{"id":31235,"date":"2025-06-21T22:42:01","date_gmt":"2025-06-21T22:42:01","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=31235"},"modified":"2025-06-21T22:42:08","modified_gmt":"2025-06-21T22:42:08","slug":"how-many-mol-of-carbon-are-in-30-7-g-of-potassium-cyanide","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-mol-of-carbon-are-in-30-7-g-of-potassium-cyanide\/","title":{"rendered":"How many mol of carbon are in 30.7 g of potassium cyanide"},"content":{"rendered":"\n<p>How many mol of carbon are in 30.7 g of potassium cyanide?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><br><strong>0.470 mol of carbon<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><br>To determine the number of moles of carbon in 30.7 grams of potassium cyanide (KCN), follow these steps:<\/p>\n\n\n\n<p><strong>Step 1: Determine the molar mass of KCN<\/strong><br>KCN contains three elements:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Potassium (K): 39.10 g\/mol<\/li>\n\n\n\n<li>Carbon (C): 12.01 g\/mol<\/li>\n\n\n\n<li>Nitrogen (N): 14.01 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Add the atomic masses:<br>39.10 + 12.01 + 14.01 = <strong>65.12 g\/mol<\/strong><\/p>\n\n\n\n<p>So, the molar mass of potassium cyanide is <strong>65.12 g\/mol<\/strong>.<\/p>\n\n\n\n<p><strong>Step 2: Calculate the number of moles of KCN in 30.7 g<\/strong><br>Use the formula: moles&nbsp;of&nbsp;KCN=massmolar&nbsp;mass=30.7\u2009g65.12\u2009g\/mol\u22480.4716\u2009mol\\text{moles of KCN} = \\frac{\\text{mass}}{\\text{molar mass}} = \\frac{30.7\\, \\text{g}}{65.12\\, \\text{g\/mol}} \\approx 0.4716\\, \\text{mol}<\/p>\n\n\n\n<p><strong>Step 3: Use mole ratio to find moles of carbon<\/strong><br>Each formula unit of KCN contains <strong>1 atom of carbon<\/strong>. That means the number of moles of KCN is equal to the number of moles of carbon in the sample.<\/p>\n\n\n\n<p>So, the number of moles of carbon = <strong>0.4716 mol<\/strong><\/p>\n\n\n\n<p>Rounded to three significant figures, the final answer is:<\/p>\n\n\n\n<p><strong>0.470 mol of carbon<\/strong><\/p>\n\n\n\n<p><strong>Why this works:<\/strong><br>The molar mass of a compound allows conversion between mass and moles. Once the number of moles of the compound is known, the mole ratio from the chemical formula is used to determine how many moles of a specific element are present. Since KCN contains one carbon atom per molecule, the number of moles of KCN equals the number of moles of carbon atoms.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>How many mol of carbon are in 30.7 g of potassium cyanide? The correct answer and explanation is: Correct Answer:0.470 mol of carbon Explanation:To determine the number of moles of carbon in 30.7 grams of potassium cyanide (KCN), follow these steps: Step 1: Determine the molar mass of KCNKCN contains three elements: Add the atomic [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-31235","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31235","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=31235"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31235\/revisions"}],"predecessor-version":[{"id":31236,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31235\/revisions\/31236"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=31235"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=31235"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=31235"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}