a: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b9\u2070<\/strong><\/p>\n\n\n\n Now Zn\u00b2\u207a has 28 electrons<\/strong>.<\/p>\n\n\n\n Now count the electrons in s-orbitals (l = 0):<\/p>\n\n\n\n Each s orbital holds 2 electrons, one with spin +1\/2 and one with spin -1\/2.<\/p>\n\n\n\n There are three s-orbitals<\/strong>, and each has one electron with spin -1\/2:<\/p>\n\n\n\n 1s\u00b2 \u2192 1 In addition, 4s\u00b2 would have had 1 more, but those were removed in forming Zn\u00b2\u207a.<\/p>\n\n\n\n So far, this gives 3 electrons<\/strong>.<\/p>\n\n\n\n However, we missed the s electrons in the p shells<\/strong>:<\/p>\n\n\n\n Now reconsider: are there other s-type electrons? Yes, 4s\u00b2<\/strong> originally had 2, but those were removed.<\/p>\n\n\n\n So the only s orbitals with electrons are:<\/p>\n\n\n\n Each contributes 1 spin-down<\/strong> electron.<\/p>\n\n\n\n Therefore, the number of electrons with l = 0<\/strong> and s = -1\/2<\/strong> in Zn\u00b2\u207a is 3<\/strong>.<\/p>\n\n\n\n Correction: this shows 3<\/strong>, not 5.<\/p>\n\n\n\n Let us now double-check and correct accordingly.<\/p>\n\n\n\n Electrons in s-orbitals in Zn\u00b2\u207a:<\/p>\n\n\n\n That gives 3<\/strong> electrons.<\/p>\n\n\n\n Therefore, the correct answer is: 3 electrons<\/strong><\/p>\n\n\n\n In the Zn2+ ion (in its ground state), how many electrons are l = 0 and s = -1\/2? The atomic number of Zn is 30. The correct answer and explanation is: Correct Answer: 5 electrons Explanation: To solve this question, we need to understand the electronic configuration of the Zn\u00b2\u207a ion and identify the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32727","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32727","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32727"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32727\/revisions"}],"predecessor-version":[{"id":32728,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32727\/revisions\/32728"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32727"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32727"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32727"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
\n\n\n\nStep 1: Atomic Number and Neutral Zinc Configuration<\/h4>\n\n\n\n
\n\n\n\nStep 2: Zinc Ion Zn\u00b2\u207a Configuration<\/h4>\n\n\n\n
\n\n\n\nStep 3: Determine How Many Electrons Have l = 0 and s = -1\/2<\/h4>\n\n\n\n
\n
\n
2s\u00b2 \u2192 1
3s\u00b2 \u2192 1<\/p>\n\n\n\n\n
\n
\n\n\n\nFinal Confirmation:<\/h4>\n\n\n\n
\n
Final Answer: 3 electrons<\/strong><\/h3>\n","protected":false},"excerpt":{"rendered":"