{"id":32053,"date":"2025-06-22T10:53:24","date_gmt":"2025-06-22T10:53:24","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=32053"},"modified":"2025-06-22T10:53:26","modified_gmt":"2025-06-22T10:53:26","slug":"give-the-nuclear-symbol-isotope-symbol-for-the-isotope-of-bromine-br-that-contains-46-neutrons-per-atom","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/give-the-nuclear-symbol-isotope-symbol-for-the-isotope-of-bromine-br-that-contains-46-neutrons-per-atom\/","title":{"rendered":"Give the nuclear symbol (isotope symbol) for the isotope of bromine, Br, that contains 46 neutrons per atom."},"content":{"rendered":"\n<p>Give the nuclear symbol (isotope symbol) for the isotope of bromine, Br, that contains 46 neutrons per atom. Replace the question marks with the proper integers. nuclear symbol: $^{80}_{35}Br<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"700\" height=\"378\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-192.png\" alt=\"\" class=\"wp-image-32058\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-192.png 700w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/image-192-300x162.png 300w\" sizes=\"auto, (max-width: 700px) 100vw, 700px\" \/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct nuclear symbol is:<br><strong>\u2083\u2085\u2078\u00b9Br<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the nuclear (isotope) symbol of an element, we use the notation:<\/p>\n\n\n\n<p><strong>\u2090\u1dbbX<\/strong><\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>X<\/strong> is the chemical symbol of the element (in this case, <strong>Br<\/strong> for bromine),<\/li>\n\n\n\n<li><strong>Z<\/strong> is the atomic number (number of protons),<\/li>\n\n\n\n<li><strong>A<\/strong> is the mass number (sum of protons and neutrons).<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Identify the atomic number of bromine (Br)<\/h4>\n\n\n\n<p>The atomic number <strong>Z<\/strong> of bromine is <strong>35<\/strong>.<br>This means each atom of bromine has <strong>35 protons<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Use the given number of neutrons<\/h4>\n\n\n\n<p>We are told that this isotope of bromine has <strong>46 neutrons<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 3: Calculate the mass number (A)<\/h4>\n\n\n\n<p>The mass number is the total number of protons and neutrons:A=number&nbsp;of&nbsp;protons&nbsp;(Z)+number&nbsp;of&nbsp;neutronsA = \\text{number of protons (Z)} + \\text{number of neutrons}A=number&nbsp;of&nbsp;protons&nbsp;(Z)+number&nbsp;of&nbsp;neutronsA=35+46=81A = 35 + 46 = 81A=35+46=81<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\">Step 4: Write the nuclear symbol<\/h4>\n\n\n\n<p>Now that we know:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Z = 35<\/strong> (atomic number),<\/li>\n\n\n\n<li><strong>A = 81<\/strong> (mass number),<\/li>\n\n\n\n<li><strong>X = Br<\/strong> (element symbol),<\/li>\n<\/ul>\n\n\n\n<p>The isotope symbol is:<br><strong>\u2083\u2085\u2078\u00b9Br<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>This notation is essential in nuclear chemistry and physics because it clearly shows both the identity of the element and the specific isotope. Isotopes of the same element have the same number of protons but different numbers of neutrons, resulting in different mass numbers. In this case, bromine can exist in several isotopic forms, and the isotope with 46 neutrons is designated as bromine-81.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-203.jpeg\" alt=\"\" class=\"wp-image-32059\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-203.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-203-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-203-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-203-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Give the nuclear symbol (isotope symbol) for the isotope of bromine, Br, that contains 46 neutrons per atom. Replace the question marks with the proper integers. nuclear symbol: $^{80}_{35}Br The Correct Answer and Explanation is: The correct nuclear symbol is:\u2083\u2085\u2078\u00b9Br Explanation: To determine the nuclear (isotope) symbol of an element, we use the notation: \u2090\u1dbbX [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-32053","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32053","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=32053"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32053\/revisions"}],"predecessor-version":[{"id":32060,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/32053\/revisions\/32060"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=32053"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=32053"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=32053"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}