{"id":31520,"date":"2025-06-22T03:29:37","date_gmt":"2025-06-22T03:29:37","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=31520"},"modified":"2025-06-22T03:29:39","modified_gmt":"2025-06-22T03:29:39","slug":"calculate-the-molarity-of-a-sulfuric-acid-solution-containing-24-4g-of-sulfuric-acid-in-198g-of-water","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/calculate-the-molarity-of-a-sulfuric-acid-solution-containing-24-4g-of-sulfuric-acid-in-198g-of-water\/","title":{"rendered":"Calculate the molarity of a sulfuric acid solution containing 24.4g of sulfuric acid in 198g of water"},"content":{"rendered":"\n<p>Calculate the molarity of a sulfuric acid solution containing 24.4g of sulfuric acid in 198g of water. The molar mass of sulfuric acid is 98.09<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the <strong>molarity (M)<\/strong> of a sulfuric acid solution, we need to know the number of <strong>moles of solute<\/strong> (sulfuric acid, H\u2082SO\u2084) and the <strong>volume of the solution in liters<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Calculate moles of sulfuric acid<\/h3>\n\n\n\n<p>Given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of sulfuric acid = 24.4 g<\/li>\n\n\n\n<li>Molar mass of sulfuric acid (H\u2082SO\u2084) = 98.09 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Moles&nbsp;of&nbsp;H\u2082SO\u2084=massmolar&nbsp;mass=24.4&nbsp;g98.09&nbsp;g\/mol\u22480.249&nbsp;mol\\text{Moles of H\u2082SO\u2084} = \\frac{\\text{mass}}{\\text{molar mass}} = \\frac{24.4 \\text{ g}}{98.09 \\text{ g\/mol}} \\approx 0.249 \\text{ mol}Moles&nbsp;of&nbsp;H\u2082SO\u2084=molar&nbsp;massmass\u200b=98.09&nbsp;g\/mol24.4&nbsp;g\u200b\u22480.249&nbsp;mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Estimate volume of solution in liters<\/h3>\n\n\n\n<p>We are given the mass of water, not the volume of the entire solution. However, since this is a dilute aqueous solution, we can assume the <strong>density<\/strong> of water is approximately <strong>1.00 g\/mL<\/strong>. The mass of water is 198 g, which is about <strong>198 mL<\/strong> of water. After adding sulfuric acid (24.4 g), the <strong>total mass<\/strong> is 222.4 g.<\/p>\n\n\n\n<p>Assuming the final volume is roughly equivalent to its mass (reasonable for dilute solutions), the <strong>volume of the solution is about 222.4 mL<\/strong>, which is:222.4&nbsp;mL=0.2224&nbsp;L222.4 \\text{ mL} = 0.2224 \\text{ L}222.4&nbsp;mL=0.2224&nbsp;L<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate molarity<\/h3>\n\n\n\n<p>Molarity&nbsp;(M)=moles&nbsp;of&nbsp;soluteliters&nbsp;of&nbsp;solution=0.2490.2224\u22481.12&nbsp;M\\text{Molarity (M)} = \\frac{\\text{moles of solute}}{\\text{liters of solution}} = \\frac{0.249}{0.2224} \\approx 1.12 \\text{ M}Molarity&nbsp;(M)=liters&nbsp;of&nbsp;solutionmoles&nbsp;of&nbsp;solute\u200b=0.22240.249\u200b\u22481.12&nbsp;M<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>The molarity of the sulfuric acid solution is <strong>1.12 M<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>Molarity is a unit that expresses the concentration of a solution. It is defined as the number of moles of solute per liter of solution. In this question, sulfuric acid is the solute and water is the solvent. The problem provides the mass of sulfuric acid and water. To determine molarity, the number of moles of sulfuric acid is calculated first using its molar mass. The molar mass of sulfuric acid is 98.09 grams per mole. Dividing the mass of sulfuric acid, 24.4 grams, by its molar mass gives approximately 0.249 moles.<\/p>\n\n\n\n<p>The next step involves estimating the volume of the solution. Since the density of water is approximately 1 gram per milliliter, 198 grams of water is estimated to be 198 milliliters. Adding the 24.4 grams of sulfuric acid increases the total mass to about 222.4 grams. In dilute solutions like this, we can assume the final volume is close to the mass in milliliters, making the volume about 222.4 milliliters, or 0.2224 liters.<\/p>\n\n\n\n<p>Finally, molarity is found by dividing the moles of sulfuric acid (0.249) by the volume of the solution in liters (0.2224). This gives a result of approximately 1.12 molar. This means that each liter of the solution contains 1.12 moles of sulfuric acid. Understanding how to calculate molarity is important in chemistry because it allows chemists to prepare and work with solutions of known concentration, which is essential in reactions and laboratory experiments.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-344.jpeg\" alt=\"\" class=\"wp-image-31521\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-344.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-344-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-344-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the molarity of a sulfuric acid solution containing 24.4g of sulfuric acid in 198g of water. The molar mass of sulfuric acid is 98.09 The Correct Answer and Explanation is: To calculate the molarity (M) of a sulfuric acid solution, we need to know the number of moles of solute (sulfuric acid, H\u2082SO\u2084) and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-31520","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31520","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=31520"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31520\/revisions"}],"predecessor-version":[{"id":31522,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31520\/revisions\/31522"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=31520"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=31520"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=31520"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}