{"id":31198,"date":"2025-06-21T22:26:59","date_gmt":"2025-06-21T22:26:59","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=31198"},"modified":"2025-06-21T22:27:04","modified_gmt":"2025-06-21T22:27:04","slug":"which-of-the-following-compounds-are-nonpolar","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-of-the-following-compounds-are-nonpolar\/","title":{"rendered":"Which of the following compounds are nonpolar"},"content":{"rendered":"\n<p>Which of the following compounds are nonpolar? 1) 3-methyl-2-hexanone 2) propanal 3) pentane 4) 2,3-dimethylhexane 5) 2-butanamine<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The nonpolar compounds from the list are:<\/p>\n\n\n\n<ol start=\"3\" class=\"wp-block-list\">\n<li>Pentane<\/li>\n\n\n\n<li>2,3-Dimethylhexane<\/li>\n<\/ol>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>Polarity of a compound depends largely on the presence of polar bonds (such as C=O, N-H, O-H) and the overall molecular geometry, which can either reinforce or cancel dipole moments.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>3-methyl-2-hexanone<\/strong> is a ketone. It contains a carbonyl group (C=O), which is highly polar because oxygen is much more electronegative than carbon. This polar group gives the molecule a significant dipole moment, making it polar.<\/li>\n\n\n\n<li><strong>Propanal<\/strong> is an aldehyde with a carbonyl group (C=O) at the end of the chain. Like ketones, aldehydes have a strong dipole due to the carbonyl group, so propanal is polar.<\/li>\n\n\n\n<li><strong>Pentane<\/strong> is a straight-chain alkane with only carbon and hydrogen atoms connected by nonpolar C\u2013C and C\u2013H bonds. Alkanes are generally nonpolar because the electronegativity difference between carbon and hydrogen is very small, and the molecule is symmetrical enough to have no net dipole moment.<\/li>\n\n\n\n<li><strong>2,3-Dimethylhexane<\/strong> is a branched alkane, also consisting only of carbon and hydrogen atoms. Like pentane, it is nonpolar for the same reasons: mainly nonpolar bonds and no polar functional groups.<\/li>\n\n\n\n<li><strong>2-Butanamine<\/strong> contains an amine group (-NH2), which has a nitrogen atom bonded to hydrogens. Nitrogen is more electronegative than carbon or hydrogen, creating a polar N-H bond. This makes 2-butanamine polar because of the amine group&#8217;s dipole.<\/li>\n<\/ol>\n\n\n\n<p>In summary, compounds without strongly electronegative atoms bonded to carbon or hydrogen and without polar functional groups are generally nonpolar. This is true for pentane and 2,3-dimethylhexane, both alkanes, making them nonpolar compounds on the list.<\/p>\n\n\n\n<p><a href=\"https:\/\/www.numerade.com\/ask\/question\/which-of-the-following-compounds-are-nonpolar-1-3-methyl-2-hexanone-2-propanal-3-pentane-4-23-dimethylhexane-5-2-butanamine\/\" target=\"_blank\" rel=\"noopener\"><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which of the following compounds are nonpolar? 1) 3-methyl-2-hexanone 2) propanal 3) pentane 4) 2,3-dimethylhexane 5) 2-butanamine The correct answer and explanation is: The nonpolar compounds from the list are: Explanation: Polarity of a compound depends largely on the presence of polar bonds (such as C=O, N-H, O-H) and the overall molecular geometry, which can [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-31198","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=31198"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31198\/revisions"}],"predecessor-version":[{"id":31199,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/31198\/revisions\/31199"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=31198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=31198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=31198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}