{"id":29480,"date":"2025-06-21T05:02:12","date_gmt":"2025-06-21T05:02:12","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=29480"},"modified":"2025-06-21T05:02:14","modified_gmt":"2025-06-21T05:02:14","slug":"assuming-equal-concentrations-and-complete-dissociation-arrange-these-aqueous-solutions-by-their-freezing-points_","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/assuming-equal-concentrations-and-complete-dissociation-arrange-these-aqueous-solutions-by-their-freezing-points_\/","title":{"rendered":"Assuming equal concentrations and complete dissociation, arrange these aqueous solutions by their freezing points_"},"content":{"rendered":"\n

Assuming equal concentrations and complete dissociation, arrange these aqueous solutions by their freezing points_ Highest freezing point NHABr Na;” PO4 LizSO Lowest freezing point<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

To determine the correct order of freezing points for the aqueous solutions given, we need to understand freezing point depression<\/strong>, a colligative property. This property depends on the number of particles the solute produces in solution and not on their identity. The more particles present in solution, the lower the freezing point will be.<\/p>\n\n\n\n

Each compound dissociates in water as follows:<\/p>\n\n\n\n

    \n
  1. NH\u2084Br<\/strong> \u2192 NH\u2084\u207a + Br\u207b (2 ions)<\/li>\n\n\n\n
  2. Na\u2083PO\u2084<\/strong> \u2192 3Na\u207a + PO\u2084\u00b3\u207b (4 ions)<\/li>\n\n\n\n
  3. Li\u2082SO\u2084<\/strong> \u2192 2Li\u207a + SO\u2084\u00b2\u207b (3 ions)<\/li>\n<\/ol>\n\n\n\n

    Now, we apply the concept of van\u2019t Hoff factor (i)<\/strong> which represents the number of particles into which a compound dissociates in solution:<\/p>\n\n\n\n

      \n
    • NH\u2084Br has i = 2<\/li>\n\n\n\n
    • Li\u2082SO\u2084 has i = 3<\/li>\n\n\n\n
    • Na\u2083PO\u2084 has i = 4<\/li>\n<\/ul>\n\n\n\n

      According to the formula for freezing point depression: \u0394Tf=i\u22c5Kf\u22c5m\\Delta T_f = i \\cdot K_f \\cdot m\u0394Tf\u200b=i\u22c5Kf\u200b\u22c5m<\/p>\n\n\n\n

      Where:<\/p>\n\n\n\n

        \n
      • \u0394T\u2093 is the freezing point depression<\/li>\n\n\n\n
      • i is the van\u2019t Hoff factor<\/li>\n\n\n\n
      • Kf is the cryoscopic constant (same for all as water is the solvent)<\/li>\n\n\n\n
      • m is the molality (same for all solutions as given)<\/li>\n<\/ul>\n\n\n\n

        Therefore, the more ions a solute produces, the lower the freezing point of the solution.<\/p>\n\n\n\n

        Conclusion:<\/h3>\n\n\n\n
          \n
        • NH\u2084Br<\/strong> produces the fewest particles, so it will have the highest freezing point<\/strong><\/li>\n\n\n\n
        • Li\u2082SO\u2084<\/strong> produces more particles than NH\u2084Br but fewer than Na\u2083PO\u2084, so it is in the middle<\/strong><\/li>\n\n\n\n
        • Na\u2083PO\u2084<\/strong> produces the most particles, leading to the lowest freezing point<\/strong><\/li>\n<\/ul>\n\n\n\n

          Correct Order:<\/h3>\n\n\n\n

          Highest freezing point<\/strong>: NH\u2084Br
          Middle<\/strong>: Li\u2082SO\u2084
          Lowest freezing point<\/strong>: Na\u2083PO\u2084<\/p>\n\n\n\n

          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          Assuming equal concentrations and complete dissociation, arrange these aqueous solutions by their freezing points_ Highest freezing point NHABr Na;” PO4 LizSO Lowest freezing point The Correct Answer and Explanation is: To determine the correct order of freezing points for the aqueous solutions given, we need to understand freezing point depression, a colligative property. This property […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-29480","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29480","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=29480"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29480\/revisions"}],"predecessor-version":[{"id":29483,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/29480\/revisions\/29483"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=29480"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=29480"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=29480"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}