{"id":23777,"date":"2025-06-17T21:34:41","date_gmt":"2025-06-17T21:34:41","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=23777"},"modified":"2025-06-17T21:34:43","modified_gmt":"2025-06-17T21:34:43","slug":"nbrs-n-is-central-number-of-total-electrons","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/nbrs-n-is-central-number-of-total-electrons\/","title":{"rendered":"NBrS (N is central) Number of total electrons"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">NBrS (N is central) Number of total electrons?Lewis structure?Bond order for N-BrBond order for N-S<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To analyze the molecule <strong>NBrS<\/strong> (with nitrogen as the central atom), we will follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udd22 <strong>1. Total Number of Valence Electrons<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Nitrogen (N)<\/strong>: 5 valence electrons<\/li>\n\n\n\n<li><strong>Bromine (Br)<\/strong>: 7 valence electrons<\/li>\n\n\n\n<li><strong>Sulfur (S)<\/strong>: 6 valence electrons<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Total = 5 + 7 + 6 = 18 valence electrons<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u270f\ufe0f <strong>2. Lewis Structure of NBrS<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Place <strong>N<\/strong> in the center (less electronegative than Br and S).<\/li>\n\n\n\n<li>Connect <strong>Br<\/strong> and <strong>S<\/strong> to <strong>N<\/strong> with single bonds initially.<\/li>\n\n\n\n<li>Subtract bonding electrons (2 per bond \u00d7 2 bonds = 4 electrons).<\/li>\n\n\n\n<li>Remaining = 18 \u2013 4 = <strong>14 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Distribute remaining 14 electrons to complete octets on terminal atoms (Br and S):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Br<\/strong> gets 6 electrons (3 lone pairs)<\/li>\n\n\n\n<li><strong>S<\/strong> gets 6 electrons (3 lone pairs)<br>Now <strong>N<\/strong> has only 4 electrons (from single bonds), so we add a <strong>lone pair<\/strong> (2 electrons) to nitrogen.<br>Total used: 6 (Br) + 6 (S) + 2 (N) + 4 (2 bonds) = <strong>18 electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">However, this gives nitrogen only 6 electrons total. Nitrogen tends to form multiple bonds to complete its octet.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Alternative structure<\/strong>: Add a <strong>double bond<\/strong> between <strong>N and S<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>N\u2013Br: single bond<\/li>\n\n\n\n<li>N=S: double bond<\/li>\n\n\n\n<li>This way, nitrogen has 8 electrons (1 single + 1 double + 1 lone pair = 8e\u207b)<\/li>\n\n\n\n<li>Formal charges are minimized:\n<ul class=\"wp-block-list\">\n<li>N: 5 valence \u2013 (2 lone + 3 bonding) = 0<\/li>\n\n\n\n<li>Br: 7 \u2013 (6 lone + 1 bond) = 0<\/li>\n\n\n\n<li>S: 6 \u2013 (4 lone + 2 bonds) = 0<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">\u2705 <strong>Correct Lewis Structure:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>Br \u2013 N = S\n     :\n<\/code><\/pre>\n\n\n\n<p class=\"wp-block-paragraph\">With lone pairs on Br, S, and one on N.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2696\ufe0f <strong>3. Bond Orders<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Bond order = number of bonding electron pairs \/ number of bonds<\/strong><\/li>\n\n\n\n<li><strong>N\u2013Br<\/strong>: single bond \u2192 bond order = <strong>1<\/strong><\/li>\n\n\n\n<li><strong>N=S<\/strong>: double bond \u2192 bond order = <strong>2<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83e\udde0 <strong>Summary<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Total valence electrons<\/strong>: 18<\/li>\n\n\n\n<li><strong>Lewis structure<\/strong>: Br\u2013N=S, with lone pairs to complete octets<\/li>\n\n\n\n<li><strong>Bond order N\u2013Br<\/strong>: 1<\/li>\n\n\n\n<li><strong>Bond order N\u2013S<\/strong>: 2<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">This structure satisfies the octet rule, minimizes formal charges, and correctly accounts for bonding.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NBrS (N is central) Number of total electrons?Lewis structure?Bond order for N-BrBond order for N-S The correct answer and explanation is: To analyze the molecule NBrS (with nitrogen as the central atom), we will follow these steps: \ud83d\udd22 1. Total Number of Valence Electrons Total = 5 + 7 + 6 = 18 valence electrons [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-23777","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/23777","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=23777"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/23777\/revisions"}],"predecessor-version":[{"id":23778,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/23777\/revisions\/23778"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=23777"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=23777"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=23777"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}