{"id":25635,"date":"2025-06-19T05:59:52","date_gmt":"2025-06-19T05:59:52","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=25635"},"modified":"2025-06-19T05:59:54","modified_gmt":"2025-06-19T05:59:54","slug":"the-electron-configuration-kr-4d10-corresponds-to-which-of-the-following-atom-ion-sn2-inj","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-electron-configuration-kr-4d10-corresponds-to-which-of-the-following-atom-ion-sn2-inj\/","title":{"rendered":"The electron configuration: [Kr] 4d10 , corresponds to which of the following atom\/ ion: Sn2 Inj+"},"content":{"rendered":"\n<p>The electron configuration: [Kr] 4d10 , corresponds to which of the following atom\/ ion: Sn2 Inj+<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-light-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>Sn\u00b2\u207a (Tin (II) ion)<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The electron configuration given is:<\/p>\n\n\n\n<p><strong>[Kr] 4d\u00b9\u2070<\/strong><\/p>\n\n\n\n<p>This means the element or ion has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The same electron configuration as krypton (Kr), which is the noble gas with atomic number 36<\/li>\n\n\n\n<li>Plus 10 electrons in the 4d subshell<\/li>\n<\/ul>\n\n\n\n<p>Let us identify what neutral atom would have this configuration <strong>after ionization<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understand the full configuration of neutral tin (Sn)<\/h3>\n\n\n\n<p>Tin (Sn) has atomic number <strong>50<\/strong>, meaning a neutral tin atom has 50 electrons. Its ground-state electron configuration is:<\/p>\n\n\n\n<p><strong>[Kr] 5s\u00b2 4d\u00b9\u2070 5p\u00b2<\/strong><\/p>\n\n\n\n<p>So, the outermost electrons are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 electrons in the 5s orbital<\/li>\n\n\n\n<li>2 electrons in the 5p orbital<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: What happens when Sn loses electrons to form <strong>Sn\u00b2\u207a<\/strong><\/h3>\n\n\n\n<p>When Sn loses <strong>2 electrons<\/strong>, it forms <strong>Sn\u00b2\u207a<\/strong>. The electrons are removed from the outermost energy level first (which is the 5p and 5s orbitals).<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>First, the 2 electrons from the 5p\u00b2 are removed<\/li>\n\n\n\n<li>That leaves the configuration: <strong>[Kr] 4d\u00b9\u2070<\/strong><\/li>\n<\/ul>\n\n\n\n<p>So <strong>Sn\u00b2\u207a<\/strong> has the configuration [Kr] 4d\u00b9\u2070.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Consider Inj\u207a<\/h3>\n\n\n\n<p>&#8220;Inj\u207a&#8221; does not correspond to any known chemical symbol or ion. It might be a typo or an undefined species, so we discard it.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The electron configuration [Kr] 4d\u00b9\u2070 corresponds to <strong>Sn\u00b2\u207a<\/strong>, the tin ion with a +2 charge. This ion has lost the two electrons from the 5p orbital, leaving a stable, filled 4d subshell and no electrons in the 5th energy level. This configuration gives the ion some extra stability due to the completely filled 4d subshell.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-74.jpeg\" alt=\"\" class=\"wp-image-25636\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-74.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-74-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-74-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The electron configuration: [Kr] 4d10 , corresponds to which of the following atom\/ ion: Sn2 Inj+ The Correct Answer and Explanation is: The correct answer is Sn\u00b2\u207a (Tin (II) ion). Explanation: The electron configuration given is: [Kr] 4d\u00b9\u2070 This means the element or ion has: Let us identify what neutral atom would have this configuration [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-25635","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25635","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=25635"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25635\/revisions"}],"predecessor-version":[{"id":25637,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25635\/revisions\/25637"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=25635"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=25635"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=25635"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}