Balanced Equation:<\/strong><\/p>\n\n\n\n C\u2083H\u2088 + 5O\u2082 \u2192 3CO\u2082 + 4H\u2082O<\/p>\n\n\n\n Explanation:<\/strong><\/p>\n\n\n\n To balance the chemical equation involving the combustion of propane (C\u2083H\u2088), we need to ensure the number of atoms of each element on the left side equals the number of atoms on the right side of the equation.<\/p>\n\n\n\n This is a combustion reaction. Propane (C\u2083H\u2088), a hydrocarbon, reacts with oxygen (O\u2082) to produce carbon dioxide (CO\u2082) and water (H\u2082O). Combustion reactions of hydrocarbons always produce these two products if the combustion is complete.<\/p>\n\n\n\n Propane has 3 carbon atoms. So, place a coefficient of 3 in front of CO\u2082 to balance the carbon atoms: Now both sides have 3 carbon atoms.<\/p>\n\n\n\n Propane has 8 hydrogen atoms. Each water molecule has 2 hydrogen atoms. To get 8 hydrogen atoms on the product side, place a coefficient of 4 in front of H\u2082O: Now both sides have 8 hydrogen atoms.<\/p>\n\n\n\n Now count the total number of oxygen atoms on the right-hand side. Each O\u2082 molecule has 2 oxygen atoms, so to get 10 oxygen atoms, you need 5 O\u2082 molecules: Now both sides have equal numbers of each atom:<\/p>\n\n\n\n The equation is now balanced.<\/p>\n\n\n\n Balance C3H8 + O2 + CO2 + H2O The Correct Answer and Explanation is: Balanced Equation: C\u2083H\u2088 + 5O\u2082 \u2192 3CO\u2082 + 4H\u2082O Explanation: To balance the chemical equation involving the combustion of propane (C\u2083H\u2088), we need to ensure the number of atoms of each element on the left side equals the number of atoms […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-25483","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25483","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=25483"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25483\/revisions"}],"predecessor-version":[{"id":25485,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25483\/revisions\/25485"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=25483"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=25483"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=25483"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep 1: Understand the Reaction Type<\/h3>\n\n\n\n
Step 2: Balance Carbon Atoms<\/h3>\n\n\n\n
C\u2083H\u2088 + O\u2082 \u2192 3CO\u2082<\/strong> + H\u2082O<\/p>\n\n\n\nStep 3: Balance Hydrogen Atoms<\/h3>\n\n\n\n
C\u2083H\u2088 + O\u2082 \u2192 3CO\u2082 + 4H\u2082O<\/strong><\/p>\n\n\n\nStep 4: Balance Oxygen Atoms<\/h3>\n\n\n\n
From 3CO\u2082, you get 3 \u00d7 2 = 6 oxygen atoms.
From 4H\u2082O, you get 4 \u00d7 1 = 4 oxygen atoms.
In total, 6 + 4 = 10 oxygen atoms<\/strong> are needed.<\/p>\n\n\n\n
C\u2083H\u2088 + 5O\u2082<\/strong> \u2192 3CO\u2082 + 4H\u2082O<\/p>\n\n\n\n\n
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