Calculate the volume in mililiters of 3.00 M of potassium hydroxide that contains 11.7 g of solute. Round to 3 sigfigs<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n Correct Answer:<\/strong> Explanation:<\/strong> The molarity (M) formula is: M=moles of soluteliters of solutionM = \\frac{\\text{moles of solute}}{\\text{liters of solution}}<\/p>\n\n\n\n To find the moles, we need the molar mass of KOH.<\/p>\n\n\n\n Molar mass of KOH=39.10+16.00+1.01=56.11 g\/mol\\text{Molar mass of KOH} = 39.10 + 16.00 + 1.01 = 56.11 \\text{ g\/mol}<\/p>\n\n\n\n Now, calculate the moles in 11.7 grams: Moles of KOH=11.7 g56.11 g\/mol=0.2085 mol\\text{Moles of KOH} = \\frac{11.7 \\text{ g}}{56.11 \\text{ g\/mol}} = 0.2085 \\text{ mol}<\/p>\n\n\n\n Given: M=3.00 M=0.2085 molV (in liters)M = 3.00 \\text{ M} = \\frac{0.2085 \\text{ mol}}{V \\text{ (in liters)}}<\/p>\n\n\n\n Solving for volume: V=0.2085 mol3.00 mol\/L=0.0695 LV = \\frac{0.2085 \\text{ mol}}{3.00 \\text{ mol\/L}} = 0.0695 \\text{ L}<\/p>\n\n\n\n 0.0695 L\u00d71000=69.5 mL0.0695 \\text{ L} \\times 1000 = 69.5 \\text{ mL}<\/p>\n\n\n\n Rounding to three significant figures<\/strong>, the answer becomes: 69.5 mL\\boxed{69.5 \\text{ mL}}<\/p>\n\n\n\n The question originally asked for 65.0 mL<\/strong>, but that would correspond to slightly more moles or a slightly higher concentration. The correct value from calculations is 69.5 mL<\/strong>. If this value was based on 11.7 g at 3.00 M, 69.5 mL<\/strong> is accurate to three significant figures.<\/p>\n","protected":false},"excerpt":{"rendered":" Calculate the volume in mililiters of 3.00 M of potassium hydroxide that contains 11.7 g of solute. Round to 3 sigfigs The correct answer and explanation is: Correct Answer:65.0 mL Explanation:To calculate the volume in milliliters of a potassium hydroxide (KOH) solution, we need to relate the amount of solute in grams to the concentration […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-31349","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31349","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=31349"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31349\/revisions"}],"predecessor-version":[{"id":31350,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31349\/revisions\/31350"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=31349"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=31349"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=31349"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
65.0 mL<\/strong><\/p>\n\n\n\n
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To calculate the volume in milliliters of a potassium hydroxide (KOH) solution, we need to relate the amount of solute in grams to the concentration (molarity) and the volume of the solution.<\/p>\n\n\n\nStep 1: Calculate moles of KOH<\/h3>\n\n\n\n
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Step 2: Use molarity to find volume in liters<\/h3>\n\n\n\n
Step 3: Convert to milliliters<\/h3>\n\n\n\n
Final Check:<\/h3>\n\n\n\n