{"id":24700,"date":"2025-06-18T17:22:25","date_gmt":"2025-06-18T17:22:25","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=24700"},"modified":"2025-06-18T17:22:27","modified_gmt":"2025-06-18T17:22:27","slug":"write-the-ground-state-configuration-for-cu-fe3-ti3-and-s4","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-the-ground-state-configuration-for-cu-fe3-ti3-and-s4\/","title":{"rendered":"Write the ground state configuration for Cu, Fe3+, Ti3+ and S4+"},"content":{"rendered":"\n<p>Write the ground state configuration for Cu, Fe3+, Ti3+ and S4+. Cu+ <strong><em><strong><em>_____<\/em><\/strong><\/em><\/strong> Ti3+ <strong><em><strong><em>__________<\/em><\/strong><\/em><\/strong> Fe2+<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-luminous-vivid-amber-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answers:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Cu\u207a (Copper ion):<\/strong><br><strong>[Ar] 3d\u00b9\u2070<\/strong><\/li>\n\n\n\n<li><strong>Ti\u00b3\u207a (Titanium ion):<\/strong><br><strong>[Ar] 3d\u00b9<\/strong><\/li>\n\n\n\n<li><strong>Fe\u00b2\u207a (Iron ion):<\/strong><br><strong>[Ar] 3d\u2076<\/strong><\/li>\n\n\n\n<li><strong>S\u2074\u207a (Sulfur ion):<\/strong><br><strong>1s\u00b2 2s\u00b2 2p\u2076<\/strong> (or simply [Ne])<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation<\/strong><\/h3>\n\n\n\n<p>To understand the ground-state electron configurations of ions like Cu\u207a, Ti\u00b3\u207a, Fe\u00b2\u207a, and S\u2074\u207a, we begin with their neutral atom configurations and remove electrons according to the ion\u2019s charge.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. Copper (Cu\u207a):<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Neutral Cu has atomic number 29.<\/li>\n\n\n\n<li>Its ground state: <strong>[Ar] 4s\u00b9 3d\u00b9\u2070<\/strong><\/li>\n\n\n\n<li>When Cu loses one electron to form Cu\u207a, it is removed from the <strong>4s orbital first<\/strong>, not the 3d.<\/li>\n\n\n\n<li>So, <strong>Cu\u207a = [Ar] 3d\u00b9\u2070<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This fully filled d-subshell (3d\u00b9\u2070) makes Cu\u207a more stable due to electron configuration symmetry and energy considerations.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. Titanium (Ti\u00b3\u207a):<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Atomic number of Ti is 22.<\/li>\n\n\n\n<li>Neutral configuration: <strong>[Ar] 4s\u00b2 3d\u00b2<\/strong><\/li>\n\n\n\n<li>Losing three electrons for Ti\u00b3\u207a: remove the <strong>two 4s<\/strong> and <strong>one 3d<\/strong> electron.<\/li>\n\n\n\n<li>So, <strong>Ti\u00b3\u207a = [Ar] 3d\u00b9<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This is a common oxidation state for titanium in coordination complexes, and it results in one unpaired d-electron.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>3. Iron (Fe\u00b2\u207a):<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Fe atomic number: 26.<\/li>\n\n\n\n<li>Neutral: <strong>[Ar] 4s\u00b2 3d\u2076<\/strong><\/li>\n\n\n\n<li>To get Fe\u00b2\u207a, remove two electrons. The <strong>4s electrons<\/strong> are removed first.<\/li>\n\n\n\n<li>Fe\u00b2\u207a = <strong>[Ar] 3d\u2076<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This configuration has four unpaired electrons and is commonly seen in biological systems like hemoglobin.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>4. Sulfur (S\u2074\u207a):<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Atomic number of sulfur: 16.<\/li>\n\n\n\n<li>Neutral configuration: <strong>1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2074<\/strong><\/li>\n\n\n\n<li>S\u2074\u207a loses four electrons: two from 3p and two from 3s.<\/li>\n\n\n\n<li>Remaining configuration: <strong>1s\u00b2 2s\u00b2 2p\u2076<\/strong>, or simply <strong>[Ne]<\/strong><\/li>\n<\/ul>\n\n\n\n<p>This noble gas configuration is especially stable and occurs in compounds like SO\u2082.<\/p>\n\n\n\n<p>Understanding which orbitals lose electrons first is key in writing ion configurations correctly.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-9.jpeg\" alt=\"\" class=\"wp-image-24701\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-9.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-9-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-9-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the ground state configuration for Cu, Fe3+, Ti3+ and S4+. Cu+ _____ Ti3+ __________ Fe2+ The Correct Answer and Explanation is: Correct Answers: Explanation To understand the ground-state electron configurations of ions like Cu\u207a, Ti\u00b3\u207a, Fe\u00b2\u207a, and S\u2074\u207a, we begin with their neutral atom configurations and remove electrons according to the ion\u2019s charge. 1. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-24700","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/24700","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=24700"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/24700\/revisions"}],"predecessor-version":[{"id":24702,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/24700\/revisions\/24702"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=24700"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=24700"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=24700"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}