What mass (in g) does 7.98 moles of Kr hare?<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n To find the mass (in grams) of 7.98 moles of krypton (Kr)<\/strong>, we use the formula: Mass=Moles\u00d7Molar Mass\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass}<\/p>\n\n\n\n From the periodic table, the atomic mass<\/strong> of krypton is: Molar Mass of Kr=83.80\u2009g\/mol\\text{Molar Mass of Kr} = 83.80 \\, \\text{g\/mol}<\/p>\n\n\n\n Mass=7.98\u2009mol\u00d783.80\u2009g\/mol\\text{Mass} = 7.98 \\, \\text{mol} \\times 83.80 \\, \\text{g\/mol} Mass=668.82\u2009g\\text{Mass} = 668.82 \\, \\text{g}<\/p>\n\n\n\n 668.82\u2009g\\boxed{668.82 \\, \\text{g}}<\/p>\n\n\n\n In chemistry, the mole<\/strong> is a standard scientific unit for measuring large quantities of very small entities like atoms or molecules. The molar mass<\/strong> tells us how much one mole of an element or compound weighs in grams. For elements, this value is numerically equal to the atomic mass listed on the periodic table.<\/p>\n\n\n\n Krypton (Kr) is a noble gas with an atomic number of 36. Its atomic mass is approximately 83.80 amu (atomic mass units), and this is also its molar mass<\/strong>, meaning one mole of krypton atoms weighs 83.80 grams.<\/p>\n\n\n\n To determine how much 7.98 moles of krypton weigh, we multiply the number of moles by the molar mass. This operation gives us the total mass<\/strong> of krypton in grams. Mass=Moles\u00d7Molar Mass=7.98\u00d783.80=668.82\u2009g\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass} = 7.98 \\times 83.80 = 668.82 \\, \\text{g}<\/p>\n\n\n\n This calculation is fundamental in chemistry, especially when preparing gases or calculating reactants and products in a chemical reaction.<\/p>\n\n\n\n Understanding mole-mass conversions helps in quantifying substances accurately, which is essential for laboratory experiments, industrial chemical production, and even environmental calculations involving gases in the atmosphere.<\/p>\n\n\n\n Thus, 7.98 moles of krypton weighs 668.82 grams.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" What mass (in g) does 7.98 moles of Kr hare? The correct answer and explanation is: To find the mass (in grams) of 7.98 moles of krypton (Kr), we use the formula: Mass=Moles\u00d7Molar Mass\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass} Step 1: Find the molar mass of krypton (Kr) From the periodic table, the atomic mass of […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-22096","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22096","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=22096"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22096\/revisions"}],"predecessor-version":[{"id":22097,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/22096\/revisions\/22097"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=22096"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=22096"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=22096"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep 1: Find the molar mass of krypton (Kr)<\/h3>\n\n\n\n
\n\n\n\nStep 2: Multiply moles by molar mass<\/h3>\n\n\n\n
\n\n\n\n\u2705 Final Answer:<\/h3>\n\n\n\n
\n\n\n\n\ud83d\udd0d 300-Word Explanation:<\/h3>\n\n\n\n