Correct Answers:<\/h3>\n\n\n\n\n- Structural Formula of Diisopentyl Ketone<\/strong>:
Diisopentyl ketone has the structure:
(CH\u2083)\u2082CHCH\u2082COCH\u2082CH(CH\u2083)\u2082<\/strong>
It is a ketone with two isopentyl (3-methylbutyl)<\/strong> groups attached to the carbonyl carbon.<\/li>\n\n\n\n- Structural Formula of 2,4-Pentanedione<\/strong>:
Also known as acetylacetone<\/strong>, the structure is:
CH\u2083COCH\u2082COCH\u2083<\/strong>
It has two ketone groups at carbon positions 2 and 4 in a 5-carbon chain.<\/li>\n\n\n\n- Oxime of Cyclopropanone<\/strong>:
Replace the carbonyl oxygen (C=O) of cyclopropanone with =N\u2013OH:
![\"Oxime](\"https:\/\/www.chemsynthesis.com\/base\/structure_diagrams\/924.gif\")
Structure:
Cyclopropyl\u2013C=NOH<\/strong> (where the C=NOH replaces the original carbonyl of cyclopropanone)<\/li>\n\n\n\n- Which compound is the tertiary (3\u00b0) amide?<\/strong>
Answer: None of the above.<\/strong>
A tertiary amide is defined as a compound with a carbonyl group (C=O) bonded to a nitrogen atom<\/strong> that is further bonded to two carbon groups<\/strong> (i.e., no hydrogen directly on nitrogen).
The given compounds \u2014 CH\u2083, NH\u2082, H\u2083C\u2013CH\u2082\u2013CH\u2083 \u2014 are not tertiary amides.<\/li>\n\n\n\n- Reaction of 1-Pentanol with Jones Reagent (CrO\u2083\/H\u2082SO\u2084)<\/strong>:
The reaction gives a carboxylic acid<\/strong>, specifically pentanoic acid<\/strong>.
Jones reagent is a strong oxidizing agent<\/strong>, and when reacting with primary alcohols<\/strong> like 1-pentanol, it oxidizes them all the way to carboxylic acids<\/strong>, not stopping at aldehydes.<\/li>\n<\/ol>\n\n\n\n
\n\n\n\nExplanation (300 words):<\/h3>\n\n\n\n
This question covers several key organic chemistry topics: ketone structure, diketones, oximes, functional groups, and oxidation reactions.<\/p>\n\n\n\n
1. Diisopentyl Ketone<\/strong>:
This is a symmetrical ketone where both sides of the carbonyl are bonded to isopentyl groups (3-methylbutyl). Recognizing the branched nature of isopentyl is key.<\/p>\n\n\n\n2. 2,4-Pentanedione<\/strong>:
This molecule is a beta-diketone. It has a notable chemical behavior, often undergoing keto-enol tautomerism. This structure is common in chelation chemistry due to its ability to bind metal ions.<\/p>\n\n\n\n3. Oximes<\/strong>:
An oxime forms when a ketone or aldehyde reacts with hydroxylamine (NH\u2082OH)<\/strong>. Cyclopropanone is a strained, highly reactive ketone. Its oxime has the formula cyclopropyl-C=NOH<\/strong>, and is less stable due to ring strain.<\/p>\n\n\n\n4. Tertiary Amides<\/strong>:
A tertiary amide must have no hydrogen atoms on the nitrogen. None of the provided fragments describe an amide structure, let alone a tertiary one.<\/p>\n\n\n\n5. Jones Oxidation<\/strong>:
Jones reagent is used to oxidize alcohols. Primary alcohols like 1-pentanol first form aldehydes but then proceed to carboxylic acids<\/strong> under the strong oxidative conditions. Only secondary alcohols<\/strong> are oxidized to ketones<\/strong>. Thus, the product here is pentanoic acid<\/strong>.<\/p>\n\n\n\nUnderstanding the nature of these functional groups and their reactions helps in mastering organic synthesis and compound identification.<\/p>\n","protected":false},"excerpt":{"rendered":"
Draw the structural formula of diisopentyl ketone. Draw the structural formula of 2,4-pentanedione. Draw the structure of the oxime of cyclopropanone. Which compound is the tertiary (3\u00c2\u00b0) amide? None of the above. CH3 NH2 H3C CH2 CH3 The reaction of 1-pentanol with Jones reagent (CrO3\/H2SO4) gives aldehyde, ketone, and carboxylic acid. The correct answer and […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-21793","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21793","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=21793"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21793\/revisions"}],"predecessor-version":[{"id":21794,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21793\/revisions\/21794"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=21793"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=21793"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=21793"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
