Correct Answer:<\/strong><\/p>\n\n\n\n a. The woman\u2019s genotype: X\u1d9cX\u1d9c<\/strong> Red-green colorblindness is caused by a gene located on the X chromosome. It is a recessive disorder, meaning a person must inherit two copies of the defective gene (if female) or one copy (if male) to be colorblind.<\/p>\n\n\n\n a.<\/strong> Since the woman is colorblind and this is an X-linked recessive trait, she must carry two defective X chromosomes. Therefore, her genotype is X\u1d9cX\u1d9c<\/strong> (where X\u1d9c represents the X chromosome with the colorblind gene).<\/p>\n\n\n\n b.<\/strong> The man has normal vision and is male. Males only have one X chromosome and one Y chromosome. Since he is not colorblind, his genotype is XY<\/strong> (with a normal X chromosome).<\/p>\n\n\n\n Now, we use a Punnett square to determine the possible genotypes of their children.<\/p>\n\n\n\n From the Punnett square:<\/p>\n\n\n\n This couple will not have any daughters who are colorblind, but all daughters will be carriers. There is a 2\/4 (or 50%) chance<\/strong> that a child will be a colorblind son. The key factor is that the mother passes on an X\u1d9c to every child, while the father determines the sex of the baby through the contribution of either an X or a Y.<\/p>\n\n\n\n Red-Green colorblindness is a X linked recessive disorder. A woman who is colorblind marries a man with normal vision. a. how would you write the woman\u2019s genotype? b. How would you write the man\u2019s genotype? c. Conduct a Punnett square to determine the chances that the couple has a son who is colorblind. Write the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-30820","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/30820","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=30820"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/30820\/revisions"}],"predecessor-version":[{"id":30846,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/30820\/revisions\/30846"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=30820"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=30820"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=30820"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
b. The man\u2019s genotype: XY<\/strong>
c. Chance of a colorblind son:<\/strong> 2\/4<\/strong>
d. Chance of a colorblind daughter:<\/strong> 0\/4<\/strong><\/p>\n\n\n\n
\n\n\n\nExplanation<\/strong><\/h3>\n\n\n\n
Punnett Square:<\/strong><\/h3>\n\n\n\n
<\/th> X (male)<\/th> Y (male)<\/th><\/tr><\/thead> X\u1d9c (female)<\/td> X\u1d9cX<\/td> X\u1d9cY<\/td><\/tr> X\u1d9c (female)<\/td> X\u1d9cX<\/td> X\u1d9cY<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n \n
\n
So, 2 out of 2 sons<\/strong> are colorblind \u2192 2\/4<\/strong> total probability.<\/li>\n<\/ul>\n<\/li>\n\n\n\n\n
So, 0 out of 2 daughters<\/strong> are colorblind \u2192 0\/4<\/strong> total probability.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\nConclusion:<\/strong><\/h3>\n\n\n\n
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