Subtract (3 + 2i) from (\u20139 \u2013 8i). \u201317 \u2013 5i \u20136 \u2013 6i \u201312 \u2013 10i 12 + 10<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n Correct Answer: \u201312 \u2013 10i<\/strong><\/p>\n\n\n\n We are asked to subtract the complex number (3 + 2i)<\/strong> from (\u20139 \u2013 8i)<\/strong>. To subtract complex numbers, subtract the real parts and then the imaginary parts separately.<\/p>\n\n\n\n \u20139\u20133=\u201312\u20139 \u2013 3 = \u201312<\/p>\n\n\n\n \u20138i\u20132i=\u201310i\u20138i \u2013 2i = \u201310i<\/p>\n\n\n\n \u201312\u201310i\\boxed{\u201312 \u2013 10i}<\/p>\n\n\n\n Complex numbers are composed of two parts: a real part<\/strong> and an imaginary part<\/strong>. The imaginary unit “i” is defined as the square root of \u20131. A complex number looks like this: In this problem, we are subtracting two complex numbers: The expression “subtract (3 + 2i) from (\u20139 \u2013 8i)”<\/strong> means we take the second number and subtract the first: (\u20139\u20138i)\u2013(3+2i)(\u20139 \u2013 8i) \u2013 (3 + 2i)<\/p>\n\n\n\n To solve this, we treat the real and imaginary parts separately. Next, handle the imaginary parts:<\/p>\n\n\n\n When we combine the results, we get: \u201312\u201310i\u201312 \u2013 10i<\/p>\n\n\n\n This is our final simplified answer. Subtracting complex numbers this way is similar to subtracting binomials: handle each part (real and imaginary) separately. This keeps your work clear and accurate.<\/p>\n\n\n\n \u2705 Answer: \u201312 \u2013 10i<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Subtract (3 + 2i) from (\u20139 \u2013 8i). \u201317 \u2013 5i \u20136 \u2013 6i \u201312 \u2013 10i 12 + 10 The correct answer and explanation is: Correct Answer: \u201312 \u2013 10i Step-by-step Calculation: We are asked to subtract the complex number (3 + 2i) from (\u20139 \u2013 8i).In math terms, this means: (\u20139\u20138i)\u2013(3+2i)(\u20139 \u2013 8i) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-22176","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22176","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=22176"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22176\/revisions"}],"predecessor-version":[{"id":22177,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22176\/revisions\/22177"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=22176"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=22176"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=22176"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep-by-step Calculation:<\/strong><\/h3>\n\n\n\n
In math terms, this means: (\u20139\u20138i)\u2013(3+2i)(\u20139 \u2013 8i) \u2013 (3 + 2i)<\/p>\n\n\n\n1. Subtract the real parts:<\/strong><\/h4>\n\n\n\n
2. Subtract the imaginary parts:<\/strong><\/h4>\n\n\n\n
Final Answer:<\/h3>\n\n\n\n
\n\n\n\n300-Word Explanation:<\/strong><\/h3>\n\n\n\n
a + bi<\/strong>, where a<\/strong> is the real part and b<\/strong> is the coefficient of the imaginary part.<\/p>\n\n\n\n
(\u20139 \u2013 8i)<\/strong> and (3 + 2i)<\/strong>.<\/p>\n\n\n\n
Start with the real parts:<\/p>\n\n\n\n\n
\n