{"id":19855,"date":"2025-06-13T21:54:54","date_gmt":"2025-06-13T21:54:54","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=19855"},"modified":"2025-06-13T21:54:55","modified_gmt":"2025-06-13T21:54:55","slug":"water-has-a-mass-per-mole-of-18-0-g-mol","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/water-has-a-mass-per-mole-of-18-0-g-mol\/","title":{"rendered":"Water has a mass per mole of 18.0 g\/mol"},"content":{"rendered":"\n<p>Water has a mass per mole of 18.0 g\/mol, and each molecule (H2O) has 10 electrons a)How many electrons are there in 9.68 liters of water? What is the net charge of all these electrons<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s analyze the problem step-by-step.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Given data:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass of water, M=18.0\u2009g\/molM = 18.0 \\, g\/mol<\/li>\n\n\n\n<li>Each water molecule (H\u2082O) has 10 electrons<\/li>\n\n\n\n<li>Volume of water = 9.68 liters<\/li>\n\n\n\n<li>We want to find:\n<ul class=\"wp-block-list\">\n<li>(a) Number of electrons in 9.68 liters of water<\/li>\n\n\n\n<li>Net charge of all these electrons<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Find the mass of water in 9.68 L<\/h3>\n\n\n\n<p>Water has a density close to 1.00\u2009g\/cm31.00 \\, g\/cm^3 or 1.00\u2009g\/mL1.00 \\, g\/mL.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>1\u2009L=1000\u2009mL1 \\, L = 1000 \\, mL<\/li>\n\n\n\n<li>Therefore, Mass\u00a0of\u00a0water=9.68\u2009L\u00d71000\u2009mL\/L\u00d71.00\u2009g\/mL=9680\u2009g\\text{Mass of water} = 9.68 \\, L \\times 1000 \\, mL\/L \\times 1.00 \\, g\/mL = 9680 \\, g<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate moles of water<\/h3>\n\n\n\n<p>Using the molar mass: Moles&nbsp;of&nbsp;water=massmolar&nbsp;mass=9680\u2009g18.0\u2009g\/mol\u2248538.89\u2009mol\\text{Moles of water} = \\frac{\\text{mass}}{\\text{molar mass}} = \\frac{9680 \\, g}{18.0 \\, g\/mol} \\approx 538.89 \\, mol<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate number of water molecules<\/h3>\n\n\n\n<p>Using Avogadro&#8217;s number: NA=6.022\u00d71023&nbsp;molecules\/molN_A = 6.022 \\times 10^{23} \\text{ molecules\/mol} Number&nbsp;of&nbsp;molecules=538.89\u2009mol\u00d76.022\u00d71023\u2009molecules\/mol\u22483.24\u00d71026&nbsp;molecules\\text{Number of molecules} = 538.89 \\, mol \\times 6.022 \\times 10^{23} \\, molecules\/mol \\approx 3.24 \\times 10^{26} \\text{ molecules}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Calculate number of electrons<\/h3>\n\n\n\n<p>Each water molecule has 10 electrons: Number&nbsp;of&nbsp;electrons=3.24\u00d71026\u00d710=3.24\u00d71027&nbsp;electrons\\text{Number of electrons} = 3.24 \\times 10^{26} \\times 10 = 3.24 \\times 10^{27} \\text{ electrons}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 5: Calculate net charge of all electrons<\/h3>\n\n\n\n<p>Charge of one electron is approximately: e=\u22121.602\u00d710\u221219\u2009Ce = -1.602 \\times 10^{-19} \\, C<\/p>\n\n\n\n<p>Therefore: Net&nbsp;charge=3.24\u00d71027\u00d7(\u22121.602\u00d710\u221219)=\u22125.19\u00d7108\u2009C\\text{Net charge} = 3.24 \\times 10^{27} \\times (-1.602 \\times 10^{-19}) = -5.19 \\times 10^{8} \\, C<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final answers:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Number of electrons in 9.68 L of water: 3.24\u00d71027\u00a0electrons\\boxed{3.24 \\times 10^{27} \\text{ electrons}}<\/li>\n\n\n\n<li>Net charge of all electrons: \u22125.19\u00d7108\u2009coulombs\u00a0(C)\\boxed{-5.19 \\times 10^{8} \\, \\text{coulombs (C)}}<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Water molecules contain electrons that carry a negative electric charge. To find how many electrons are in a specific volume of water, we first calculate the total mass using water&#8217;s density, then convert that mass into moles by dividing by the molar mass of water. Using Avogadro\u2019s number, which tells us how many molecules are in one mole, we find the total number of water molecules. Multiplying by the number of electrons per molecule gives the total electrons.<\/p>\n\n\n\n<p>The net charge is then calculated by multiplying the number of electrons by the charge of one electron (which is negative). The result is a very large negative charge because the number of electrons in even a small volume of water is enormous. This illustrates how electrically neutral matter contains a huge number of charged particles, but their charges balance out to net zero overall (since protons have positive charge to balance the electrons in neutral water molecules).<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Water has a mass per mole of 18.0 g\/mol, and each molecule (H2O) has 10 electrons a)How many electrons are there in 9.68 liters of water? What is the net charge of all these electrons The correct answer and explanation is: Let&#8217;s analyze the problem step-by-step. Given data: Step 1: Find the mass of water [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-19855","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19855","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=19855"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19855\/revisions"}],"predecessor-version":[{"id":19856,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19855\/revisions\/19856"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=19855"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=19855"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=19855"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}