{"id":30663,"date":"2025-06-21T19:29:21","date_gmt":"2025-06-21T19:29:21","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=30663"},"modified":"2025-06-21T19:29:22","modified_gmt":"2025-06-21T19:29:22","slug":"which-statement-is-correct","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-statement-is-correct\/","title":{"rendered":"Which statement is correct"},"content":{"rendered":"\n<p> Which statement is correct? A) If K &lt; 1, ?G\u00b0 is negative then the reaction is product favored. B) If K > 1, ?G\u00b0 is positive then the reaction is product favored C) If K > 1, ?G\u00b0 is negative then the reaction is product favored. D) If K > 1, ?G\u00b0 is negative then the reaction is reactant favored.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>C) If K &gt; 1, \u0394G\u00b0 is negative then the reaction is product favored.<\/strong><\/p>\n\n\n\n<p>To understand why this is true, we need to look at the relationship between the equilibrium constant <strong>K<\/strong> and the standard Gibbs free energy change <strong>\u0394G\u00b0<\/strong>. This relationship is governed by the equation:<\/p>\n\n\n\n<p>\u0394G\u00b0=\u2212RTln\u2061K\u0394G\u00b0 = -RT \\ln K<\/p>\n\n\n\n<p>where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>\u0394G\u00b0<\/strong> is the standard Gibbs free energy change,<\/li>\n\n\n\n<li><strong>R<\/strong> is the gas constant (8.314 J\/mol\u00b7K),<\/li>\n\n\n\n<li><strong>T<\/strong> is the temperature in Kelvin,<\/li>\n\n\n\n<li><strong>K<\/strong> is the equilibrium constant.<\/li>\n<\/ul>\n\n\n\n<p>If <strong>K &gt; 1<\/strong>, then <strong>ln K<\/strong> is positive. Because the equation has a negative sign in front of <strong>RT ln K<\/strong>, this makes <strong>\u0394G\u00b0 negative<\/strong>. A negative <strong>\u0394G\u00b0<\/strong> indicates that the reaction is spontaneous under standard conditions and that the formation of products is favored. Therefore, the equilibrium lies toward the products.<\/p>\n\n\n\n<p>Conversely, if <strong>K &lt; 1<\/strong>, then <strong>ln K<\/strong> is negative, and the value of <strong>\u0394G\u00b0<\/strong> becomes positive. This suggests the reaction is nonspontaneous under standard conditions, so the equilibrium lies toward the reactants.<\/p>\n\n\n\n<p>Options A, B, and D are incorrect for the following reasons:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A<\/strong> says that <strong>K &lt; 1<\/strong> and <strong>\u0394G\u00b0 is negative<\/strong>, which is inconsistent with the equation. If <strong>K &lt; 1<\/strong>, <strong>\u0394G\u00b0<\/strong> must be positive.<\/li>\n\n\n\n<li><strong>B<\/strong> claims <strong>K > 1<\/strong> and <strong>\u0394G\u00b0 is positive<\/strong>, which again contradicts the mathematical relationship.<\/li>\n\n\n\n<li><strong>D<\/strong> suggests that even with <strong>K > 1<\/strong> and <strong>\u0394G\u00b0 negative<\/strong>, the reaction is reactant favored, which is backwards.<\/li>\n<\/ul>\n\n\n\n<p>In summary, when <strong>K &gt; 1<\/strong>, more products are present at equilibrium, and a <strong>negative \u0394G\u00b0<\/strong> confirms that the forward reaction is spontaneous and product favored.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"722\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-196.jpeg\" alt=\"\" class=\"wp-image-30664\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-196.jpeg 722w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-196-212x300.jpeg 212w\" sizes=\"auto, (max-width: 722px) 100vw, 722px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Which statement is correct? A) If K &lt; 1, ?G\u00b0 is negative then the reaction is product favored. B) If K > 1, ?G\u00b0 is positive then the reaction is product favored C) If K > 1, ?G\u00b0 is negative then the reaction is product favored. D) If K > 1, ?G\u00b0 is negative then [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-30663","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/30663","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=30663"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/30663\/revisions"}],"predecessor-version":[{"id":30665,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/30663\/revisions\/30665"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=30663"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=30663"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=30663"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}