Here’s the complete answer and explanation for the ions you’ve listed: Cd\u207a, Au\u207a, Mo\u00b3\u207a, and Zr\u207a.<\/p>\n\n\n\n
1. Cd\u207a (Cadmium ion)<\/strong><\/h3>\n\n\n\nAtomic number of Cd: 48<\/strong> Neutral Cd configuration<\/strong>: [Kr] 4d\u00b9\u2070 5s\u00b2 Cd\u207a configuration<\/strong>: [Kr] 4d\u00b9\u2070 5s\u00b9 Orbital diagram<\/strong> (valence shell only): 4d: \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 5s: \u2191 Unpaired electrons<\/strong>: 1 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\n2. Au\u207a (Gold ion)<\/strong><\/h3>\n\n\n\nAtomic number of Au: 79<\/strong> Neutral Au configuration<\/strong>: [Xe] 4f\u00b9\u2074 5d\u00b9\u2070 6s\u00b9 Au\u207a configuration<\/strong>: [Xe] 4f\u00b9\u2074 5d\u00b9\u2070 Orbital diagram<\/strong> (valence shell only): 5d: \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 Unpaired electrons<\/strong>: 0 Magnetism<\/strong>: Diamagnetic<\/strong><\/p>\n\n\n\n3. Mo\u00b3\u207a (Molybdenum ion)<\/strong><\/h3>\n\n\n\nAtomic number of Mo: 42<\/strong> Neutral Mo configuration<\/strong>: [Kr] 4d\u2075 5s\u00b9 Mo\u00b3\u207a configuration<\/strong>: [Kr] 4d\u00b3 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\n4. Zr\u207a (Zirconium ion)<\/strong><\/h3>\n\n\n\nAtomic number of Zr: 40<\/strong> Neutral Zr configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b2 Zr\u207a configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b9 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 5s: \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\nExplanation <\/h3>\n\n\n\n
Magnetism in transition metal ions hinges on the presence of unpaired electrons in their d or s orbitals. Ions with all electrons paired exhibit diamagnetism<\/strong>, meaning they are weakly repelled by magnetic fields. In contrast, ions with one or more unpaired electrons exhibit paramagnetism<\/strong>, meaning they are attracted by magnetic fields due to their net magnetic moment.<\/p>\n\n\n\nCd\u207a<\/strong>, having lost only one electron, retains the [Kr] 4d\u00b9\u2070 5s\u00b9 configuration. The single 5s electron remains unpaired, making Cd\u207a paramagnetic.<\/p>\n\n\n\nAu\u207a<\/strong> is unusual. Neutral gold has a filled 5d shell and one 6s electron. Upon losing the 6s\u00b9 electron to become Au\u207a, the resulting 5d\u00b9\u2070 is fully filled. No unpaired electrons remain, hence Au\u207a is diamagnetic.<\/p>\n\n\n\nMo\u00b3\u207a<\/strong> arises when Mo loses its two 5s and one 4d electron. The resulting 4d\u00b3 configuration includes three unpaired electrons, firmly qualifying Mo\u00b3\u207a as paramagnetic.<\/p>\n\n\n\nZr\u207a<\/strong> loses one electron, typically from the 5s orbital first, resulting in 4d\u00b2 5s\u00b9. Both 4d and 5s orbitals contain unpaired electrons. Zr\u207a thus has three unpaired electrons, making it paramagnetic.<\/p>\n\n\n\nThis analysis underscores the importance of electron configuration in predicting chemical and physical behavior, particularly for ions of transition metals. Understanding how orbital occupancy changes with ionization is vital to determining an ion’s magnetic character.<\/p>\n\n\n\n![\"\"](\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-170.jpeg\")
<\/figure>\n","protected":false},"excerpt":{"rendered":"‘Write the full electron configuration and orbital diagram for each ion and indicate whether it is diamagnetic or paramagnetic (10 pts): Cdl+ b. Aut Mo3+ d. Zrt’ The Correct Answer and Explanation is: Here’s the complete answer and explanation for the ions you’ve listed: Cd\u207a, Au\u207a, Mo\u00b3\u207a, and Zr\u207a. 1. Cd\u207a (Cadmium ion) Atomic number […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-29925","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=29925"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions"}],"predecessor-version":[{"id":29927,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions\/29927"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=29925"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=29925"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=29925"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
