{"id":26741,"date":"2025-06-19T17:46:44","date_gmt":"2025-06-19T17:46:44","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=26741"},"modified":"2025-06-19T17:46:46","modified_gmt":"2025-06-19T17:46:46","slug":"which-of-the-following-has-the-highest-percent-by-mass-of-chlorine","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/which-of-the-following-has-the-highest-percent-by-mass-of-chlorine\/","title":{"rendered":"Which of the following has the highest percent by mass of chlorine"},"content":{"rendered":"\n<p>Which of the following has the highest percent by mass of chlorine? a. HClO b. HClO2 c. HClO3 d. HClO4 e. All the same<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer: a. HClO<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>To determine which compound has the highest <strong>percent by mass of chlorine<\/strong>, we must calculate the <strong>mass percent of chlorine<\/strong> in each of the given compounds using this formula: Percent&nbsp;by&nbsp;mass&nbsp;of&nbsp;Cl=(Molar&nbsp;mass&nbsp;of&nbsp;ClMolar&nbsp;mass&nbsp;of&nbsp;compound)\u00d7100\\text{Percent by mass of Cl} = \\left( \\frac{\\text{Molar mass of Cl}}{\\text{Molar mass of compound}} \\right) \\times 100<\/p>\n\n\n\n<p>The atomic masses (approximate):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H = 1 g\/mol<\/li>\n\n\n\n<li>Cl = 35.5 g\/mol<\/li>\n\n\n\n<li>O = 16 g\/mol<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Option a: HClO<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass = 1 (H) + 35.5 (Cl) + 16 (O) = <strong>52.5 g\/mol<\/strong><\/li>\n\n\n\n<li>Percent Cl = (35.5 \/ 52.5) \u00d7 100 \u2248 <strong>67.6%<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Option b: HClO\u2082<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass = 1 + 35.5 + (2 \u00d7 16) = <strong>67.5 g\/mol<\/strong><\/li>\n\n\n\n<li>Percent Cl = (35.5 \/ 67.5) \u00d7 100 \u2248 <strong>52.6%<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Option c: HClO\u2083<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass = 1 + 35.5 + (3 \u00d7 16) = <strong>83.5 g\/mol<\/strong><\/li>\n\n\n\n<li>Percent Cl = (35.5 \/ 83.5) \u00d7 100 \u2248 <strong>42.5%<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Option d: HClO\u2084<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass = 1 + 35.5 + (4 \u00d7 16) = <strong>99.5 g\/mol<\/strong><\/li>\n\n\n\n<li>Percent Cl = (35.5 \/ 99.5) \u00d7 100 \u2248 <strong>35.7%<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Option e: All the same<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Incorrect<\/strong>, since we just calculated different percentages.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h3>\n\n\n\n<p>As the number of oxygen atoms increases in the series HClO \u2192 HClO\u2084, the total molar mass of the compound increases while the mass of chlorine remains the same (35.5 g\/mol). Therefore, the <strong>percentage of chlorine by mass decreases<\/strong> with more oxygen atoms.<\/p>\n\n\n\n<p>Thus, <strong>HClO has the highest percent by mass of chlorine<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which of the following has the highest percent by mass of chlorine? a. HClO b. HClO2 c. HClO3 d. HClO4 e. All the same The correct answer and explanation is: Correct Answer: a. HClO Explanation: To determine which compound has the highest percent by mass of chlorine, we must calculate the mass percent of chlorine [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-26741","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26741","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=26741"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26741\/revisions"}],"predecessor-version":[{"id":26742,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26741\/revisions\/26742"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=26741"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=26741"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=26741"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}