{"id":21704,"date":"2025-06-16T06:18:37","date_gmt":"2025-06-16T06:18:37","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=21704"},"modified":"2025-06-16T06:18:42","modified_gmt":"2025-06-16T06:18:42","slug":"what-is-the-mass-in-grams-of-34-5-mol-of-copper-1-sulfat","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-mass-in-grams-of-34-5-mol-of-copper-1-sulfat\/","title":{"rendered":"what is the mass in grams of 34.5 mol of copper (1) sulfat"},"content":{"rendered":"\n<p>what is the mass in grams of 34.5 mol of copper (1) sulfate<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p>To find the <strong>mass in grams<\/strong> of <strong>34.5 mol<\/strong> of <strong>copper(I) sulfate (Cu\u2082SO\u2084)<\/strong>, we use the formula: Mass=Moles\u00d7Molar&nbsp;Mass\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Determine the Molar Mass of Copper(I) Sulfate (Cu\u2082SO\u2084)<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Cu (Copper):<\/strong> 63.55 g\/mol<\/li>\n\n\n\n<li><strong>S (Sulfur):<\/strong> 32.07 g\/mol<\/li>\n\n\n\n<li><strong>O\u2084 (Oxygen):<\/strong> 16.00 \u00d7 4 = 64.00 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Molar&nbsp;Mass&nbsp;of&nbsp;Cu\u2082SO\u2084=(63.55\u00d72)+32.07+64.00=127.10+32.07+64.00=223.17&nbsp;g\/mol\\text{Molar Mass of Cu\u2082SO\u2084} = (63.55 \\times 2) + 32.07 + 64.00 = 127.10 + 32.07 + 64.00 = 223.17 \\text{ g\/mol}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Multiply by the Number of Moles<\/h3>\n\n\n\n<p>Mass=34.5&nbsp;mol\u00d7223.17&nbsp;g\/mol=7709.37&nbsp;grams\\text{Mass} = 34.5 \\text{ mol} \\times 223.17 \\text{ g\/mol} = 7709.37 \\text{ grams}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer:<\/h3>\n\n\n\n<p>7709.37&nbsp;grams\\boxed{7709.37 \\text{ grams}}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udca1 Explanation (300 words):<\/h3>\n\n\n\n<p>To calculate the mass of a substance from the number of moles, you multiply the number of moles by the molar mass of the substance. This is because <strong>one mole<\/strong> of any substance contains <strong>Avogadro\u2019s number<\/strong> of particles (6.022 \u00d7 10\u00b2\u00b3) and weighs exactly its <strong>molar mass in grams<\/strong>.<\/p>\n\n\n\n<p>In this question, the substance is <strong>copper(I) sulfate<\/strong>, which has the chemical formula <strong>Cu\u2082SO\u2084<\/strong>. This formula indicates that each formula unit contains <strong>2 atoms of copper (Cu)<\/strong>, <strong>1 atom of sulfur (S)<\/strong>, and <strong>4 atoms of oxygen (O)<\/strong>.<\/p>\n\n\n\n<p>Using the periodic table:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Copper has a molar mass of about <strong>63.55 g\/mol<\/strong>.<\/li>\n\n\n\n<li>Sulfur is <strong>32.07 g\/mol<\/strong>.<\/li>\n\n\n\n<li>Oxygen is <strong>16.00 g\/mol<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Adding them up: (2\u00d763.55)+32.07+(4\u00d716.00)=223.17&nbsp;g\/mol(2 \\times 63.55) + 32.07 + (4 \\times 16.00) = 223.17 \\text{ g\/mol}<\/p>\n\n\n\n<p>This means that <strong>1 mole<\/strong> of Cu\u2082SO\u2084 weighs <strong>223.17 grams<\/strong>.<\/p>\n\n\n\n<p>Now, you are given <strong>34.5 moles<\/strong> of Cu\u2082SO\u2084. Multiply: 34.5&nbsp;mol\u00d7223.17&nbsp;g\/mol=7709.37&nbsp;grams34.5 \\text{ mol} \\times 223.17 \\text{ g\/mol} = 7709.37 \\text{ grams}<\/p>\n\n\n\n<p>So, the mass of 34.5 moles of copper(I) sulfate is <strong>7709.37 grams<\/strong>. This is a direct application of the molar relationship between amount and mass in chemistry.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>what is the mass in grams of 34.5 mol of copper (1) sulfate The correct answer and explanation is: To find the mass in grams of 34.5 mol of copper(I) sulfate (Cu\u2082SO\u2084), we use the formula: Mass=Moles\u00d7Molar&nbsp;Mass\\text{Mass} = \\text{Moles} \\times \\text{Molar Mass} Step 1: Determine the Molar Mass of Copper(I) Sulfate (Cu\u2082SO\u2084) Molar&nbsp;Mass&nbsp;of&nbsp;Cu\u2082SO\u2084=(63.55\u00d72)+32.07+64.00=127.10+32.07+64.00=223.17&nbsp;g\/mol\\text{Molar Mass of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-21704","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21704","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=21704"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21704\/revisions"}],"predecessor-version":[{"id":21705,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21704\/revisions\/21705"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=21704"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=21704"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=21704"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}