2. Au\u207a (Gold ion)<\/strong><\/h3>\n\n\n\nAtomic number of Au: 79<\/strong> Neutral Au configuration<\/strong>: [Xe] 4f\u00b9\u2074 5d\u00b9\u2070 6s\u00b9 Au\u207a configuration<\/strong>: [Xe] 4f\u00b9\u2074 5d\u00b9\u2070 Orbital diagram<\/strong> (valence shell only): 5d: \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 \u2191\u2193 Unpaired electrons<\/strong>: 0 Magnetism<\/strong>: Diamagnetic<\/strong><\/p>\n\n\n\n3. Mo\u00b3\u207a (Molybdenum ion)<\/strong><\/h3>\n\n\n\nAtomic number of Mo: 42<\/strong> Neutral Mo configuration<\/strong>: [Kr] 4d\u2075 5s\u00b9 Mo\u00b3\u207a configuration<\/strong>: [Kr] 4d\u00b3 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\n4. Zr\u207a (Zirconium ion)<\/strong><\/h3>\n\n\n\nAtomic number of Zr: 40<\/strong> Neutral Zr configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b2 Zr\u207a configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b9 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 5s: \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\nExplanation <\/h3>\n\n\n\n
Magnetism in transition metal ions hinges on the presence of unpaired electrons in their d or s orbitals. Ions with all electrons paired exhibit diamagnetism<\/strong>, meaning they are weakly repelled by magnetic fields. In contrast, ions with one or more unpaired electrons exhibit paramagnetism<\/strong>, meaning they are attracted by magnetic fields due to their net magnetic moment.<\/p>\n\n\n\nCd\u207a<\/strong>, having lost only one electron, retains the [Kr] 4d\u00b9\u2070 5s\u00b9 configuration. The single 5s electron remains unpaired, making Cd\u207a paramagnetic.<\/p>\n\n\n\nAu\u207a<\/strong> is unusual. Neutral gold has a filled 5d shell and one 6s electron. Upon losing the 6s\u00b9 electron to become Au\u207a, the resulting 5d\u00b9\u2070 is fully filled. No unpaired electrons remain, hence Au\u207a is diamagnetic.<\/p>\n\n\n\nMo\u00b3\u207a<\/strong> arises when Mo loses its two 5s and one 4d electron. The resulting 4d\u00b3 configuration includes three unpaired electrons, firmly qualifying Mo\u00b3\u207a as paramagnetic.<\/p>\n\n\n\nZr\u207a<\/strong> loses one electron, typically from the 5s orbital first, resulting in 4d\u00b2 5s\u00b9. Both 4d and 5s orbitals contain unpaired electrons. Zr\u207a thus has three unpaired electrons, making it paramagnetic.<\/p>\n\n\n\nThis analysis underscores the importance of electron configuration in predicting chemical and physical behavior, particularly for ions of transition metals. Understanding how orbital occupancy changes with ionization is vital to determining an ion’s magnetic character.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"‘Write the full electron configuration and orbital diagram for each ion and indicate whether it is diamagnetic or paramagnetic (10 pts): Cdl+ b. Aut Mo3+ d. Zrt’ The Correct Answer and Explanation is: Here’s the complete answer and explanation for the ions you’ve listed: Cd\u207a, Au\u207a, Mo\u00b3\u207a, and Zr\u207a. 1. Cd\u207a (Cadmium ion) Atomic number […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-29925","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=29925"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions"}],"predecessor-version":[{"id":29927,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions\/29927"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=29925"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=29925"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=29925"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
3. Mo\u00b3\u207a (Molybdenum ion)<\/strong><\/h3>\n\n\n\nAtomic number of Mo: 42<\/strong> Neutral Mo configuration<\/strong>: [Kr] 4d\u2075 5s\u00b9 Mo\u00b3\u207a configuration<\/strong>: [Kr] 4d\u00b3 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\n4. Zr\u207a (Zirconium ion)<\/strong><\/h3>\n\n\n\nAtomic number of Zr: 40<\/strong> Neutral Zr configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b2 Zr\u207a configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b9 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 5s: \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\nExplanation <\/h3>\n\n\n\n
