{"id":32608,"date":"2025-06-22T17:22:30","date_gmt":"2025-06-22T17:22:30","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=32608"},"modified":"2025-06-22T17:22:31","modified_gmt":"2025-06-22T17:22:31","slug":"the-lewis-structure-of-hcn-h-bonded-to-c-shows-that-n-has-_-bonding-and-__-nonbonding-electron-pairs-respectively","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-lewis-structure-of-hcn-h-bonded-to-c-shows-that-n-has-_-bonding-and-__-nonbonding-electron-pairs-respectively\/","title":{"rendered":"The Lewis structure of HCN (H bonded to C) shows that N has _ bonding and __ nonbonding electron pair(s) respectively."},"content":{"rendered":"\n<p>The Lewis structure of HCN (H bonded to C) shows that N has <strong>_ bonding and __<\/strong> nonbonding electron pair(s) respectively. A) 3, 1 B) 1, 1 C) 2, 2 D) 3, 2<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: A) 3, 1<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>The Lewis structure of <strong>HCN<\/strong> (hydrogen cyanide) provides a visual representation of how the atoms bond and how electrons are shared or remain unshared.<\/p>\n\n\n\n<p>Hydrogen (H) has 1 valence electron and can form only one bond. Carbon (C) has 4 valence electrons and tends to form 4 bonds. Nitrogen (N) has 5 valence electrons and tends to form 3 bonds, often leaving one lone pair of electrons.<\/p>\n\n\n\n<p>To construct the Lewis structure of HCN:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Place hydrogen on one side, since it forms only one bond.<\/li>\n\n\n\n<li>Carbon is in the center because it forms the most bonds.<\/li>\n\n\n\n<li>Nitrogen is placed at the opposite end of carbon.<\/li>\n<\/ol>\n\n\n\n<p>Now arrange the atoms as <strong>H\u2013C\u2261N<\/strong>, with a triple bond between carbon and nitrogen, and a single bond between hydrogen and carbon.<\/p>\n\n\n\n<p>Here\u2019s the breakdown:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Hydrogen shares its one electron with carbon, forming a single bond.<\/li>\n\n\n\n<li>Carbon uses three of its electrons to form a triple bond with nitrogen and one electron to bond with hydrogen.<\/li>\n\n\n\n<li>Nitrogen contributes three of its valence electrons to the triple bond with carbon. That makes 6 electrons in bonding pairs (3 bonding pairs).<\/li>\n\n\n\n<li>Nitrogen has 5 valence electrons in total. After donating 3 electrons for bonding, it has 2 left, which form one <strong>nonbonding pair<\/strong> (a lone pair).<\/li>\n<\/ul>\n\n\n\n<p>Thus, nitrogen in HCN has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>3 bonding pairs<\/strong> of electrons shared with carbon (in the triple bond)<\/li>\n\n\n\n<li><strong>1 nonbonding pair<\/strong> (lone pair) of electrons that is not shared<\/li>\n<\/ul>\n\n\n\n<p>This matches choice <strong>A: 3 bonding and 1 nonbonding pair<\/strong>. The structure satisfies the octet rule for carbon and nitrogen and the duet rule for hydrogen.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-418.jpeg\" alt=\"\" class=\"wp-image-32615\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-418.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-418-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-418-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The Lewis structure of HCN (H bonded to C) shows that N has _ bonding and __ nonbonding electron pair(s) respectively. A) 3, 1 B) 1, 1 C) 2, 2 D) 3, 2 The Correct Answer and Explanation is: Correct Answer: A) 3, 1 Explanation: The Lewis structure of HCN (hydrogen cyanide) provides a visual [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32608","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32608","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32608"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32608\/revisions"}],"predecessor-version":[{"id":32616,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32608\/revisions\/32616"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32608"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32608"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32608"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}