{"id":18810,"date":"2025-06-13T09:34:15","date_gmt":"2025-06-13T09:34:15","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=18810"},"modified":"2025-06-13T09:34:18","modified_gmt":"2025-06-13T09:34:18","slug":"what-is-the-electronic-geometry-and-molecular-geometry-of-the-hypophosphite-ion-po23","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/what-is-the-electronic-geometry-and-molecular-geometry-of-the-hypophosphite-ion-po23\/","title":{"rendered":"What is the electronic geometry and molecular geometry of the hypophosphite ion (PO2^3-)"},"content":{"rendered":"\n<p>What is the electronic geometry and molecular geometry of the hypophosphite ion (PO2^3-)? Can you please provide an explanation also.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p><strong>Correct Answer:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Electronic Geometry:<\/strong> Tetrahedral<\/li>\n\n\n\n<li><strong>Molecular Geometry:<\/strong> Trigonal pyramidal<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words):<\/strong><\/h3>\n\n\n\n<p>The <strong>hypophosphite ion (PO\u2082\u00b3\u207b)<\/strong> consists of a central <strong>phosphorus (P)<\/strong> atom bonded to <strong>two oxygen atoms<\/strong>, with a <strong>formal charge of \u20133<\/strong> distributed over the ion.<\/p>\n\n\n\n<p>Let\u2019s go step-by-step to determine the <strong>electronic and molecular geometry<\/strong>:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 1: Count Valence Electrons<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Phosphorus (P) has 5 valence electrons.<\/li>\n\n\n\n<li>Each oxygen (O) has 6 valence electrons, for a total of 2 \u00d7 6 = 12.<\/li>\n\n\n\n<li>Add 3 electrons for the \u20133 charge.<\/li>\n\n\n\n<li><strong>Total = 5 (P) + 12 (O) + 3 (charge) = 20 valence electrons<\/strong><\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 2: Draw the Lewis Structure<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Place phosphorus in the center.<\/li>\n\n\n\n<li>Attach two oxygen atoms to phosphorus using single bonds (2 \u00d7 2 = 4 electrons).<\/li>\n\n\n\n<li>Complete octets of both oxygen atoms by adding lone pairs (2 \u00d7 6 = 12 electrons).<\/li>\n\n\n\n<li>This accounts for 16 electrons; 4 remain.<\/li>\n\n\n\n<li>These remaining electrons go as <strong>a lone pair on phosphorus<\/strong>.<\/li>\n\n\n\n<li>So, phosphorus has 3 regions: 2 bonding pairs (P\u2013O bonds) and 1 lone pair.<\/li>\n<\/ul>\n\n\n\n<p>Note: One oxygen is likely doubly bonded to reduce formal charges, making the bonding situation P=O and P\u2013O\u207b. Still, from a <strong>VSEPR<\/strong> (Valence Shell Electron Pair Repulsion) perspective, we count <strong>regions of electron density<\/strong>, not bond order.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 3: Determine Geometries<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>There are <strong>4 regions of electron density<\/strong> around P (2 bonds + 1 lone pair + 1 single bond).<\/li>\n\n\n\n<li>According to VSEPR theory:\n<ul class=\"wp-block-list\">\n<li><strong>4 regions<\/strong> \u2192 <strong>Tetrahedral electronic geometry<\/strong><\/li>\n\n\n\n<li>With <strong>one lone pair<\/strong> \u2192 <strong>Trigonal pyramidal molecular geometry<\/strong><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Conclusion:<\/strong><\/h4>\n\n\n\n<p>The <strong>electronic geometry<\/strong> of the <strong>PO\u2082\u00b3\u207b ion<\/strong> is <strong>tetrahedral<\/strong>, reflecting the 4 electron domains. However, because one domain is a lone pair, the actual <strong>molecular geometry<\/strong> becomes <strong>trigonal pyramidal<\/strong>, giving the ion its 3D shape.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the electronic geometry and molecular geometry of the hypophosphite ion (PO2^3-)? Can you please provide an explanation also. The correct answer and explanation is: Correct Answer: Explanation (300 words): The hypophosphite ion (PO\u2082\u00b3\u207b) consists of a central phosphorus (P) atom bonded to two oxygen atoms, with a formal charge of \u20133 distributed over [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-18810","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/18810","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=18810"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/18810\/revisions"}],"predecessor-version":[{"id":18813,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/18810\/revisions\/18813"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=18810"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=18810"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=18810"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}