Magnetism in transition metal ions hinges on the presence of unpaired electrons in their d or s orbitals. Ions with all electrons paired exhibit diamagnetism<\/strong>, meaning they are weakly repelled by magnetic fields. In contrast, ions with one or more unpaired electrons exhibit paramagnetism<\/strong>, meaning they are attracted by magnetic fields due to their net magnetic moment.<\/p>\n\n\n\nCd\u207a<\/strong>, having lost only one electron, retains the [Kr] 4d\u00b9\u2070 5s\u00b9 configuration. The single 5s electron remains unpaired, making Cd\u207a paramagnetic.<\/p>\n\n\n\nAu\u207a<\/strong> is unusual. Neutral gold has a filled 5d shell and one 6s electron. Upon losing the 6s\u00b9 electron to become Au\u207a, the resulting 5d\u00b9\u2070 is fully filled. No unpaired electrons remain, hence Au\u207a is diamagnetic.<\/p>\n\n\n\nMo\u00b3\u207a<\/strong> arises when Mo loses its two 5s and one 4d electron. The resulting 4d\u00b3 configuration includes three unpaired electrons, firmly qualifying Mo\u00b3\u207a as paramagnetic.<\/p>\n\n\n\nZr\u207a<\/strong> loses one electron, typically from the 5s orbital first, resulting in 4d\u00b2 5s\u00b9. Both 4d and 5s orbitals contain unpaired electrons. Zr\u207a thus has three unpaired electrons, making it paramagnetic.<\/p>\n\n\n\nThis analysis underscores the importance of electron configuration in predicting chemical and physical behavior, particularly for ions of transition metals. Understanding how orbital occupancy changes with ionization is vital to determining an ion’s magnetic character.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"‘Write the full electron configuration and orbital diagram for each ion and indicate whether it is diamagnetic or paramagnetic (10 pts): Cdl+ b. Aut Mo3+ d. Zrt’ The Correct Answer and Explanation is: Here’s the complete answer and explanation for the ions you’ve listed: Cd\u207a, Au\u207a, Mo\u00b3\u207a, and Zr\u207a. 1. Cd\u207a (Cadmium ion) Atomic number […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-29925","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=29925"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions"}],"predecessor-version":[{"id":29927,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions\/29927"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=29925"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=29925"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=29925"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
4. Zr\u207a (Zirconium ion)<\/strong><\/h3>\n\n\n\nAtomic number of Zr: 40<\/strong> Neutral Zr configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b2 Zr\u207a configuration<\/strong>: [Kr] 4d\u00b2 5s\u00b9 Orbital diagram<\/strong> (valence shell only): 4d: \u2191 \u2191 5s: \u2191 Unpaired electrons<\/strong>: 3 Magnetism<\/strong>: Paramagnetic<\/strong><\/p>\n\n\n\nExplanation <\/h3>\n\n\n\n
Magnetism in transition metal ions hinges on the presence of unpaired electrons in their d or s orbitals. Ions with all electrons paired exhibit diamagnetism<\/strong>, meaning they are weakly repelled by magnetic fields. In contrast, ions with one or more unpaired electrons exhibit paramagnetism<\/strong>, meaning they are attracted by magnetic fields due to their net magnetic moment.<\/p>\n\n\n\nCd\u207a<\/strong>, having lost only one electron, retains the [Kr] 4d\u00b9\u2070 5s\u00b9 configuration. The single 5s electron remains unpaired, making Cd\u207a paramagnetic.<\/p>\n\n\n\nAu\u207a<\/strong> is unusual. Neutral gold has a filled 5d shell and one 6s electron. Upon losing the 6s\u00b9 electron to become Au\u207a, the resulting 5d\u00b9\u2070 is fully filled. No unpaired electrons remain, hence Au\u207a is diamagnetic.<\/p>\n\n\n\nMo\u00b3\u207a<\/strong> arises when Mo loses its two 5s and one 4d electron. The resulting 4d\u00b3 configuration includes three unpaired electrons, firmly qualifying Mo\u00b3\u207a as paramagnetic.