{"id":27429,"date":"2025-06-19T22:48:14","date_gmt":"2025-06-19T22:48:14","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=27429"},"modified":"2025-06-19T22:48:15","modified_gmt":"2025-06-19T22:48:15","slug":"what-is-the-product-of-this-reaction","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-product-of-this-reaction\/","title":{"rendered":"What is the product of this reaction"},"content":{"rendered":"\n<p>What is the product of this reaction? (Note: NaBD4 is the same as NaBH4 where the hydrogens have been replaced by deuterium) NaBD4 H2O CH3OH OH CDCH3 OD CHCH3 OD CDCH3 CH2CO2CH3 A B CH3<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: B. CDCH3<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The reagent <strong>NaBD\u2084<\/strong> (sodium borodeuteride) is a deuterated version of <strong>NaBH\u2084<\/strong> (sodium borohydride), commonly used to reduce carbonyl compounds such as aldehydes and ketones. In NaBD\u2084, the <strong>hydride (H\u207b)<\/strong> ions are replaced with <strong>deuteride (D\u207b)<\/strong> ions. This means during reduction, the <strong>D\u207b<\/strong> from NaBD\u2084 is delivered to the carbonyl carbon instead of H\u207b, leading to a product with deuterium.<\/p>\n\n\n\n<p>Let\u2019s break down the reaction step by step:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Starting Material<\/strong>: CH\u2083COCH\u2083 (acetone) is the likely substrate given the context of the product choices. Acetone is a ketone with the structure:\n<ul class=\"wp-block-list\">\n<li>CH\u2083\u2014CO\u2014CH\u2083<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Reagent<\/strong>: NaBD\u2084 in a protic solvent (e.g. H\u2082O and CH\u2083OH). NaBD\u2084 donates a deuteride ion (D\u207b), which attacks the electrophilic carbonyl carbon of acetone.<\/li>\n\n\n\n<li><strong>Mechanism<\/strong>:\n<ul class=\"wp-block-list\">\n<li>The deuteride (D\u207b) adds to the carbon of the C=O bond.<\/li>\n\n\n\n<li>The pi electrons from the C=O double bond move to the oxygen, forming an alkoxide intermediate.<\/li>\n\n\n\n<li>Protonation of the alkoxide occurs from the solvent (H\u2082O or CH\u2083OH), delivering an H\u207a (proton) to the oxygen.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Product<\/strong>: The carbonyl is reduced to a secondary alcohol, and one of the methyl groups is now bonded to a carbon bearing a D (from NaBD\u2084) and an OH (from solvent protonation). This gives:\n<ul class=\"wp-block-list\">\n<li><strong>CDCH\u2083OH<\/strong> or more specifically <strong>(CH\u2083)\u2082C(OH)D<\/strong><\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Among the answer choices<\/strong>, the only one representing the correct product is <strong>B. CDCH\u2083<\/strong>, since it reflects that one of the methyl groups has been reduced with the incorporation of a deuterium at the central carbon.<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<p>NaBD\u2084 reduces carbonyl groups just like NaBH\u2084, but replaces a hydrogen atom with deuterium. In the case of acetone, this leads to the formation of <strong>isopropanol with one D atom<\/strong>, represented by <strong>CDCH\u2083<\/strong>. Hence, the correct answer is <strong>B<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-161.jpeg\" alt=\"\" class=\"wp-image-27430\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-161.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-161-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-161-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the product of this reaction? (Note: NaBD4 is the same as NaBH4 where the hydrogens have been replaced by deuterium) NaBD4 H2O CH3OH OH CDCH3 OD CHCH3 OD CDCH3 CH2CO2CH3 A B CH3 The Correct Answer and Explanation is: Correct Answer: B. CDCH3 Explanation: The reagent NaBD\u2084 (sodium borodeuteride) is a deuterated version [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-27429","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/27429","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=27429"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/27429\/revisions"}],"predecessor-version":[{"id":27431,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/27429\/revisions\/27431"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=27429"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=27429"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=27429"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}