{"id":32511,"date":"2025-06-22T15:00:48","date_gmt":"2025-06-22T15:00:48","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=32511"},"modified":"2025-06-22T15:00:49","modified_gmt":"2025-06-22T15:00:49","slug":"the-density-of-2-methyl-2-butanol-is-0-806-g-ml","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-density-of-2-methyl-2-butanol-is-0-806-g-ml\/","title":{"rendered":"The density of 2-methyl-2-butanol is 0.806 g\/mL"},"content":{"rendered":"\n
The density of 2-methyl-2-butanol is 0.806 g\/mL. How many milligrams represent an aliquot of 430 \u00ce\u00bcL? How many millimoles represent an aliquot of 0.650 mL (2-methyl-2-butanol; formula weight is 88.15 g\/mol)?<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n
Let’s solve both parts step by step.<\/p>\n\n\n\n
\n\n\n\n
Part 1: How many milligrams are in 430 \u00b5L of 2-methyl-2-butanol?<\/strong><\/h3>\n\n\n\n
Given:<\/p>\n\n\n\n
\n
Volume = 430 \u00b5L<\/li>\n\n\n\n
Density = 0.806 g\/mL<\/li>\n\n\n\n
1 mL = 1000 \u00b5L<\/li>\n\n\n\n
1 g = 1000 mg<\/li>\n<\/ul>\n\n\n\n
Step 1: Convert \u00b5L to mL<\/strong>430\u2009\u03bcL=4301000=0.430\u2009mL430 \\, \\mu L = \\frac{430}{1000} = 0.430 \\, mL430\u03bcL=1000430\u200b=0.430mL<\/p>\n\n\n\n
Step 2: Use density to find mass in grams<\/strong>Mass=Density\u00d7Volume=0.806\u2009g\/mL\u00d70.430\u2009mL=0.34658\u2009g\\text{Mass} = \\text{Density} \\times \\text{Volume} = 0.806 \\, g\/mL \\times 0.430 \\, mL = 0.34658 \\, gMass=Density\u00d7Volume=0.806g\/mL\u00d70.430mL=0.34658g<\/p>\n\n\n\n
Step 3: Convert grams to milligrams<\/strong>0.34658\u2009g\u00d71000=346.58\u2009mg0.34658 \\, g \\times 1000 = 346.58 \\, mg0.34658g\u00d71000=346.58mg<\/p>\n\n\n\n
Answer for Part 1:<\/strong> 346.58 mg<\/strong><\/p>\n\n\n\n\n\n\n\n
Part 2: How many millimoles are in 0.650 mL of 2-methyl-2-butanol?<\/strong><\/h3>\n\n\n\n
Given:<\/p>\n\n\n\n
\n
Volume = 0.650 mL<\/li>\n\n\n\n
Density = 0.806 g\/mL<\/li>\n\n\n\n
Formula weight = 88.15 g\/mol<\/li>\n<\/ul>\n\n\n\n
Step 1: Calculate mass in grams<\/strong>Mass=Density\u00d7Volume=0.806\u2009g\/mL\u00d70.650\u2009mL=0.5239\u2009g\\text{Mass} = \\text{Density} \\times \\text{Volume} = 0.806 \\, g\/mL \\times 0.650 \\, mL = 0.5239 \\, gMass=Density\u00d7Volume=0.806g\/mL\u00d70.650mL=0.5239g<\/p>\n\n\n\n
Answer for Part 2:<\/strong> 5.94 mmol<\/strong><\/p>\n\n\n\n\n\n\n\n
Explanation<\/strong><\/h3>\n\n\n\n
To determine the amount of 2-methyl-2-butanol present in different volumes, we apply concepts from density and stoichiometry. Density provides a way to relate the volume of a substance to its mass. Since the density of 2-methyl-2-butanol is 0.806 g\/mL, this means that every 1 mL of the alcohol weighs 0.806 grams.<\/p>\n\n\n\n
In the first part, we convert microliters to milliliters to match the units used with density. Since 1000 \u00b5L equals 1 mL, 430 \u00b5L is 0.430 mL. Multiplying this volume by the density yields the mass in grams. To express the result in milligrams, which are thousandths of a gram, we multiply the gram value by 1000. This gives a total of 346.58 milligrams.<\/p>\n\n\n\n
In the second part, we calculate the number of millimoles, a common unit in chemical analysis. The volume is given in milliliters, so we use the density directly to get the mass in grams. We then divide by the molar mass of the compound, which tells us how many grams are in one mole of the substance. This calculation gives the amount in moles. Since a millimole is one-thousandth of a mole, we multiply the mole value by 1000 to convert. The final result is 5.94 millimoles.<\/p>\n\n\n\n
These calculations are essential in preparing solutions, determining reactant quantities, or analyzing sample compositions in both academic and professional laboratory settings.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"
The density of 2-methyl-2-butanol is 0.806 g\/mL. How many milligrams represent an aliquot of 430 \u00ce\u00bcL? How many millimoles represent an aliquot of 0.650 mL (2-methyl-2-butanol; formula weight is 88.15 g\/mol)? The Correct Answer and Explanation is: Let’s solve both parts step by step. Part 1: How many milligrams are in 430 \u00b5L of 2-methyl-2-butanol? […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32511","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32511","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32511"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32511\/revisions"}],"predecessor-version":[{"id":32513,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32511\/revisions\/32513"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32511"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32511"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32511"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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