{"id":19296,"date":"2025-06-13T15:25:06","date_gmt":"2025-06-13T15:25:06","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=19296"},"modified":"2025-06-13T15:25:16","modified_gmt":"2025-06-13T15:25:16","slug":"what-is-the-average-molar-mass-of-a-mixture-containing-3-mol-of-propane-and-1-mol-of-hydrogen","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-average-molar-mass-of-a-mixture-containing-3-mol-of-propane-and-1-mol-of-hydrogen\/","title":{"rendered":"What is the average molar mass of a mixture containing 3 mol of propane and 1 mol of hydrogen"},"content":{"rendered":"\n<p>What is the average molar mass of a mixture containing 3 mol of propane and 1 mol of hydrogen? The molar mass of C3H8 is 44.0 g\/mol. the molar mass of H2 is 2.0 g\/mol.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p>Let&#8217;s solve the problem step-by-step:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Problem Recap:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>You have a mixture with:\n<ul class=\"wp-block-list\">\n<li>3 moles of propane (C\u2083H\u2088), molar mass = 44.0 g\/mol<\/li>\n\n\n\n<li>1 mole of hydrogen (H\u2082), molar mass = 2.0 g\/mol<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>You need to find the <strong>average molar mass<\/strong> of the mixture.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Calculate total moles in the mixture<\/h3>\n\n\n\n<p>Total&nbsp;moles=3+1=4&nbsp;moles\\text{Total moles} = 3 + 1 = 4 \\text{ moles}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate total mass of each component<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of propane:<\/li>\n<\/ul>\n\n\n\n<p>3&nbsp;mol\u00d744.0&nbsp;g\/mol=132.0&nbsp;g3 \\text{ mol} \\times 44.0 \\text{ g\/mol} = 132.0 \\text{ g}<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mass of hydrogen:<\/li>\n<\/ul>\n\n\n\n<p>1&nbsp;mol\u00d72.0&nbsp;g\/mol=2.0&nbsp;g1 \\text{ mol} \\times 2.0 \\text{ g\/mol} = 2.0 \\text{ g}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate total mass of the mixture<\/h3>\n\n\n\n<p>132.0&nbsp;g+2.0&nbsp;g=134.0&nbsp;g132.0 \\text{ g} + 2.0 \\text{ g} = 134.0 \\text{ g}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Calculate average molar mass of the mixture<\/h3>\n\n\n\n<p>Average molar mass is total mass divided by total moles: Average&nbsp;molar&nbsp;mass=Total&nbsp;massTotal&nbsp;moles=134.0&nbsp;g4&nbsp;mol=33.5&nbsp;g\/mol\\text{Average molar mass} = \\frac{\\text{Total mass}}{\\text{Total moles}} = \\frac{134.0 \\text{ g}}{4 \\text{ mol}} = 33.5 \\text{ g\/mol}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>33.5&nbsp;g\/mol\\boxed{33.5 \\text{ g\/mol}}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words):<\/h3>\n\n\n\n<p>The average molar mass of a mixture is the weighted average based on the amount (in moles) of each component and their respective molar masses. In this case, the mixture contains propane (C\u2083H\u2088) and hydrogen (H\u2082).<\/p>\n\n\n\n<p>Propane has a molar mass of 44.0 g\/mol, which means one mole of propane weighs 44.0 grams. Hydrogen gas, being much lighter, has a molar mass of only 2.0 g\/mol. When combining different substances, the total mass is additive \u2014 the sum of each component&#8217;s mass. Similarly, the total moles is the sum of moles of each gas.<\/p>\n\n\n\n<p>Since there are 3 moles of propane and 1 mole of hydrogen, the total moles are 4. The total mass is calculated by multiplying the moles of each gas by its molar mass and then summing:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Propane contributes 3 moles \u00d7 44.0 g\/mol = 132.0 g<\/li>\n\n\n\n<li>Hydrogen contributes 1 mole \u00d7 2.0 g\/mol = 2.0 g<\/li>\n<\/ul>\n\n\n\n<p>Adding these, the total mass of the mixture is 134.0 grams.<\/p>\n\n\n\n<p>To find the average molar mass of the mixture, you divide the total mass by total moles: Average&nbsp;molar&nbsp;mass=134.0&nbsp;g4&nbsp;mol=33.5&nbsp;g\/mol\\text{Average molar mass} = \\frac{134.0 \\text{ g}}{4 \\text{ mol}} = 33.5 \\text{ g\/mol}<\/p>\n\n\n\n<p>This value lies between the two molar masses and is closer to propane\u2019s molar mass since propane is present in a greater amount. The average molar mass provides a meaningful single molar mass representing the entire mixture, useful in further calculations such as determining the mixture\u2019s density, reaction stoichiometry, or other physical properties.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the average molar mass of a mixture containing 3 mol of propane and 1 mol of hydrogen? The molar mass of C3H8 is 44.0 g\/mol. the molar mass of H2 is 2.0 g\/mol. The correct answer and explanation is: Let&#8217;s solve the problem step-by-step: Problem Recap: Step 1: Calculate total moles in the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-19296","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19296","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=19296"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19296\/revisions"}],"predecessor-version":[{"id":19297,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/19296\/revisions\/19297"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=19296"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=19296"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=19296"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}