Correct Answer:<\/strong> The conjugate base of H\u2082S is HS\u207b<\/strong> (hydrosulfide ion).<\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n A conjugate base<\/strong> is the species that remains after an acid has donated a proton (H\u207a). In this case, hydrogen sulfide (H\u2082S) is a diprotic acid<\/strong>, meaning it can donate two protons. When it donates one proton<\/strong>, it forms its conjugate base<\/strong>, which is the HS\u207b<\/strong> ion.<\/p>\n\n\n\n To understand how this works, we look at the dissociation reaction of H\u2082S in water:<\/p>\n\n\n\n H\u2082S \u21cc H\u207a + HS\u207b<\/strong><\/p>\n\n\n\n In this reaction, H\u2082S loses one hydrogen ion (proton), resulting in the formation of the hydrosulfide ion (HS\u207b). This means HS\u207b is the conjugate base<\/strong> of H\u2082S, since it is what remains after H\u2082S gives up a proton.<\/p>\n\n\n\n This process is part of Br\u00f8nsted\u2013Lowry acid\u2013base theory<\/strong>, where acids are defined as proton donors and bases are proton acceptors. According to this theory, once H\u2082S donates a proton, it becomes capable of accepting a proton again, so HS\u207b is a base \u2014 specifically, a conjugate base<\/strong>.<\/p>\n\n\n\n HS\u207b itself can also act as a weak acid<\/strong>, since it can donate a second proton to form the S\u00b2\u207b<\/strong> (sulfide) ion:<\/p>\n\n\n\n HS\u207b \u21cc H\u207a + S\u00b2\u207b<\/strong><\/p>\n\n\n\n But in the context of the first proton donation<\/strong>, HS\u207b is the conjugate base of H\u2082S.<\/p>\n\n\n\n In summary, when H\u2082S loses one hydrogen ion, it becomes HS\u207b, which is its conjugate base. This concept is essential in acid\u2013base chemistry, especially when understanding acid strength, pH, buffer systems, and equilibrium in aqueous solutions.<\/p>\n\n\n\n Give the conjugate base of h2s The Correct Answer and Explanation is: Correct Answer: The conjugate base of H\u2082S is HS\u207b (hydrosulfide ion). Explanation: A conjugate base is the species that remains after an acid has donated a proton (H\u207a). In this case, hydrogen sulfide (H\u2082S) is a diprotic acid, meaning it can donate two […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-25863","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25863","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=25863"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25863\/revisions"}],"predecessor-version":[{"id":25867,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25863\/revisions\/25867"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=25863"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=25863"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=25863"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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