{"id":31261,"date":"2025-06-21T22:51:36","date_gmt":"2025-06-21T22:51:36","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=31261"},"modified":"2025-06-21T22:51:37","modified_gmt":"2025-06-21T22:51:37","slug":"what-is-the-line-botation-and-overall-balanced-reaction-of-cr-cr2-co2-and-co","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-line-botation-and-overall-balanced-reaction-of-cr-cr2-co2-and-co\/","title":{"rendered":"what is the line botation and overall balanced reaction of Cr, Cr2 ,Co2 ,and Co"},"content":{"rendered":"\n<p>what is the line botation and overall balanced reaction of Cr, Cr2 ,Co2 ,and Co<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer:<\/h3>\n\n\n\n<p><strong>Half-reactions (line notation):<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cr \u2192 Cr\u00b3\u207a + 3e\u207b<\/strong><\/li>\n\n\n\n<li><strong>Cr\u2082O\u2087\u00b2\u207b + 14H\u207a + 6e\u207b \u2192 2Cr\u00b3\u207a + 7H\u2082O<\/strong><\/li>\n\n\n\n<li><strong>Co\u00b2\u207a + 2e\u207b \u2192 Co<\/strong><\/li>\n\n\n\n<li><strong>Co \u2192 Co\u00b2\u207a + 2e\u207b<\/strong><\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Overall Balanced Redox Reaction:<\/h3>\n\n\n\n<p>To write the overall redox reaction, we combine the oxidation and reduction half-reactions in a balanced way. Here is a typical redox reaction involving <strong>Cr\u2082O\u2087\u00b2\u207b (oxidizing agent)<\/strong> and <strong>Co (reducing agent)<\/strong>:<\/p>\n\n\n\n<p><strong>Cr\u2082O\u2087\u00b2\u207b + 14H\u207a + 6Co \u2192 2Cr\u00b3\u207a + 6Co\u00b2\u207a + 7H\u2082O<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">300-Word Explanation:<\/h3>\n\n\n\n<p>This redox reaction involves chromium and cobalt in different oxidation states. Chromium in the dichromate ion (Cr\u2082O\u2087\u00b2\u207b) acts as an oxidizing agent and is reduced to Cr\u00b3\u207a. Cobalt metal (Co), on the other hand, acts as a reducing agent and is oxidized to Co\u00b2\u207a.<\/p>\n\n\n\n<p>In acidic solution, dichromate (Cr\u2082O\u2087\u00b2\u207b) accepts electrons and is reduced:<\/p>\n\n\n\n<p><strong>Cr\u2082O\u2087\u00b2\u207b + 14H\u207a + 6e\u207b \u2192 2Cr\u00b3\u207a + 7H\u2082O<\/strong><\/p>\n\n\n\n<p>This half-reaction shows chromium going from +6 in Cr\u2082O\u2087\u00b2\u207b to +3 in Cr\u00b3\u207a. It consumes hydrogen ions (H\u207a) and produces water.<\/p>\n\n\n\n<p>The cobalt metal is oxidized:<\/p>\n\n\n\n<p><strong>Co \u2192 Co\u00b2\u207a + 2e\u207b<\/strong><\/p>\n\n\n\n<p>To balance the overall reaction, we need equal numbers of electrons in the oxidation and reduction half-reactions. The chromium half-reaction involves 6 electrons, so we need 3 cobalt atoms to provide 6 electrons:<\/p>\n\n\n\n<p><strong>3Co \u2192 3Co\u00b2\u207a + 6e\u207b<\/strong><\/p>\n\n\n\n<p>Now combine:<\/p>\n\n\n\n<p><strong>Cr\u2082O\u2087\u00b2\u207b + 14H\u207a + 3Co \u2192 2Cr\u00b3\u207a + 3Co\u00b2\u207a + 7H\u2082O<\/strong><\/p>\n\n\n\n<p>This balanced equation satisfies both mass and charge conservation. The total charge on both sides is equal: on the left, we have 2\u207b (from Cr\u2082O\u2087\u00b2\u207b) plus 14\u207a (from H\u207a) equals 12\u207a; on the right, 2Cr\u00b3\u207a and 3Co\u00b2\u207a also equal 12\u207a.<\/p>\n\n\n\n<p>Redox reactions like this are important in electrochemistry and corrosion science. They also have real-world uses in industrial processes and batteries.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>what is the line botation and overall balanced reaction of Cr, Cr2 ,Co2 ,and Co The correct answer and explanation is: Correct Answer: Half-reactions (line notation): Overall Balanced Redox Reaction: To write the overall redox reaction, we combine the oxidation and reduction half-reactions in a balanced way. Here is a typical redox reaction involving Cr\u2082O\u2087\u00b2\u207b [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-31261","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31261","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=31261"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31261\/revisions"}],"predecessor-version":[{"id":31262,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31261\/revisions\/31262"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=31261"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=31261"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=31261"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}