How many atoms of O there in 86.2 grams of cadmium (II) permanganate?<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n Let’s solve the problem step-by-step:<\/p>\n\n\n\n Question:<\/strong> So the formula is Cd(MnO\u2084)\u2082<\/strong>.<\/p>\n\n\n\n Molar mass of Cd(MnO\u2084)\u2082 = moles=massmolar mass=86.2 g350.29 g\/mol\u22480.246 mol\\text{moles} = \\frac{\\text{mass}}{\\text{molar mass}} = \\frac{86.2 \\text{ g}}{350.29 \\text{ g\/mol}} \\approx 0.246 \\text{ mol}<\/p>\n\n\n\n =1.968 mol\u00d76.022\u00d71023 atoms\/mol\u22481.185\u00d71024 oxygen atoms= 1.968 \\text{ mol} \\times 6.022 \\times 10^{23} \\text{ atoms\/mol} \\approx 1.185 \\times 10^{24} \\text{ oxygen atoms}<\/p>\n\n\n\n There are approximately 1.19 \u00d7 10\u00b2\u2074 atoms of oxygen<\/strong> in 86.2 grams of cadmium(II) permanganate.<\/p>\n\n\n\n This problem involves converting a given mass of a compound into the number of atoms of a specific element within it. To do this, you first need the correct chemical formula for the compound\u2014in this case, cadmium(II) permanganate, which is Cd(MnO\u2084)\u2082. The Roman numeral II indicates the oxidation state of cadmium is +2, which balances with two permanganate ions (MnO\u2084\u207b).<\/p>\n\n\n\n Once the formula is confirmed, calculate the molar mass by summing the atomic masses of all atoms in one mole of the compound: one Cd atom, two Mn atoms, and eight oxygen atoms (from two MnO\u2084 groups). Using atomic masses (Cd = 112.41 g\/mol, Mn = 54.94 g\/mol, O = 16.00 g\/mol), the total molar mass is 350.29 g\/mol.<\/p>\n\n\n\n Next, find the number of moles in the given mass (86.2 g) by dividing by the molar mass, yielding about 0.246 moles of the compound.<\/p>\n\n\n\n Since the compound contains 8 oxygen atoms per formula unit, multiply the moles of compound by 8 to get the moles of oxygen atoms. This gives approximately 1.968 moles of oxygen atoms.<\/p>\n\n\n\n Finally, multiply the moles of oxygen atoms by Avogadro\u2019s number (6.022 \u00d7 10\u00b2\u00b3 atoms\/mol) to convert moles into atoms. The result is roughly 1.19 \u00d7 10\u00b2\u2074 oxygen atoms in 86.2 grams of cadmium(II) permanganate.<\/p>\n\n\n\n This stepwise approach\u2014finding the molar mass, moles, and then converting to atoms\u2014is standard in stoichiometric problems involving counting atoms in a given mass of a compound.<\/p>\n","protected":false},"excerpt":{"rendered":" How many atoms of O there in 86.2 grams of cadmium (II) permanganate? The correct answer and explanation is: Let’s solve the problem step-by-step: Question:How many atoms of oxygen (O) are in 86.2 grams of cadmium(II) permanganate? Step 1: Write the formula of cadmium(II) permanganate So the formula is Cd(MnO\u2084)\u2082. Step 2: Calculate the molar […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-27060","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/27060","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=27060"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/27060\/revisions"}],"predecessor-version":[{"id":27062,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/27060\/revisions\/27062"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=27060"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=27060"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=27060"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
How many atoms of oxygen (O) are in 86.2 grams of cadmium(II) permanganate?<\/p>\n\n\n\n
\n\n\n\nStep 1: Write the formula of cadmium(II) permanganate<\/h3>\n\n\n\n
\n
\n\n\n\nStep 2: Calculate the molar mass of Cd(MnO\u2084)\u2082<\/h3>\n\n\n\n
\n
Cd = 112.41 g\/mol
Mn = 54.94 g\/mol
O = 16.00 g\/mol<\/li>\n<\/ul>\n\n\n\n
= (1 \u00d7 112.41) + (2 \u00d7 54.94) + (2 \u00d7 4 \u00d7 16.00)
= 112.41 + 109.88 + (8 \u00d7 16.00)
= 112.41 + 109.88 + 128.00
= 350.29 g\/mol<\/strong><\/p>\n\n\n\n
\n\n\n\nStep 3: Calculate the number of moles in 86.2 grams<\/h3>\n\n\n\n
\n\n\n\nStep 4: Calculate the number of oxygen atoms in the sample<\/h3>\n\n\n\n
\n
\n\n\n\nFinal answer:<\/strong><\/h3>\n\n\n\n
\n\n\n\nExplanation (about 300 words):<\/h3>\n\n\n\n