<\/p>\n\n\n\nZr\u207a<\/strong> loses one electron, typically from the 5s orbital first, resulting in 4d\u00b2 5s\u00b9. Both 4d and 5s orbitals contain unpaired electrons. Zr\u207a thus has three unpaired electrons, making it paramagnetic.<\/p>\n\n\n\nThis analysis underscores the importance of electron configuration in predicting chemical and physical behavior, particularly for ions of transition metals. Understanding how orbital occupancy changes with ionization is vital to determining an ion’s magnetic character.<\/p>\n\n\n\n<\/figure>\n","protected":false},"excerpt":{"rendered":"‘Write the full electron configuration and orbital diagram for each ion and indicate whether it is diamagnetic or paramagnetic (10 pts): Cdl+ b. Aut Mo3+ d. Zrt’ The Correct Answer and Explanation is: Here’s the complete answer and explanation for the ions you’ve listed: Cd\u207a, Au\u207a, Mo\u00b3\u207a, and Zr\u207a. 1. Cd\u207a (Cadmium ion) Atomic number […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-29925","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=29925"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions"}],"predecessor-version":[{"id":29927,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions\/29927"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=29925"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=29925"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=29925"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Explanation <\/h3>\n\n\n\n
Magnetism in transition metal ions hinges on the presence of unpaired electrons in their d or s orbitals. Ions with all electrons paired exhibit diamagnetism<\/strong>, meaning they are weakly repelled by magnetic fields. In contrast, ions with one or more unpaired electrons exhibit paramagnetism<\/strong>, meaning they are attracted by magnetic fields due to their net magnetic moment.<\/p>\n\n\n\n Cd\u207a<\/strong>, having lost only one electron, retains the [Kr] 4d\u00b9\u2070 5s\u00b9 configuration. The single 5s electron remains unpaired, making Cd\u207a paramagnetic.<\/p>\n\n\n\n Au\u207a<\/strong> is unusual. Neutral gold has a filled 5d shell and one 6s electron. Upon losing the 6s\u00b9 electron to become Au\u207a, the resulting 5d\u00b9\u2070 is fully filled. No unpaired electrons remain, hence Au\u207a is diamagnetic.<\/p>\n\n\n\n Mo\u00b3\u207a<\/strong> arises when Mo loses its two 5s and one 4d electron. The resulting 4d\u00b3 configuration includes three unpaired electrons, firmly qualifying Mo\u00b3\u207a as paramagnetic.<\/p>\n\n\n\n Zr\u207a<\/strong> loses one electron, typically from the 5s orbital first, resulting in 4d\u00b2 5s\u00b9. Both 4d and 5s orbitals contain unpaired electrons. Zr\u207a thus has three unpaired electrons, making it paramagnetic.<\/p>\n\n\n\n This analysis underscores the importance of electron configuration in predicting chemical and physical behavior, particularly for ions of transition metals. Understanding how orbital occupancy changes with ionization is vital to determining an ion’s magnetic character.<\/p>\n\n\n\n ‘Write the full electron configuration and orbital diagram for each ion and indicate whether it is diamagnetic or paramagnetic (10 pts): Cdl+ b. Aut Mo3+ d. Zrt’ The Correct Answer and Explanation is: Here’s the complete answer and explanation for the ions you’ve listed: Cd\u207a, Au\u207a, Mo\u00b3\u207a, and Zr\u207a. 1. Cd\u207a (Cadmium ion) Atomic number […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-29925","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=29925"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions"}],"predecessor-version":[{"id":29927,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29925\/revisions\/29927"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=29925"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=29925"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=29925"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}<\/figure>\n","protected":false},"excerpt":{"rendered":"