What do you predict for the height of a barometer column based on 1-iodododecane, when the atmospheric pressure is 749 torr ?<\/p>\n\n\n\n
The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n To predict the height of a barometer column based on 1-iodododecane<\/strong> when the atmospheric pressure is 749 torr<\/strong>, we need to understand the relationship between pressure, liquid density, and column height in a barometer.<\/p>\n\n\n\n The barometric formula<\/strong> relates pressure to height and density: P=\u03c1ghP = \\rho g h<\/p>\n\n\n\n Where:<\/p>\n\n\n\n Since 1\u2009torr=133.322\u2009Pa1 \\, \\text{torr} = 133.322 \\, \\text{Pa}: P=749\u2009torr\u00d7133.322\u2009Patorr=99,838.2\u2009PaP = 749 \\, \\text{torr} \\times 133.322 \\, \\frac{\\text{Pa}}{\\text{torr}} = 99,838.2 \\, \\text{Pa}<\/p>\n\n\n\n The density of 1-iodododecane<\/strong> is approximately: \u03c1\u22481.198\u2009g\/cm3=1198\u2009kg\/m3\\rho \\approx 1.198 \\, \\text{g\/cm}^3 = 1198 \\, \\text{kg\/m}^3<\/p>\n\n\n\n Rearranging the formula: h=P\u03c1g=99,838.21198\u00d79.81\u224899,838.211,751.38\u22488.5\u2009mh = \\frac{P}{\\rho g} = \\frac{99,838.2}{1198 \\times 9.81} \\approx \\frac{99,838.2}{11,751.38} \\approx 8.5 \\, \\text{m}<\/p>\n\n\n\n The predicted height<\/strong> of a barometer column based on 1-iodododecane<\/strong> at 749 torr<\/strong> is approximately 8.5 meters<\/strong>.<\/p>\n\n\n\n Barometers operate on the principle of balancing the atmospheric pressure with the weight of a liquid column. When a liquid is placed in a closed tube and exposed to atmospheric pressure, the liquid rises until the weight of the column balances the external pressure.<\/p>\n\n\n\n The height a liquid reaches depends on its density<\/strong>\u2014denser liquids rise to shorter heights<\/strong>, while less dense ones rise higher<\/strong> to balance the same pressure.<\/p>\n\n\n\n In this problem, we use 1-iodododecane, an organic compound with a relatively high density (~1.198 g\/cm\u00b3), but still much less dense than mercury (13.6 g\/cm\u00b3), which is typically used in barometers. Because 1-iodododecane is less dense, the column must be much taller than a mercury column to balance the same atmospheric pressure.<\/p>\n\n\n\n We convert atmospheric pressure from torr to pascals, ensuring all units are SI-compatible. Using the barometric formula P=\u03c1ghP = \\rho g h, we isolate hh, plug in the known pressure, density, and gravitational constant, and solve. The result (about 8.5 meters<\/strong>) is significantly taller than a mercury barometer column (typically ~0.76 m at sea level), illustrating how fluid density impacts barometer design.<\/p>\n\n\n\n In real-world applications, this is why mercury is preferred despite its toxicity\u2014it allows for compact, manageable devices. However, understanding how other fluids behave helps in designing safer or specialized instruments.<\/p>\n","protected":false},"excerpt":{"rendered":" What do you predict for the height of a barometer column based on 1-iodododecane, when the atmospheric pressure is 749 torr ? The correct answer and explanation is: To predict the height of a barometer column based on 1-iodododecane when the atmospheric pressure is 749 torr, we need to understand the relationship between pressure, liquid […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-21518","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21518","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=21518"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21518\/revisions"}],"predecessor-version":[{"id":21519,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/21518\/revisions\/21519"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=21518"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=21518"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=21518"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\n\n\n\nStep-by-Step Solution:<\/strong><\/h3>\n\n\n\n
\n
\n\n\n\nStep 1: Convert Pressure to Pascals<\/strong><\/h3>\n\n\n\n
\n\n\n\nStep 2: Find the Density of 1-iodododecane<\/strong><\/h3>\n\n\n\n
\n\n\n\nStep 3: Solve for Height<\/strong><\/h3>\n\n\n\n
\n\n\n\n\u2705 Final Answer:<\/strong><\/h3>\n\n\n\n
\n\n\n\nExplanation (300 words):<\/strong><\/h3>\n\n\n\n