{"id":31608,"date":"2025-06-22T04:51:18","date_gmt":"2025-06-22T04:51:18","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=31608"},"modified":"2025-06-22T04:51:20","modified_gmt":"2025-06-22T04:51:20","slug":"compound-a-was-treated-with-excess-methyl-iodide-and-then-heated-in-the-presence-of-aqueous-silver-oxide-to-produce-an-alkene","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/compound-a-was-treated-with-excess-methyl-iodide-and-then-heated-in-the-presence-of-aqueous-silver-oxide-to-produce-an-alkene\/","title":{"rendered":"Compound A was treated with excess methyl iodide and then heated in the presence of aqueous silver oxide to produce an alkene"},"content":{"rendered":"\n<p><br>Integrated Problem 22.86 Get help answering Molecular Drawing questions. Compound A (<br>) is an amine that does not possess a chirality center. Compound A was treated with excess methyl iodide and then heated in the presence of aqueous silver oxide to produce an alkene. The alkene was further subjected to ozonolysis to produce butanal and pentanal. Draw the structure of compound A.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine the structure of <strong>Compound A<\/strong>, we will work backward from the <strong>ozonolysis products<\/strong> and understand how the reactions lead us to an <strong>amine that is not chiral<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Ozonolysis Products<\/strong><\/h3>\n\n\n\n<p>The ozonolysis of the <strong>alkene<\/strong> yields:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Butanal<\/strong> (CH\u2083CH\u2082CH\u2082CHO)<\/li>\n\n\n\n<li><strong>Pentanal<\/strong> (CH\u2083CH\u2082CH\u2082CH\u2082CHO)<\/li>\n<\/ul>\n\n\n\n<p>Ozonolysis breaks the double bond in an alkene and replaces it with carbonyl groups on each carbon that was part of the double bond. So, if we got <strong>butanal and pentanal<\/strong>, the <strong>alkene<\/strong> must have had a double bond between:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A <strong>4-carbon chain<\/strong> (that gives butanal) and<\/li>\n\n\n\n<li>A <strong>5-carbon chain<\/strong> (that gives pentanal)<\/li>\n<\/ul>\n\n\n\n<p>Thus, the <strong>alkene<\/strong> formed after elimination was <strong>non-symmetrical<\/strong>, with the double bond located between carbon 4 and carbon 5 in a <strong>nine-carbon chain<\/strong>.<\/p>\n\n\n\n<p>So the <strong>alkene<\/strong> is:<br><strong>CH\u2083CH\u2082CH\u2082CH=CHCH\u2082CH\u2082CH\u2082CH\u2083<\/strong><br>This is <strong>nonene<\/strong>, specifically <strong>4-nonene<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Source of the Alkene \u2013 Hofmann Elimination<\/strong><\/h3>\n\n\n\n<p>The alkene was produced by heating a <strong>quaternary ammonium salt<\/strong> with aqueous <strong>silver oxide<\/strong>, which is a <strong>Hofmann elimination<\/strong> reaction. In this reaction:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>An <strong>amine<\/strong> is methylated with <strong>excess methyl iodide<\/strong> to make a <strong>quaternary ammonium iodide<\/strong><\/li>\n\n\n\n<li>Then it&#8217;s converted into a <strong>quaternary ammonium hydroxide<\/strong> using <strong>Ag\u2082O and H\u2082O<\/strong><\/li>\n\n\n\n<li>Heating leads to <strong>elimination of the least hindered \u03b2-hydrogen<\/strong>, forming an alkene<\/li>\n<\/ul>\n\n\n\n<p>So the starting <strong>amine (Compound A)<\/strong> must be a <strong>primary or secondary amine<\/strong> with a <strong>nine-carbon chain<\/strong> that leads to <strong>4-nonene<\/strong> after Hofmann elimination.<\/p>\n\n\n\n<p>The only structure that fits and <strong>has no chirality center<\/strong> is:<br><strong>4-aminononane<\/strong> \u2192 <strong>CH\u2083CH\u2082CH\u2082CH(NH\u2082)CH\u2082CH\u2082CH\u2082CH\u2082CH\u2083<\/strong><\/p>\n\n\n\n<p>But this has a chirality center at carbon 4, so it cannot be Compound A.<\/p>\n\n\n\n<p>Now consider <strong>nonylamine<\/strong> (1-aminononane), which is <strong>CH\u2083(CH\u2082)\u2088NH\u2082<\/strong>.<br>This amine has <strong>no chirality center<\/strong> and upon quaternization and Hofmann elimination, elimination occurs at the \u03b2-position, favoring the formation of <strong>4-nonene<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 <strong>Final Answer: Compound A is 1-nonanamine (nonylamine)<\/strong><\/h3>\n\n\n\n<p>Structure: <strong>CH\u2083(CH\u2082)\u2088NH\u2082<\/strong><\/p>\n\n\n\n<p>This satisfies:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Being an <strong>amine<\/strong><\/li>\n\n\n\n<li>Having <strong>no chirality center<\/strong><\/li>\n\n\n\n<li>Giving <strong>4-nonene<\/strong> after Hofmann elimination<\/li>\n\n\n\n<li>Producing <strong>butanal and pentanal<\/strong> upon ozonolysis<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-351.jpeg\" alt=\"\" class=\"wp-image-31609\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-351.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-351-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-351-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Integrated Problem 22.86 Get help answering Molecular Drawing questions. Compound A () is an amine that does not possess a chirality center. Compound A was treated with excess methyl iodide and then heated in the presence of aqueous silver oxide to produce an alkene. The alkene was further subjected to ozonolysis to produce butanal and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-31608","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31608","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=31608"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31608\/revisions"}],"predecessor-version":[{"id":31610,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31608\/revisions\/31610"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=31608"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=31608"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=31608"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}