{"id":22958,"date":"2025-06-17T08:37:10","date_gmt":"2025-06-17T08:37:10","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=22958"},"modified":"2025-06-17T08:37:12","modified_gmt":"2025-06-17T08:37:12","slug":"if-an-individual-who-is-homorygous-for-a-gene-mates-with-an-individual-who-is-heterorygous-for-the-same-gene-predict-what-percentage-of-the-offspring-with-be-heterorygous","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/if-an-individual-who-is-homorygous-for-a-gene-mates-with-an-individual-who-is-heterorygous-for-the-same-gene-predict-what-percentage-of-the-offspring-with-be-heterorygous\/","title":{"rendered":"If an individual who is homorygous for a gene mates with an individual who is heterorygous for the same gene predict what percentage of the offspring with be heterorygous"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">If an individual who is homorygous for a gene mates with an individual who is heterorygous for the same gene predict what percentage of the offspring with be heterorygous. \u25fb 50% None of the offspring will be heterorygous. 25% 75% 100%<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Correct Answer: \u25fb 50%<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To solve this problem, we must understand basic <strong>Mendelian genetics<\/strong>, specifically how alleles (forms of a gene) are inherited. Let&#8217;s denote:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A<\/strong> = dominant allele<\/li>\n\n\n\n<li><strong>a<\/strong> = recessive allele<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Identify the genotypes<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A <strong>homozygous<\/strong> individual has two identical alleles. There are two types: <strong>AA<\/strong> (homozygous dominant) or <strong>aa<\/strong> (homozygous recessive).<\/li>\n\n\n\n<li>A <strong>heterozygous<\/strong> individual has two different alleles: <strong>Aa<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">We will consider both cases where the homozygous individual could be <strong>AA<\/strong> or <strong>aa<\/strong>, since the question does not specify.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Case 1: Homozygous Dominant (AA) \u00d7 Heterozygous (Aa)<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Parent 1 (AA)<\/th><th>Parent 2 (Aa)<\/th><\/tr><\/thead><tbody><tr><td>A<\/td><td>A or a<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Possible offspring:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>A from AA parent + A from Aa = <strong>AA<\/strong><\/li>\n\n\n\n<li>A from AA parent + a from Aa = <strong>Aa<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, offspring genotypes:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>50% AA<\/strong> (homozygous dominant)<\/li>\n\n\n\n<li><strong>50% Aa<\/strong> (heterozygous)<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>\u2192 50% are heterozygous<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Case 2: Homozygous Recessive (aa) \u00d7 Heterozygous (Aa)<\/strong><\/h3>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><thead><tr><th>Parent 1 (aa)<\/th><th>Parent 2 (Aa)<\/th><\/tr><\/thead><tbody><tr><td>a<\/td><td>A or a<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Possible offspring:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>a from aa parent + A from Aa = <strong>Aa<\/strong><\/li>\n\n\n\n<li>a from aa parent + a from Aa = <strong>aa<\/strong><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">So, offspring genotypes:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>50% Aa<\/strong> (heterozygous)<\/li>\n\n\n\n<li><strong>50% aa<\/strong> (homozygous recessive)<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>\u2192 50% are heterozygous<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">In <strong>either case<\/strong> (AA or aa crossed with Aa), <strong>50%<\/strong> of the offspring will be <strong>heterozygous<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This result is consistent with Mendel&#8217;s law of segregation, which states that offspring receive one allele from each parent randomly.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u2705 <strong>Therefore, the correct answer is 50%.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>If an individual who is homorygous for a gene mates with an individual who is heterorygous for the same gene predict what percentage of the offspring with be heterorygous. \u25fb 50% None of the offspring will be heterorygous. 25% 75% 100% The correct answer and explanation is: Correct Answer: \u25fb 50% Explanation: To solve this [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-22958","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22958","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=22958"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22958\/revisions"}],"predecessor-version":[{"id":22959,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22958\/revisions\/22959"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=22958"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=22958"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=22958"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}