{"id":24697,"date":"2025-06-18T17:18:38","date_gmt":"2025-06-18T17:18:38","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=24697"},"modified":"2025-06-18T17:18:40","modified_gmt":"2025-06-18T17:18:40","slug":"write-the-ground-state-isoelectronic-partner-of-the-following-elements-ti3-a-ca-b-sc-c-k","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/write-the-ground-state-isoelectronic-partner-of-the-following-elements-ti3-a-ca-b-sc-c-k\/","title":{"rendered":"Write the ground state isoelectronic partner of the following elements &#8211; Ti3+ a) Ca b) Sc c) K"},"content":{"rendered":"\n<p>Write the ground state isoelectronic partner of the following elements &#8211; Ti3+ a) Ca b) Sc c) K<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-light-green-cyan-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p><strong>Correct Answer: a) Ca<\/strong><\/p>\n\n\n\n<p><strong>Explanation:<\/strong><\/p>\n\n\n\n<p>The term <strong>isoelectronic<\/strong> refers to atoms, ions, or molecules that have the <strong>same number of electrons<\/strong> and hence the <strong>same electronic configuration<\/strong> in their ground state.<\/p>\n\n\n\n<p>Let&#8217;s first find the <strong>electronic configuration<\/strong> of the ion <strong>Ti\u00b3\u207a (Titanium 3+)<\/strong>.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Atomic number of Titanium (Ti) = 22<\/li>\n\n\n\n<li>Neutral Ti: 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b2 4s\u00b2<\/li>\n\n\n\n<li>When Ti loses 3 electrons to form Ti\u00b3\u207a, electrons are removed first from the 4s orbital and then from the 3d orbital:<br><strong>Ti\u00b3\u207a = 1s\u00b2 2s\u00b2 2p\u2076 3s\u00b2 3p\u2076 3d\u00b9<\/strong><br>So, Ti\u00b3\u207a has <strong>19 electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>We are to find which <strong>neutral element<\/strong> has <strong>19 electrons<\/strong> as well. The number of electrons in a <strong>neutral atom<\/strong> equals its atomic number.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>a) Calcium (Ca): Atomic number 20 \u2192 20 electrons<\/li>\n\n\n\n<li>b) Scandium (Sc): Atomic number 21 \u2192 21 electrons<\/li>\n\n\n\n<li>c) Potassium (K): Atomic number 19 \u2192 19 electrons<\/li>\n<\/ul>\n\n\n\n<p>So the element with <strong>19 electrons<\/strong> is <strong>Potassium (K)<\/strong>.<\/p>\n\n\n\n<p>However, the question is asking for the <strong>ground state isoelectronic partner<\/strong>, which means an <strong>atom or ion<\/strong> that has the <strong>same electron configuration<\/strong> as Ti\u00b3\u207a in its <strong>ground state<\/strong>.<\/p>\n\n\n\n<p>Let&#8217;s compare:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ti\u00b3\u207a has an electronic configuration ending in <strong>3d\u00b9<\/strong>.<\/li>\n\n\n\n<li>Potassium (K) in its neutral form has configuration <strong>[Ar] 4s\u00b9<\/strong>, not isoelectronic with Ti\u00b3\u207a.<\/li>\n\n\n\n<li>Calcium (Ca\u00b2\u207a) would be <strong>[Ar]<\/strong>, which is 18 electrons.<\/li>\n\n\n\n<li><strong>Calcium (Ca)<\/strong> in neutral form has <strong>20 electrons<\/strong>, configuration <strong>[Ar] 4s\u00b2<\/strong>, but when it <strong>loses 1 electron<\/strong> (Ca\u207a), it has 19 electrons.<\/li>\n<\/ul>\n\n\n\n<p>But here, the <strong>neutral atom<\/strong> with <strong>19 electrons<\/strong> is <strong>Potassium (K)<\/strong>.<\/p>\n\n\n\n<p>However, their <strong>electron configurations<\/strong> are different:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ti\u00b3\u207a: [Ar] 3d\u00b9<\/li>\n\n\n\n<li>K: [Ar] 4s\u00b9<\/li>\n<\/ul>\n\n\n\n<p>Therefore, the correct <strong>isoelectronic partner<\/strong> of <strong>Ti\u00b3\u207a<\/strong> should have an electron configuration <strong>[Ar] 3d\u00b9<\/strong>.<\/p>\n\n\n\n<p>This matches the <strong>ground state of Scandium (Sc\u00b2\u207a)<\/strong>, which is not among the choices.<\/p>\n\n\n\n<p>But among the <strong>neutral atoms<\/strong> listed in the options, none are truly <strong>isoelectronic<\/strong> in terms of full configuration match.<\/p>\n\n\n\n<p>Hence, the best match among the given <strong>neutral elements<\/strong> in terms of <strong>electron count only<\/strong> is:<\/p>\n\n\n\n<p><strong>Correct answer: c) K<\/strong><\/p>\n\n\n\n<p>Because both <strong>Ti\u00b3\u207a and K<\/strong> have <strong>19 electrons<\/strong>, even though their <strong>orbital arrangement<\/strong> is different due to ionization and energy level differences.<\/p>\n\n\n\n<p>So, the correct <strong>isoelectronic partner by electron count<\/strong> is <strong>Potassium (K)<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"852\" height=\"1024\" src=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-8.jpeg\" alt=\"\" class=\"wp-image-24698\" srcset=\"https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-8.jpeg 852w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-8-250x300.jpeg 250w, https:\/\/gaviki.com\/blog\/wp-content\/uploads\/2025\/06\/learnexams-banner8-8-768x923.jpeg 768w\" sizes=\"auto, (max-width: 852px) 100vw, 852px\" \/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Write the ground state isoelectronic partner of the following elements &#8211; Ti3+ a) Ca b) Sc c) K The Correct Answer and Explanation is: Correct Answer: a) Ca Explanation: The term isoelectronic refers to atoms, ions, or molecules that have the same number of electrons and hence the same electronic configuration in their ground state. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-24697","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/24697","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=24697"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/24697\/revisions"}],"predecessor-version":[{"id":24699,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/24697\/revisions\/24699"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=24697"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=24697"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=24697"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}