What is the change, in joules, of the internal energy of the gas during the during the isochoric heating process, DA?<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n To determine the change in internal energy of a gas during an isochoric heating process<\/strong> (constant volume), we must understand how internal energy behaves under these conditions.<\/p>\n\n\n\n For an ideal gas<\/strong>, change in internal energy (\u0394U)<\/strong> depends only on the temperature change<\/strong> and is independent of volume or pressure. During isochoric (constant volume)<\/strong> heating, no work<\/strong> is done by the gas, since: W=P\u0394V=0(because \u0394V=0)W = P \\Delta V = 0 \\quad \\text{(because } \\Delta V = 0)<\/p>\n\n\n\n From the First Law of Thermodynamics<\/strong>: \u0394U=Q\u2212W\\Delta U = Q – W<\/p>\n\n\n\n Since W=0W = 0, this simplifies to: \u0394U=Q\\Delta U = Q<\/p>\n\n\n\n So, all the heat added to the gas increases its internal energy<\/strong>.<\/p>\n\n\n\n For nn moles of an ideal monoatomic gas: \u0394U=nCV\u0394T\\Delta U = n C_V \\Delta T<\/p>\n\n\n\n Where:<\/p>\n\n\n\n If values for nn, TinitialT_{\\text{initial}}, and TfinalT_{\\text{final}} are given for process DA<\/strong>, you can substitute directly.<\/p>\n\n\n\n Suppose:<\/p>\n\n\n\n Then: \u0394U=nCV\u0394T=2\u22c532\u22c58.314\u22c5(500\u2212200)\\Delta U = n C_V \\Delta T = 2 \\cdot \\frac{3}{2} \\cdot 8.314 \\cdot (500 – 200) \u0394U=3\u22c58.314\u22c5300=7482.6\u2009J\\Delta U = 3 \\cdot 8.314 \\cdot 300 = 7482.6 \\, \\text{J}<\/p>\n\n\n\n During the isochoric heating process (DA)<\/strong>:<\/p>\n\n\n\n If you have a specific diagram or values for the points D and A (temperature, pressure, or energy), I can compute the exact answer. Please upload or describe the data if available.<\/p>\n<\/blockquote>\n","protected":false},"excerpt":{"rendered":" What is the change, in joules, of the internal energy of the gas during the during the isochoric heating process, DA? The correct answer and explanation is: To determine the change in internal energy of a gas during an isochoric heating process (constant volume), we must understand how internal energy behaves under these conditions. \ud83d\udd11 […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-26887","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26887","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=26887"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26887\/revisions"}],"predecessor-version":[{"id":26888,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26887\/revisions\/26888"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=26887"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=26887"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=26887"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\n\ud83d\udd11 Key Concept<\/strong><\/h3>\n\n\n\n
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\n\n\n\n\ud83e\udde0 Summary<\/h3>\n\n\n\n
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