{"id":26037,"date":"2025-06-19T09:34:20","date_gmt":"2025-06-19T09:34:20","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=26037"},"modified":"2025-06-19T09:34:23","modified_gmt":"2025-06-19T09:34:23","slug":"how-many-atoms-are-in-4-39-g-of-co2","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-atoms-are-in-4-39-g-of-co2\/","title":{"rendered":"How many atoms are in 4.39 g of CO2"},"content":{"rendered":"\n<p>How many atoms are in 4.39 g of CO2?<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-light-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To find how many atoms are in 4.39 grams of carbon dioxide (CO\u2082), follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Calculate the molar mass of CO\u2082<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C): 12.01 g\/mol<\/li>\n\n\n\n<li>Oxygen (O): 16.00 g\/mol \u00d7 2 = 32.00 g\/mol<\/li>\n\n\n\n<li>Total molar mass of CO\u2082 = 12.01 + 32.00 = <strong>44.01 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Convert grams of CO\u2082 to moles<\/h3>\n\n\n\n<p>Moles&nbsp;of&nbsp;CO\u2082=4.39&nbsp;g44.01&nbsp;g\/mol\u22480.0998&nbsp;mol\\text{Moles of CO\u2082} = \\frac{4.39 \\text{ g}}{44.01 \\text{ g\/mol}} \u2248 0.0998 \\text{ mol}Moles&nbsp;of&nbsp;CO\u2082=44.01&nbsp;g\/mol4.39&nbsp;g\u200b\u22480.0998&nbsp;mol<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Use Avogadro&#8217;s number to find number of molecules<\/h3>\n\n\n\n<p>Number&nbsp;of&nbsp;molecules=0.0998&nbsp;mol\u00d76.022\u00d71023&nbsp;molecules\/mol\u22486.01\u00d71022&nbsp;molecules\\text{Number of molecules} = 0.0998 \\text{ mol} \u00d7 6.022 \u00d7 10^{23} \\text{ molecules\/mol} \u2248 6.01 \u00d7 10^{22} \\text{ molecules}Number&nbsp;of&nbsp;molecules=0.0998&nbsp;mol\u00d76.022\u00d71023&nbsp;molecules\/mol\u22486.01\u00d71022&nbsp;molecules<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Count atoms per molecule of CO\u2082<\/h3>\n\n\n\n<p>Each molecule of CO\u2082 contains:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>1 carbon atom<\/li>\n\n\n\n<li>2 oxygen atoms<br>Total = 3 atoms per molecule<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: Multiply molecules by atoms per molecule<\/h3>\n\n\n\n<p>Total&nbsp;atoms=6.01\u00d71022&nbsp;molecules\u00d73&nbsp;atoms\/molecule\u22481.80\u00d71023&nbsp;atoms\\text{Total atoms} = 6.01 \u00d7 10^{22} \\text{ molecules} \u00d7 3 \\text{ atoms\/molecule} \u2248 1.80 \u00d7 10^{23} \\text{ atoms}Total&nbsp;atoms=6.01\u00d71022&nbsp;molecules\u00d73&nbsp;atoms\/molecule\u22481.80\u00d71023&nbsp;atoms<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p><strong>There are approximately 1.80 \u00d7 10\u00b2\u00b3 atoms in 4.39 grams of CO\u2082.<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>To determine how many atoms are in a given mass of carbon dioxide, we begin by finding the molar mass of the compound. Carbon dioxide has one atom of carbon and two atoms of oxygen. Carbon has an atomic mass of about 12.01 grams per mole, while oxygen has an atomic mass of about 16.00 grams per mole. Thus, the molar mass of carbon dioxide is 44.01 grams per mole.<\/p>\n\n\n\n<p>Next, we convert the given mass (4.39 grams) of carbon dioxide into moles. This is done by dividing the mass by the molar mass, yielding approximately 0.0998 moles. This step tells us how many moles of carbon dioxide molecules we have.<\/p>\n\n\n\n<p>To determine how many individual molecules this represents, we use Avogadro\u2019s number, which states that one mole of any substance contains approximately 6.022 \u00d7 10\u00b2\u00b3 entities, in this case, molecules. Multiplying the number of moles by Avogadro\u2019s number gives us around 6.01 \u00d7 10\u00b2\u00b2 carbon dioxide molecules.<\/p>\n\n\n\n<p>Finally, we must remember that each molecule of carbon dioxide consists of three atoms\u2014one carbon atom and two oxygen atoms. Therefore, to find the total number of atoms, we multiply the number of molecules by three. This results in a total of about 1.80 \u00d7 10\u00b2\u00b3 atoms in 4.39 grams of carbon dioxide.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"722\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-44.jpeg\" alt=\"\" class=\"wp-image-26038\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-44.jpeg 722w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner10-44-212x300.jpeg 212w\" sizes=\"auto, (max-width: 722px) 100vw, 722px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>How many atoms are in 4.39 g of CO2? The Correct Answer and Explanation is: To find how many atoms are in 4.39 grams of carbon dioxide (CO\u2082), follow these steps: Step 1: Calculate the molar mass of CO\u2082 Step 2: Convert grams of CO\u2082 to moles Moles&nbsp;of&nbsp;CO\u2082=4.39&nbsp;g44.01&nbsp;g\/mol\u22480.0998&nbsp;mol\\text{Moles of CO\u2082} = \\frac{4.39 \\text{ g}}{44.01 \\text{ [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-26037","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26037","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=26037"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26037\/revisions"}],"predecessor-version":[{"id":26039,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/26037\/revisions\/26039"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=26037"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=26037"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=26037"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}