{"id":32333,"date":"2025-06-22T12:45:53","date_gmt":"2025-06-22T12:45:53","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=32333"},"modified":"2025-06-22T12:45:54","modified_gmt":"2025-06-22T12:45:54","slug":"naoh-h2co3-%e2%86%92-na2co3-h2o-balance-the-chemical-equations","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/naoh-h2co3-%e2%86%92-na2co3-h2o-balance-the-chemical-equations\/","title":{"rendered":"NaOH + H2CO3 \u2192 Na2CO3 + H2O balance the chemical equations"},"content":{"rendered":"\n<p>NaOH + H2CO3 \u2192 Na2CO3 + H2O balance the chemical equations<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Balanced Chemical Equation:<\/strong><\/p>\n\n\n\n<p>2NaOH + H\u2082CO\u2083 \u2192 Na\u2082CO\u2083 + 2H\u2082O<\/p>\n\n\n\n<p><strong>Explanation (300 words):<\/strong><\/p>\n\n\n\n<p>Balancing chemical equations ensures that the same number of each type of atom appears on both the reactant and product sides of the equation, in accordance with the Law of Conservation of Mass. In the given chemical reaction, sodium hydroxide (NaOH) reacts with carbonic acid (H\u2082CO\u2083) to form sodium carbonate (Na\u2082CO\u2083) and water (H\u2082O).<\/p>\n\n\n\n<p>To balance this reaction, examine each element one by one. Begin with sodium (Na). The product Na\u2082CO\u2083 contains two sodium atoms, meaning two NaOH molecules are needed to supply the two Na atoms. Write 2NaOH on the left side.<\/p>\n\n\n\n<p>Next, look at the hydrogen and oxygen atoms. Carbonic acid (H\u2082CO\u2083) contains two hydrogen atoms and three oxygen atoms. On the right side, Na\u2082CO\u2083 contributes three oxygen atoms, and water molecules contribute both hydrogen and oxygen. Since two NaOH molecules provide two hydroxide ions (OH\u207b), and H\u2082CO\u2083 provides two hydrogen ions (H\u207a), they combine to form two water molecules (H\u2082O).<\/p>\n\n\n\n<p>So, the hydrogen atoms from H\u2082CO\u2083 and the hydroxide ions from NaOH result in two water molecules. Therefore, place a coefficient of 2 in front of H\u2082O on the product side.<\/p>\n\n\n\n<p>After this, count each type of atom:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sodium: 2 on both sides<\/li>\n\n\n\n<li>Hydrogen: 2 from H\u2082CO\u2083 and 2 from 2NaOH \u2192 2H in 2H\u2082O<\/li>\n\n\n\n<li>Carbon: 1 on both sides<\/li>\n\n\n\n<li>Oxygen: 3 from H\u2082CO\u2083 and 2 from 2NaOH \u2192 3 in Na\u2082CO\u2083 and 2 in 2H\u2082O<\/li>\n<\/ul>\n\n\n\n<p>This confirms the equation is balanced. The overall reaction is a neutralization reaction between a base (NaOH) and an acid (H\u2082CO\u2083), forming a salt (Na\u2082CO\u2083) and water.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NaOH + H2CO3 \u2192 Na2CO3 + H2O balance the chemical equations The correct answer and explanation is: Balanced Chemical Equation: 2NaOH + H\u2082CO\u2083 \u2192 Na\u2082CO\u2083 + 2H\u2082O Explanation (300 words): Balancing chemical equations ensures that the same number of each type of atom appears on both the reactant and product sides of the equation, in [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32333","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32333","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32333"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32333\/revisions"}],"predecessor-version":[{"id":32334,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32333\/revisions\/32334"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32333"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32333"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32333"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}