{"id":20410,"date":"2025-06-14T12:33:54","date_gmt":"2025-06-14T12:33:54","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=20410"},"modified":"2025-06-14T12:34:10","modified_gmt":"2025-06-14T12:34:10","slug":"the-least-polar-bond-is-found-in-a-molecule-of-hi-hf-hcl-hbr","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/the-least-polar-bond-is-found-in-a-molecule-of-hi-hf-hcl-hbr\/","title":{"rendered":"The least polar bond is found in a molecule of HI, HF, HCl, HBr"},"content":{"rendered":"\n<p>The least polar bond is found in a molecule of HI, HF, HCl, HBr.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer: HI (hydrogen iodide)<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words):<\/h3>\n\n\n\n<p>To determine the <strong>least polar bond<\/strong> among the molecules HI, HF, HCl, and HBr, we need to understand <strong>bond polarity<\/strong>, which depends on the <strong>difference in electronegativity<\/strong> between the two bonded atoms.<\/p>\n\n\n\n<p>Electronegativity is a measure of an atom\u2019s ability to attract electrons in a chemical bond. The greater the difference in electronegativity between two atoms, the more polar the bond.<\/p>\n\n\n\n<p>Hydrogen (H) has an electronegativity of <strong>2.1<\/strong>. The halogens involved have the following electronegativities:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>F (fluorine): 4.0<\/strong><\/li>\n\n\n\n<li><strong>Cl (chlorine): 3.0<\/strong><\/li>\n\n\n\n<li><strong>Br (bromine): 2.8<\/strong><\/li>\n\n\n\n<li><strong>I (iodine): 2.5<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Now, let\u2019s calculate the electronegativity differences:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>HF<\/strong>: |4.0 &#8211; 2.1| = <strong>1.9<\/strong> \u2192 <strong>Most polar<\/strong><\/li>\n\n\n\n<li><strong>HCl<\/strong>: |3.0 &#8211; 2.1| = <strong>0.9<\/strong><\/li>\n\n\n\n<li><strong>HBr<\/strong>: |2.8 &#8211; 2.1| = <strong>0.7<\/strong><\/li>\n\n\n\n<li><strong>HI<\/strong>: |2.5 &#8211; 2.1| = <strong>0.4<\/strong> \u2192 <strong>Least polar<\/strong><\/li>\n<\/ul>\n\n\n\n<p>Therefore, <strong>HI has the smallest electronegativity difference<\/strong>, making it the <strong>least polar bond<\/strong> among the given molecules.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Why Polarity Matters:<\/h3>\n\n\n\n<p>Polarity affects many physical and chemical properties such as <strong>boiling point, solubility, dipole moment<\/strong>, and <strong>reactivity<\/strong>. More polar molecules (like HF) often have higher boiling points and stronger intermolecular forces due to stronger dipole-dipole interactions.<\/p>\n\n\n\n<p>In contrast, a molecule like HI, with a less polar bond, has <strong>weaker dipole interactions<\/strong> and behaves more like a nonpolar molecule in certain conditions.<\/p>\n\n\n\n<p>In summary, <strong>HI<\/strong> has the <strong>least polar bond<\/strong> because the electronegativity difference between hydrogen and iodine is the smallest among the four options.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The least polar bond is found in a molecule of HI, HF, HCl, HBr. The correct answer and explanation is: Correct Answer: HI (hydrogen iodide) Explanation (300 words): To determine the least polar bond among the molecules HI, HF, HCl, and HBr, we need to understand bond polarity, which depends on the difference in electronegativity [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-20410","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/20410","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=20410"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/20410\/revisions"}],"predecessor-version":[{"id":20411,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/20410\/revisions\/20411"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=20410"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=20410"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=20410"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}