{"id":18528,"date":"2025-06-13T07:18:39","date_gmt":"2025-06-13T07:18:39","guid":{"rendered":"https:\/\/gaviki.com\/blog\/?p=18528"},"modified":"2025-06-13T07:18:40","modified_gmt":"2025-06-13T07:18:40","slug":"a-cylinder-contains-40-g-of-he-56-g-of-n2-and-40-g-of-ar","status":"publish","type":"post","link":"https:\/\/gaviki.com\/blog\/a-cylinder-contains-40-g-of-he-56-g-of-n2-and-40-g-of-ar\/","title":{"rendered":"A cylinder contains 40 g of HE, 56 g of N2, and 40 g of Ar"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">A cylinder contains 40 g of HE, 56 g of N2, and 40 g of Ar. How many moles of each gas are in the mixture?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\"><strong>The correct answer and explanation is:<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the number of <strong>moles<\/strong> of each gas in the mixture, we use the formula: Moles=Mass&nbsp;(g)Molar&nbsp;Mass&nbsp;(g\/mol)\\text{Moles} = \\frac{\\text{Mass (g)}}{\\text{Molar Mass (g\/mol)}}<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Identify the molar mass of each gas:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Helium (He)<\/strong>: 4 g\/mol<\/li>\n\n\n\n<li><strong>Nitrogen (N\u2082)<\/strong>: 28 g\/mol<\/li>\n\n\n\n<li><strong>Argon (Ar)<\/strong>: 40 g\/mol<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Calculate the moles of each gas:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>1. Helium (He):<\/strong> 40\u2009g4\u2009g\/mol=10\u2009mol\\frac{40\\,g}{4\\,g\/mol} = 10\\,\\text{mol}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2. Nitrogen (N\u2082):<\/strong> 56\u2009g28\u2009g\/mol=2\u2009mol\\frac{56\\,g}{28\\,g\/mol} = 2\\,\\text{mol}<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3. Argon (Ar):<\/strong> 40\u2009g40\u2009g\/mol=1\u2009mol\\frac{40\\,g}{40\\,g\/mol} = 1\\,\\text{mol}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>He<\/strong>: 10 mol<\/li>\n\n\n\n<li><strong>N\u2082<\/strong>: 2 mol<\/li>\n\n\n\n<li><strong>Ar<\/strong>: 1 mol<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">300-Word Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To find the number of moles in a gas mixture, it\u2019s essential to understand the concept of <strong>molar mass<\/strong>, which is the mass of one mole of a substance. The unit for molar mass is grams per mole (g\/mol), and it varies depending on the type of gas.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In this case, we&#8217;re dealing with three gases: helium (He), nitrogen (N\u2082), and argon (Ar). Their molar masses are based on their atomic or molecular structure:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Helium (He)<\/strong> is a noble gas and exists as a monoatomic gas with a molar mass of 4 g\/mol.<\/li>\n\n\n\n<li><strong>Nitrogen (N\u2082)<\/strong> exists as a diatomic molecule (two nitrogen atoms bonded together), giving it a molar mass of 28 g\/mol (14 \u00d7 2).<\/li>\n\n\n\n<li><strong>Argon (Ar)<\/strong> is also a noble gas, monoatomic, with a molar mass of 40 g\/mol.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">To find the number of moles of each gas, we divide the given mass by the molar mass:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>40 grams of He divided by 4 g\/mol equals 10 moles.<\/li>\n\n\n\n<li>56 grams of N\u2082 divided by 28 g\/mol equals 2 moles.<\/li>\n\n\n\n<li>40 grams of Ar divided by 40 g\/mol equals 1 mole.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Knowing the number of moles helps in many chemical calculations, including finding partial pressures, mole fractions, or total pressure in a gas mixture. These are all important in applications like gas laws (e.g., Dalton\u2019s Law) and stoichiometry.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A cylinder contains 40 g of HE, 56 g of N2, and 40 g of Ar. How many moles of each gas are in the mixture? The correct answer and explanation is: To determine the number of moles of each gas in the mixture, we use the formula: Moles=Mass&nbsp;(g)Molar&nbsp;Mass&nbsp;(g\/mol)\\text{Moles} = \\frac{\\text{Mass (g)}}{\\text{Molar Mass (g\/mol)}} Step [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-18528","post","type-post","status-publish","format-standard","hentry","category-quiz-questions"],"_links":{"self":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/18528","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/comments?post=18528"}],"version-history":[{"count":1,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/18528\/revisions"}],"predecessor-version":[{"id":18529,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/posts\/18528\/revisions\/18529"}],"wp:attachment":[{"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/media?parent=18528"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/categories?post=18528"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/gaviki.com\/blog\/wp-json\/wp\/v2\/tags?post=18528"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}