Diisopentyl ketone has the structure:
(CH\u2083)\u2082CHCH\u2082COCH\u2082CH(CH\u2083)\u2082<\/strong>
It is a ketone with two isopentyl (3-methylbutyl)<\/strong> groups attached to the carbonyl carbon.<\/li>\n\n\n\n
Also known as acetylacetone<\/strong>, the structure is:
CH\u2083COCH\u2082COCH\u2083<\/strong>
It has two ketone groups at carbon positions 2 and 4 in a 5-carbon chain.<\/li>\n\n\n\n
Replace the carbonyl oxygen (C=O) of cyclopropanone with =N\u2013OH:
Structure:
Cyclopropyl\u2013C=NOH<\/strong> (where the C=NOH replaces the original carbonyl of cyclopropanone)<\/li>\n\n\n\n
Answer: None of the above.<\/strong>
A tertiary amide is defined as a compound with a carbonyl group (C=O) bonded to a nitrogen atom<\/strong> that is further bonded to two carbon groups<\/strong> (i.e., no hydrogen directly on nitrogen).
The given compounds \u2014 CH\u2083, NH\u2082, H\u2083C\u2013CH\u2082\u2013CH\u2083 \u2014 are not tertiary amides.<\/li>\n\n\n\n
The reaction gives a carboxylic acid<\/strong>, specifically pentanoic acid<\/strong>.
Jones reagent is a strong oxidizing agent<\/strong>, and when reacting with primary alcohols<\/strong> like 1-pentanol, it oxidizes them all the way to carboxylic acids<\/strong>, not stopping at aldehydes.<\/li>\n<\/ol>\n\n\n\n
\n\n\n\n
Explanation (300 words):<\/h3>\n\n\n\n
This question covers several key organic chemistry topics: ketone structure, diketones, oximes, functional groups, and oxidation reactions.<\/p>\n\n\n\n
1. Diisopentyl Ketone<\/strong>: 2. 2,4-Pentanedione<\/strong>: 3. Oximes<\/strong>: 4. Tertiary Amides<\/strong>: 5. Jones Oxidation<\/strong>: Understanding the nature of these functional groups and their reactions helps in mastering organic synthesis and compound identification.<\/p>\n","protected":false},"excerpt":{"rendered":" Draw the structural formula of diisopentyl ketone. Draw the structural formula of 2,4-pentanedione. Draw the structure of the oxime of cyclopropanone. Which compound is the tertiary (3\u00c2\u00b0) amide? None of the above. CH3 NH2 H3C CH2 CH3 The reaction of 1-pentanol with Jones reagent (CrO3\/H2SO4) gives aldehyde, ketone, and carboxylic acid. The correct answer and […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-21793","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21793","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=21793"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21793\/revisions"}],"predecessor-version":[{"id":21794,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21793\/revisions\/21794"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=21793"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=21793"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=21793"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
This is a symmetrical ketone where both sides of the carbonyl are bonded to isopentyl groups (3-methylbutyl). Recognizing the branched nature of isopentyl is key.<\/p>\n\n\n\n
This molecule is a beta-diketone. It has a notable chemical behavior, often undergoing keto-enol tautomerism. This structure is common in chelation chemistry due to its ability to bind metal ions.<\/p>\n\n\n\n
An oxime forms when a ketone or aldehyde reacts with hydroxylamine (NH\u2082OH)<\/strong>. Cyclopropanone is a strained, highly reactive ketone. Its oxime has the formula cyclopropyl-C=NOH<\/strong>, and is less stable due to ring strain.<\/p>\n\n\n\n
A tertiary amide must have no hydrogen atoms on the nitrogen. None of the provided fragments describe an amide structure, let alone a tertiary one.<\/p>\n\n\n\n
Jones reagent is used to oxidize alcohols. Primary alcohols like 1-pentanol first form aldehydes but then proceed to carboxylic acids<\/strong> under the strong oxidative conditions. Only secondary alcohols<\/strong> are oxidized to ketones<\/strong>. Thus, the product here is pentanoic acid<\/strong>.<\/p>\n\n\n\n