{"id":23059,"date":"2025-06-17T09:36:43","date_gmt":"2025-06-17T09:36:43","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=23059"},"modified":"2025-06-17T09:36:45","modified_gmt":"2025-06-17T09:36:45","slug":"how-many-lone-pairs-of-electrons-does-the-lewis-dot-structure-of-h2se-have-around-its-central-atom-and-what-is-the-shape-of-the-molecule","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/how-many-lone-pairs-of-electrons-does-the-lewis-dot-structure-of-h2se-have-around-its-central-atom-and-what-is-the-shape-of-the-molecule\/","title":{"rendered":"How many lone pairs of electrons does the Lewis dot structure of H2Se have around its central atom and what is the shape of the molecule"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">How many lone pairs of electrons does the Lewis dot structure of H2Se have around its central atom and what is the shape of the molecule? A. 2, tetrahedral B. 2, bent C. 1, triangular planar D. 0, linear<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answer: B. 2, bent<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the number of <strong>lone pairs<\/strong> around the central atom and the <strong>shape<\/strong> of the molecule H\u2082Se (hydrogen selenide), we follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Determine the total number of valence electrons:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Hydrogen (H):<\/strong> 1 valence electron \u00d7 2 = <strong>2<\/strong><\/li>\n\n\n\n<li><strong>Selenium (Se):<\/strong> Group 16 element = <strong>6<\/strong> valence electrons<br><strong>Total = 2 + 6 = 8 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Draw the Lewis structure:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Place <strong>Se<\/strong> as the <strong>central atom<\/strong>.<\/li>\n\n\n\n<li>Attach <strong>2 hydrogen atoms<\/strong> to Se using single bonds.<\/li>\n\n\n\n<li>Each single bond uses 2 electrons, so 2 \u00d7 2 = 4 electrons are used.<\/li>\n\n\n\n<li>This leaves 8 \u2013 4 = <strong>4 electrons<\/strong>, or <strong>2 lone pairs<\/strong>, which are placed on the Se atom.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, the Lewis structure has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 bonding pairs (H\u2013Se\u2013H)<\/li>\n\n\n\n<li>2 lone pairs on Se<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. Determine the molecular shape (VSEPR theory):<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The electron pair geometry is based on <strong>four regions of electron density<\/strong> (2 bonds + 2 lone pairs) around Se, which corresponds to a <strong>tetrahedral electron geometry<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">However, lone pairs <strong>do not count<\/strong> toward the molecular shape\u2014only the atoms do. With only two atoms bonded to Se, and two lone pairs, the molecular shape is:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\ud83d\udc49 <strong>Bent<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>4. Final Answer:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Number of lone pairs around Se:<\/strong> 2<\/li>\n\n\n\n<li><strong>Molecular shape:<\/strong> Bent<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, <strong>H\u2082Se<\/strong> is a <strong>bent molecule<\/strong> with <strong>two lone pairs<\/strong> on selenium. This bent shape gives H\u2082Se polar properties and a similar geometry to H\u2082O, due to the same electron pair distribution around the central atom.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u2705 <strong>Answer: B. 2, bent<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>How many lone pairs of electrons does the Lewis dot structure of H2Se have around its central atom and what is the shape of the molecule? A. 2, tetrahedral B. 2, bent C. 1, triangular planar D. 0, linear The correct answer and explanation is: Correct Answer: B. 2, bent Explanation: To determine the number [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-23059","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/23059","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=23059"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/23059\/revisions"}],"predecessor-version":[{"id":23060,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/23059\/revisions\/23060"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=23059"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=23059"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=23059"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}