{"id":32154,"date":"2025-06-22T11:39:09","date_gmt":"2025-06-22T11:39:09","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=32154"},"modified":"2025-06-22T11:39:10","modified_gmt":"2025-06-22T11:39:10","slug":"calculate-the-molar-mass-of-the-substance-phosphorus-molecule-p4-atomic-mass-of-phosphorus-31","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/calculate-the-molar-mass-of-the-substance-phosphorus-molecule-p4-atomic-mass-of-phosphorus-31\/","title":{"rendered":"Calculate the molar mass of the substance – Phosphorus molecule, P4 (Atomic mass of phosphorus = 31)"},"content":{"rendered":"\n

Calculate the molar mass of the substance – Phosphorus molecule, P4 (Atomic mass of phosphorus = 31)<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

Correct Answer:<\/strong><\/p>\n\n\n\n

The molar mass of the phosphorus molecule, P\u2084, is:Molar mass of P4=4\u00d731=124 g\/mol\\text{Molar mass of P}_4 = 4 \\times 31 = 124 \\text{ g\/mol}Molar mass of P4\u200b=4\u00d731=124 g\/mol<\/p>\n\n\n\n

\n\n\n\n

Explanation:<\/strong><\/p>\n\n\n\n

To calculate the molar mass of any compound or molecule, we first need to know two key pieces of information:<\/p>\n\n\n\n

    \n
  1. The chemical formula of the molecule<\/li>\n\n\n\n
  2. The atomic masses of the constituent elements<\/li>\n<\/ol>\n\n\n\n

    In this case, the molecule in question is phosphorus<\/strong>, which commonly exists in nature as a tetraphosphorus<\/strong> molecule, written as P\u2084<\/strong>. This molecular form means that one molecule of phosphorus consists of four atoms<\/strong> of phosphorus chemically bonded together.<\/p>\n\n\n\n

    The atomic mass of a single phosphorus atom is given as 31 grams per mole<\/strong>. This means that one mole<\/strong> of phosphorus atoms weighs 31 grams<\/strong>. However, since the P\u2084 molecule contains four phosphorus atoms<\/strong>, we must multiply the atomic mass by 4<\/strong> to get the total molar mass of the P\u2084 molecule:Molar mass of P4=4\u00d731=124 grams per mole\\text{Molar mass of P}_4 = 4 \\times 31 = 124 \\text{ grams per mole}Molar mass of P4\u200b=4\u00d731=124 grams per mole<\/p>\n\n\n\n

    This calculation tells us that one mole<\/strong> of P\u2084 molecules weighs 124 grams<\/strong>. This value is essential in stoichiometry when performing chemical reaction calculations involving phosphorus.<\/p>\n\n\n\n

    Understanding molar mass allows chemists to convert between the mass of a substance and the number of moles, which is important when determining reactant-product relationships, reaction yields, and reagent quantities.<\/p>\n\n\n\n

    For example, if a chemist needs 1 mole of P\u2084 for a reaction, they must weigh out 124 grams of the substance. If they only have 62 grams, then they have 0.5 moles of P\u2084. This concept ensures that chemical reactions are carried out using precise quantities, leading to correct and predictable outcomes.<\/p>\n\n\n\n

    \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

    Calculate the molar mass of the substance – Phosphorus molecule, P4 (Atomic mass of phosphorus = 31) The Correct Answer and Explanation is: Correct Answer: The molar mass of the phosphorus molecule, P\u2084, is:Molar mass of P4=4\u00d731=124 g\/mol\\text{Molar mass of P}_4 = 4 \\times 31 = 124 \\text{ g\/mol}Molar mass of P4\u200b=4\u00d731=124 g\/mol Explanation: To calculate the molar mass of any compound or […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32154","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32154","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32154"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32154\/revisions"}],"predecessor-version":[{"id":32170,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32154\/revisions\/32170"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32154"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32154"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32154"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}