{"id":25697,"date":"2025-06-19T06:19:45","date_gmt":"2025-06-19T06:19:45","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=25697"},"modified":"2025-06-19T06:19:47","modified_gmt":"2025-06-19T06:19:47","slug":"the-density-of-seawater-is-1030-kg-m3-and-the-density-of-whole-blood-is-1050-kg-m3","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-density-of-seawater-is-1030-kg-m3-and-the-density-of-whole-blood-is-1050-kg-m3\/","title":{"rendered":"The density of seawater is 1030 kg\/m3 and the density of whole blood is 1050 kg\/m3"},"content":{"rendered":"\n<p>The density of seawater is 1030 kg\/m3 and the density of whole blood is 1050 kg\/m3. Note that 1cm3 = 1mL. What is the volume (in Liters, L) of 103 grams seawater? What is the volume (in Liters, L) of 105 grams whole blood?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s solve the problem step by step.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Given:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Density of seawater, \u03c1sw=1030\u2009kg\/m3\\rho_{sw} = 1030 \\, \\text{kg\/m}^3<\/li>\n\n\n\n<li>Density of whole blood, \u03c1wb=1050\u2009kg\/m3\\rho_{wb} = 1050 \\, \\text{kg\/m}^3<\/li>\n\n\n\n<li>Mass of seawater, msw=103\u2009gm_{sw} = 103 \\, \\text{g}<\/li>\n\n\n\n<li>Mass of whole blood, mwb=105\u2009gm_{wb} = 105 \\, \\text{g}<\/li>\n\n\n\n<li>1\u2009cm3=1\u2009mL1 \\, \\text{cm}^3 = 1 \\, \\text{mL}<\/li>\n\n\n\n<li>1000\u2009mL=1\u2009L1000 \\, \\text{mL} = 1 \\, \\text{L}<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Convert mass from grams to kilograms<\/h3>\n\n\n\n<p>Since density is in kg\/m\u00b3, convert mass to kg: msw=103\u2009g=1031000=0.103\u2009kgm_{sw} = 103 \\, \\text{g} = \\frac{103}{1000} = 0.103 \\, \\text{kg} mwb=105\u2009g=1051000=0.105\u2009kgm_{wb} = 105 \\, \\text{g} = \\frac{105}{1000} = 0.105 \\, \\text{kg}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Use the density formula to find volume<\/h3>\n\n\n\n<p>Density formula: \u03c1=mV\u2005\u200a\u27f9\u2005\u200aV=m\u03c1\\rho = \\frac{m}{V} \\implies V = \\frac{m}{\\rho}<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For seawater:<\/li>\n<\/ul>\n\n\n\n<p>Vsw=0.103\u2009kg1030\u2009kg\/m3=1.0\u00d710\u22124\u2009m3V_{sw} = \\frac{0.103 \\, \\text{kg}}{1030 \\, \\text{kg\/m}^3} = 1.0 \\times 10^{-4} \\, \\text{m}^3<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For whole blood:<\/li>\n<\/ul>\n\n\n\n<p>Vwb=0.105\u2009kg1050\u2009kg\/m3=1.0\u00d710\u22124\u2009m3V_{wb} = \\frac{0.105 \\, \\text{kg}}{1050 \\, \\text{kg\/m}^3} = 1.0 \\times 10^{-4} \\, \\text{m}^3<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Convert volume from cubic meters to liters<\/h3>\n\n\n\n<p>1\u2009m3=1000\u2009L1 \\, \\text{m}^3 = 1000 \\, \\text{L}<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For seawater:<\/li>\n<\/ul>\n\n\n\n<p>Vsw=1.0\u00d710\u22124\u00d71000=0.1\u2009LV_{sw} = 1.0 \\times 10^{-4} \\times 1000 = 0.1 \\, \\text{L}<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For whole blood:<\/li>\n<\/ul>\n\n\n\n<p>Vwb=1.0\u00d710\u22124\u00d71000=0.1\u2009LV_{wb} = 1.0 \\times 10^{-4} \\times 1000 = 0.1 \\, \\text{L}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final answers:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Volume of 103 g seawater = <strong>0.1 L<\/strong><\/li>\n\n\n\n<li>Volume of 105 g whole blood = <strong>0.1 L<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words):<\/h3>\n\n\n\n<p>The volume of a substance can be calculated using its mass and density through the relation: V=m\u03c1V = \\frac{m}{\\rho}<\/p>\n\n\n\n<p>where VV is volume, mm is mass, and \u03c1\\rho is density.<\/p>\n\n\n\n<p>In this problem, the densities of seawater and whole blood are given in kilograms per cubic meter (kg\/m\u00b3), while the mass is given in grams. To maintain unit consistency, the mass must first be converted into kilograms because 1 kg = 1000 g.<\/p>\n\n\n\n<p>Once the mass is converted, we substitute the values into the density formula. For example, seawater with a mass of 103 g converts to 0.103 kg. Using the density of seawater 1030\u2009kg\/m31030 \\, \\text{kg\/m}^3, dividing mass by density gives the volume in cubic meters. The calculation yields 1.0\u00d710\u22124\u2009m31.0 \\times 10^{-4} \\, \\text{m}^3.<\/p>\n\n\n\n<p>Similarly, whole blood with a mass of 105 g converts to 0.105 kg. Using the density 1050\u2009kg\/m31050 \\, \\text{kg\/m}^3, the volume is again approximately 1.0\u00d710\u22124\u2009m31.0 \\times 10^{-4} \\, \\text{m}^3.<\/p>\n\n\n\n<p>Because volumes in cubic meters are often cumbersome for small quantities, converting them to liters is practical, knowing that 1\u2009m3=1000\u2009L1 \\, \\text{m}^3 = 1000 \\, \\text{L}. This conversion results in volumes of 0.1 liters for both seawater and whole blood in the given masses.<\/p>\n\n\n\n<p>Interestingly, even though the masses and densities differ slightly, the resulting volumes are nearly the same due to the close values of density and mass, both approximating 0.1 liters.<\/p>\n\n\n\n<p>Understanding these conversions is crucial in many scientific and engineering applications, such as calculating fluid displacement, medical dosage, or chemical solution preparation, where accurate volume measurements are vital.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The density of seawater is 1030 kg\/m3 and the density of whole blood is 1050 kg\/m3. Note that 1cm3 = 1mL. What is the volume (in Liters, L) of 103 grams seawater? What is the volume (in Liters, L) of 105 grams whole blood? The correct answer and explanation is: Let&#8217;s solve the problem step [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-25697","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25697","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=25697"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25697\/revisions"}],"predecessor-version":[{"id":25699,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25697\/revisions\/25699"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=25697"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=25697"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=25697"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}