{"id":25675,"date":"2025-06-19T06:13:05","date_gmt":"2025-06-19T06:13:05","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=25675"},"modified":"2025-06-19T06:13:06","modified_gmt":"2025-06-19T06:13:06","slug":"part-b-please-use-the-lewis-dot-structure","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/part-b-please-use-the-lewis-dot-structure\/","title":{"rendered":"Part B &#8211; Please use the Lewis dot structure."},"content":{"rendered":"\n<p>Part B &#8211; Please use the Lewis dot structure. a) ClH b) CHN c) CH2OS d) SiH3P<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-light-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Here are the Lewis dot structures and explanations for each molecule:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">a) <strong>ClH (Hydrogen chloride)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">rubyCopyEdit<code>:H \u2013 Cl:\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong><br>Hydrogen has 1 valence electron and forms one bond. Chlorine has 7 valence electrons and needs one more to complete its octet. A single bond forms between H and Cl, with Cl keeping 6 electrons as lone pairs. This satisfies both atoms \u2014 hydrogen has 2 electrons (full shell for H), and chlorine has 8 electrons around it.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">b) <strong>CHN (Assuming structure is H\u2013C\u2261N)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>H \u2013 C \u2261 N:\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong><br>Carbon has 4 valence electrons, hydrogen has 1, and nitrogen has 5. The most stable configuration is a linear molecule with hydrogen single-bonded to carbon and carbon triple-bonded to nitrogen. Carbon shares one pair with H and three pairs with N. Nitrogen keeps one lone pair. This arrangement satisfies the octet rule for both carbon and nitrogen, and hydrogen has its full shell of 2 electrons.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">c) <strong>CH\u2082OS (Assuming structure is H\u2082C=O\u2013S)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">mathematicaCopyEdit<code>H   H  \n \\ \/  \n  C = O  \n      |  \n      S:\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong><br>Carbon forms four bonds: two with hydrogen, one double bond with oxygen, and one single bond with sulfur. Oxygen forms a double bond with carbon and keeps two lone pairs. Sulfur forms a single bond with carbon and keeps two lone pairs (can exceed the octet). This satisfies the bonding rules for all atoms involved.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">d) <strong>SiH\u2083P (Silicon bonded to three hydrogens and one phosphorus)<\/strong><\/h3>\n\n\n\n<p><strong>Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">lessCopyEdit<code>   H  \n   |  \nH\u2013Si\u2013P:  \n   |  \n   H\n<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Explanation:<\/strong><br>Silicon has 4 valence electrons and forms four single bonds: three with hydrogen atoms and one with phosphorus. Phosphorus has 5 valence electrons and uses one to bond with Si, keeping two lone pairs. Hydrogen atoms each form one single bond. The octet rule is satisfied for Si and P, and H has full shells.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>These Lewis structures ensure each atom achieves a stable configuration using shared electron pairs and lone pairs.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-79.jpeg\" alt=\"\" class=\"wp-image-25682\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-79.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-79-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-79-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Part B &#8211; Please use the Lewis dot structure. a) ClH b) CHN c) CH2OS d) SiH3P The Correct Answer and Explanation is: Here are the Lewis dot structures and explanations for each molecule: a) ClH (Hydrogen chloride) Lewis Structure: rubyCopyEdit:H \u2013 Cl: b) CHN (Assuming structure is H\u2013C\u2261N) Lewis Structure: mathematicaCopyEditH \u2013 C \u2261 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-25675","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25675","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=25675"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25675\/revisions"}],"predecessor-version":[{"id":25683,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25675\/revisions\/25683"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=25675"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=25675"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=25675"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}