{"id":19455,"date":"2025-06-13T18:49:13","date_gmt":"2025-06-13T18:49:13","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=19455"},"modified":"2025-06-13T18:49:14","modified_gmt":"2025-06-13T18:49:14","slug":"a-deer-accelerates-at-a-constant-rate-from-0-mph-to-29-mph-in-20-seconds","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/a-deer-accelerates-at-a-constant-rate-from-0-mph-to-29-mph-in-20-seconds\/","title":{"rendered":"A deer accelerates at a constant rate from 0 mph to 29 mph in 20 seconds"},"content":{"rendered":"\n<p>A deer accelerates at a constant rate from 0 mph to 29 mph in 20 seconds. How far does the deer run during this time? A. 0.0806 mi B. 0.1611 mi C. 0.1208 mi D. 0.4833 mi<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer: <strong>B. 0.1611 mi<\/strong><\/h3>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step-by-Step Explanation:<\/strong><\/h3>\n\n\n\n<p>We are given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Initial velocity vi=0v_i = 0 mph<\/li>\n\n\n\n<li>Final velocity vf=29v_f = 29 mph<\/li>\n\n\n\n<li>Time t=20t = 20 seconds<\/li>\n\n\n\n<li>We are to find the <strong>distance in miles<\/strong> that the deer runs during this time while accelerating <strong>at a constant rate<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Use the average velocity formula<\/strong><\/h3>\n\n\n\n<p>Since the deer is accelerating <strong>uniformly<\/strong>, the average speed is: vavg=vi+vf2=0+292=14.5&nbsp;mphv_{avg} = \\frac{v_i + v_f}{2} = \\frac{0 + 29}{2} = 14.5 \\text{ mph}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Convert time from seconds to hours<\/strong><\/h3>\n\n\n\n<p>20&nbsp;seconds=203600&nbsp;hours=1180&nbsp;hours20 \\text{ seconds} = \\frac{20}{3600} \\text{ hours} = \\frac{1}{180} \\text{ hours}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Use the formula for distance<\/strong><\/h3>\n\n\n\n<p>Distance=vavg\u00d7t\\text{Distance} = v_{avg} \\times t Distance=14.5\u2009mph\u00d71180\u2009hr=14.5180\u22480.0806\u2009miles\\text{Distance} = 14.5 \\, \\text{mph} \\times \\frac{1}{180} \\, \\text{hr} = \\frac{14.5}{180} \\approx 0.0806 \\, \\text{miles}<\/p>\n\n\n\n<p>Wait! That gives us option <strong>A<\/strong>, but that\u2019s assuming <strong>average velocity<\/strong>. Let\u2019s double-check using <strong>kinematics<\/strong> in consistent units.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Alternate Method (More Accurate): Use SI Units<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">Convert 29 mph to meters per second:<\/h4>\n\n\n\n<p>29\u2009mph\u00d71609.34\u2009m1\u2009mile\u00d713600\u2009s\u224812.96\u2009m\/s29 \\, \\text{mph} \\times \\frac{1609.34 \\, \\text{m}}{1 \\, \\text{mile}} \\times \\frac{1}{3600 \\, \\text{s}} \\approx 12.96 \\, \\text{m\/s}<\/p>\n\n\n\n<p>Then use the formula: Distance=12vt=12\u00d712.96\u2009m\/s\u00d720\u2009s=129.6\u2009m\\text{Distance} = \\frac{1}{2} v t = \\frac{1}{2} \\times 12.96 \\, \\text{m\/s} \\times 20 \\, \\text{s} = 129.6 \\, \\text{m}<\/p>\n\n\n\n<p>Convert meters to miles: 129.6\u2009m\u00d71\u2009mile1609.34\u2009m\u22480.0806\u2009mi129.6 \\, \\text{m} \\times \\frac{1 \\, \\text{mile}}{1609.34 \\, \\text{m}} \\approx 0.0806 \\, \\text{mi}<\/p>\n\n\n\n<p>\u2705 Confirms that <strong>option A<\/strong> is actually correct.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Final Answer: <strong>A. 0.0806 mi<\/strong><\/h3>\n\n\n\n<p>The deer runs approximately <strong>0.0806 miles<\/strong> during the 20-second acceleration.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A deer accelerates at a constant rate from 0 mph to 29 mph in 20 seconds. How far does the deer run during this time? A. 0.0806 mi B. 0.1611 mi C. 0.1208 mi D. 0.4833 mi The correct answer and explanation is: Correct Answer: B. 0.1611 mi Step-by-Step Explanation: We are given: Step 1: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-19455","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19455","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=19455"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19455\/revisions"}],"predecessor-version":[{"id":19456,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19455\/revisions\/19456"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=19455"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=19455"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=19455"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}