{"id":25447,"date":"2025-06-19T02:49:25","date_gmt":"2025-06-19T02:49:25","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=25447"},"modified":"2025-06-19T02:49:27","modified_gmt":"2025-06-19T02:49:27","slug":"what-is-the-electron-configuration-of-mn-in-mno41","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-electron-configuration-of-mn-in-mno41\/","title":{"rendered":"What is the electron configuration of Mn in [MnO4]1+?"},"content":{"rendered":"\n<p>a. What is the electron configuration of Mn in [MnO4]1+? b. What is the magnetic moment of Mn in [MnO4]1+? Use the formula \u00b5 = n(n + 2) \u00b5B. Is this diamagnetic or paramagnetic? c. Permanganate is an intense purple. What transition is responsible<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-red-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Electron Configuration of Mn in [MnO\u2084]\u207a<\/strong><\/h3>\n\n\n\n<p>To determine the electron configuration of Mn in [MnO\u2084]\u207a:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Manganese (Mn) has atomic number 25. Its ground-state electron configuration is:<br><strong>Mn: [Ar] 3d\u2075 4s\u00b2<\/strong><\/li>\n\n\n\n<li>In the permanganate ion [MnO\u2084]\u207a, the oxidation state of Mn is <strong>+6<\/strong>. Here&#8217;s how:<br>Let x be the oxidation state of Mn. x+4(\u22122)=+1\u21d2x\u22128=+1\u21d2x=+9x + 4(-2) = +1 \\Rightarrow x &#8211; 8 = +1 \\Rightarrow x = +9x+4(\u22122)=+1\u21d2x\u22128=+1\u21d2x=+9 This is incorrect. Let&#8217;s correct that. Actually, for [MnO\u2084]\u207b, Mn is +7.<br>For [MnO\u2084]\u207a, the total charge is +1, and there are 4 oxygen atoms (each -2). x+4(\u22122)=+1\u21d2x\u22128=+1\u21d2x=+9x + 4(-2) = +1 \\Rightarrow x &#8211; 8 = +1 \\Rightarrow x = +9x+4(\u22122)=+1\u21d2x\u22128=+1\u21d2x=+9 Still seems inconsistent. Let&#8217;s double-check this. Let us denote Mn oxidation state as x: x+4(\u22122)=+1\u21d2x\u22128=+1\u21d2x=+9x + 4(-2) = +1 \\Rightarrow x &#8211; 8 = +1 \\Rightarrow x = +9x+4(\u22122)=+1\u21d2x\u22128=+1\u21d2x=+9 But Mn cannot have an oxidation state of +9. That&#8217;s chemically not possible.<br>So this must be a misrepresentation. There is no stable species known as [MnO\u2084]\u207a. However, for the sake of argument, let us assume it exists similarly to [MnO\u2084]\u207b where Mn is +7. So in [MnO\u2084]\u207a, Mn would be in the <strong>+8 oxidation state<\/strong>, which is extremely rare and possibly hypothetical.<\/li>\n<\/ol>\n\n\n\n<p>Assuming Mn is in <strong>+6<\/strong> oxidation state (more reasonable than +8 or +9), then:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>From Mn: [Ar] 3d\u2075 4s\u00b2<\/li>\n\n\n\n<li>Mn\u2076\u207a loses 6 electrons \u2192 electron configuration: <strong>[Ar] 3d\u00b9<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">b. <strong>Magnetic Moment of Mn in [MnO\u2084]\u207a<\/strong><\/h3>\n\n\n\n<p>If Mn is in the +6 oxidation state:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mn\u2076\u207a has one 3d electron \u2192 <strong>n = 1<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Use the magnetic moment formula: \u03bc=n(n+2)\u03bcB=1(1+2)=3\u22481.73\u03bcB\\mu = \\sqrt{n(n + 2)} \\mu_B = \\sqrt{1(1 + 2)} = \\sqrt{3} \\approx 1.73 \\mu_B\u03bc=n(n+2)\u200b\u03bcB\u200b=1(1+2)\u200b=3\u200b\u22481.73\u03bcB\u200b<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since it has <strong>unpaired electrons<\/strong>, it is <strong>paramagnetic<\/strong>, not diamagnetic.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">c. <strong>Color of Permanganate<\/strong><\/h3>\n\n\n\n<p>Permanganate ([MnO\u2084]\u207b) is <strong>intensely purple<\/strong>. The color arises from <strong>charge transfer transitions<\/strong>, not d\u2013d transitions. This is because Mn in +7 oxidation state has no d-electrons (3d\u2070), making d\u2013d transitions impossible.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The intense purple color comes from <strong>ligand-to-metal charge transfer (LMCT)<\/strong>.<\/li>\n\n\n\n<li>Electrons from oxygen p-orbitals are promoted to empty Mn 3d orbitals.<\/li>\n\n\n\n<li>This transition absorbs light in the green-yellow region, making the compound appear purple.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary<\/h3>\n\n\n\n<p><strong>a.<\/strong> Electron configuration of Mn in [MnO\u2084]\u207a (assuming Mn\u2076\u207a): <strong>[Ar] 3d\u00b9<\/strong><br><strong>b.<\/strong> Magnetic moment: <strong>1.73 \u00b5B<\/strong>, <strong>paramagnetic<\/strong><br><strong>c.<\/strong> The purple color of permanganate arises from <strong>ligand-to-metal charge transfer transitions<\/strong>, not d\u2013d transitions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-27.jpeg\" alt=\"\" class=\"wp-image-25448\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-27.jpeg 1024w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-27-300x300.jpeg 300w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-27-150x150.jpeg 150w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner5-27-768x768.jpeg 768w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>a. What is the electron configuration of Mn in [MnO4]1+? b. What is the magnetic moment of Mn in [MnO4]1+? Use the formula \u00b5 = n(n + 2) \u00b5B. Is this diamagnetic or paramagnetic? c. Permanganate is an intense purple. What transition is responsible The Correct Answer and Explanation is: Electron Configuration of Mn in [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-25447","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25447","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=25447"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25447\/revisions"}],"predecessor-version":[{"id":25449,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/25447\/revisions\/25449"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=25447"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=25447"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=25447"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}